Linearization at Critical Points

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  • เผยแพร่เมื่อ 31 ธ.ค. 2024

ความคิดเห็น • 11

  • @NoOne-yw6pr
    @NoOne-yw6pr 6 ปีที่แล้ว +14

    In my experience success is always the result of team work: Professor Strang delivers a brilliant lecture, MIT uploads, we all benefit, the whole system benefits. Go team!

  • @syedsheheryarbokhari2780
    @syedsheheryarbokhari2780 6 ปีที่แล้ว +4

    Thank you Professor Strang and MIT OCW. Professor Strang is amazing and his method of building complicating structures from simplified versions is awesome.

  • @georgesadler7830
    @georgesadler7830 3 ปีที่แล้ว +2

    DR. Strang you are the grandfather of linear systems.

  • @seamus9898
    @seamus9898 5 ปีที่แล้ว

    Denoting the critical point as Y really confuses me... because whenever I see y or Y, I think of functions. But Y here is always a constant.
    Using a different letter helped me.

  • @marverickbin
    @marverickbin 6 ปีที่แล้ว +1

    y is a function, right? You tried to plot f(y), and got a curve. I am confused.

    • @GammaSigma1234
      @GammaSigma1234 4 ปีที่แล้ว

      Yes, y should be interpreted as a function of time. For example, it could be y(t) = 2t - 1

  • @germainguerin3063
    @germainguerin3063 4 ปีที่แล้ว

    i surely miss something, i can't see a zero slope at the point Y in his graphs. Can someone help!

    • @enderyu
      @enderyu 4 ปีที่แล้ว

      I think you mean at 3:00 ? f(y) is defined as dy/dt; so f(Y) = 0 [intersecting the y axis] and the slope of f(Y) is d²y/dt².

    • @rakhimovv
      @rakhimovv 2 ปีที่แล้ว

      Worth mentioning that he draws phase plane (dy/dt y)

  • @lalitsharma4233
    @lalitsharma4233 7 ปีที่แล้ว

    Wow

  • @غديالحربي-س2ث
    @غديالحربي-س2ث 6 ปีที่แล้ว

    G