VALIDITY and ENTAILMENT in Truth Trees for Predicate Logic - Logic

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  • เผยแพร่เมื่อ 25 ก.ค. 2024
  • In this video on Logic, we look at entailment and validity in truth trees for predicate logic. We learn how to do negated universal decomposition, negated existential decomposition, universal elimination, and existential elimination. We then do three practice truth trees.
    0:00 - [Validity and Entailment]
    2:05 - [Tree #1]
    7:42 - [Tree #2]
    12:27 - [Tree #3]
    #PredicateLogic #TruthTrees #LogicTrees
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ความคิดเห็น • 10

  • @philosophyversuslogic
    @philosophyversuslogic 2 ปีที่แล้ว +1

    I wish I had a teacher like you!.. Probably, all your students adore you, doesn't it?

  • @standowner6979
    @standowner6979 2 ปีที่แล้ว +1

    They're back! And making quality content as always.

  • @shanks5393
    @shanks5393 2 ปีที่แล้ว

    Thanks you've helped us a lot

  • @tahaasif2526
    @tahaasif2526 7 หลายเดือนก่อน

    Father of Pradicate Logic without a doubt

  • @el-6757
    @el-6757 2 ปีที่แล้ว

    I'm literally studying THIS EXACT SUBJECT right now!!! 🤯🤯

  • @SyedShah-os7ck
    @SyedShah-os7ck 2 ปีที่แล้ว

    Awesome video, Noticed very good writing software here, can you please let us know how you make the videos, with list of software and hardware as well. thank you

  • @el-6757
    @el-6757 2 ปีที่แล้ว

    Yessss!!

  • @friend4825
    @friend4825 2 ปีที่แล้ว

    What about "Mb" on left and "Jaa" on right in 12:00?

  • @gabrieltapo1744
    @gabrieltapo1744 2 ปีที่แล้ว

    How I never learnt this before

  • @ReadrOFilz
    @ReadrOFilz 2 ปีที่แล้ว

    On the last example, I want to propose an interpretation showing that:
    ∀x∀y(Lxy → Kxy) does not entail ∀x∀y(Lxy → (Kxy ∧ Kyx)).
    Let Lab be true.
    Let Kab be true.
    Let Kba be false.
    This falsifies ∀x∀y(Lxy → (Kxy ∧ Kyx)) .
    But does not falsify ∀x∀y(Lxy → Kxy) .
    (I use less parentheses than in the video.)