Propositional Logic Truth Trees (and, or, not)

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  • เผยแพร่เมื่อ 25 ก.ค. 2024
  • In this video on #Logic / #PhilosophicalLogic I introduce truth trees, inconsistent sets of wffs, and rules for disjunction, conjunction, and the negation. We talk about disjunction decomposition, conjunction decomposition, double negation, negated disjunction decomposition, and negated conjunction decomposition. Then, we do an example of a truth tree.
    0:00 [Intro]
    0:17 [What is a truth tree?]
    2:51 [Rule: Conjunction Decomposition]
    4:04 [Rule: Disjunction Decomposition]
    5:02 [Rule: Double Negation]
    5:20 [Rule: Negated Conjunction Decomposition]
    7:39 [Rule: Negated Disjunction Decomposition]
    8:47 [Inconsistency and Example #1]
    10:51 [Example #2]
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ความคิดเห็น • 9

  • @T-The-K
    @T-The-K 2 ปีที่แล้ว +1

    This one took me a bit longer to fully grasp, a lot of rewinding but i figured out everything (hopefully) so looking forward to the excercises!

  • @QuocDatPhung
    @QuocDatPhung 3 ปีที่แล้ว +4

    This is amazing!

  • @flirkvslife2385
    @flirkvslife2385 ปีที่แล้ว +1

    I don’t understand why we’re branching out from ~R, and also, why did we put P Q instead of P R in the branch? On top of that, I also don’t get why Q branches into P AND R!!

  • @salmanizzadin
    @salmanizzadin 3 หลายเดือนก่อน

    📝

  • @stephaniew7501
    @stephaniew7501 2 ปีที่แล้ว

    Where is the solution video?

  • @lucarius4465
    @lucarius4465 2 ปีที่แล้ว

    In our class we call the NCD and the NDD 'The Morgan'. I quite prefer that name over this spaghetti alternative xD

  • @paulcarello6390
    @paulcarello6390 ปีที่แล้ว

    1) (P ∨ Q) ∧ (P ∨ R) ⇔ (P ∨ Q) ∧ ~(~P ∧ ~R) ... De Morgans
    ∴ (P ∨ Q) and ~(~P ∧ ~R) ... ∧ deconstruction
    2) (~P ∧ ~R)
    From 1 and 2
    ~(~P ∧ ~R) is TRUE and (~P ∧ ~R) is TRUE ... this is a contradiction
    ∴ 1 and 2 are NOT consistent.