EASY MATH HACKS You Need to Know!!

[@ShriH-d1o]

After getting XY=9 & Y>X >0;
Suppose X&Y=a√37±a; =>
XY=(a√37+a)(a√37-a); =>
XY=a^2(37) -a^2; Recall XY=9; =>
a^2(37-1)=9; ,=>
a^2=9/36; a=±1/2;
X&Y=(√37±1)(1/2); for Y>X =>X=(√37-1)(1/2)

[@RyanLewis-Johnson-wq6xs]

(x^3+Sqrt[196])/(Sqrt[37])=5 x=0.5Sqrt[37]-0.5=(Sqrt[37]-1)/2 x=-0.25Sqrt[37]+0.25±(0.25Sqrt[111]-0.25Sqrt[3])i

[@Quest3669]

X= (√ 37-1)/2

[@潘博宇-k4l]

X=([-1+(37)^(1/2)]/2, [-1-(37)^(1/2)]/2.)

[@PulkitGupta-g2t]

X is 3

[@moeberry8226]

This use of unnecessary algebra is not worth watching these videos. Just take the cube root of both sides after isolating x. That’s it. Then you can show using Descartes rule of sign that there’s only 1 sign change so at most 1 positive real root.

[@Fjfurufjdfjd]

[(37)^(1/2)-1]/2