Design the one-way continuous slab of the figure subjected to uniformly distributed imposed loads of 5 kN/m2 . The span dimensions shown in the figure are effective spans. The width of beams at the support = 300 mm.
You just write answers and dictate it why don't you explain it Universe mentioned why self weight of slab is multiplied with 0.165 into 25 and you never mentioned why the maximum shear force at SP is multiplied with 0.165 into 25 from where maximum shear force at the support formula came don't dictate we also have answers please explain
how did you get b as 10 power 3
Sir reinforcement detailing depth,cover, effective depth beam oda support la mention pannirukken sir athukku exam la evloo mark reduce pannuvaga sir
Design the one-way continuous slab of the figure subjected to uniformly distributed
imposed loads of 5 kN/m2
. The span dimensions shown in the figure are effective spans.
The width of beams at the support = 300 mm.
Sir, why didn't you do the ultimate load calculation?
how did you get the finish load
Span/depth=25
d'=clearance+dia/2
Continuous beam span=26
You just write answers and dictate it why don't you explain it Universe mentioned why self weight of slab is multiplied with 0.165 into 25 and you never mentioned why the maximum shear force at SP is multiplied with 0.165 into 25 from where maximum shear force at the support formula came don't dictate we also have answers please explain
Can you mention page number in comment and pin code 456:2000
IS 456:2000pg.no: 81,82,93,73
Not 26
"promo sm"
not at all clear explanation