Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible
he is 'sneakily' using LHopital's rule here, which is only for 0/0 and inf/inf form. depending on functions, there may be some limits that get 0/0 or inf/inf by approaching a constant too
If the highest order of the denominator is same with numerator, you only need to divide the coefficient of the highest order (coef. numerator/coef. denominaror)
When the difference between dominant exponents is odd, and X approaches negative infinity. If said difference is positive, the limit is always positive infinity, regardless of which infinity X approaches.
Just took x ( or x 's higher power) common from both numerator and denominator. After that common x 's will be cancelled, after that put the limit directly. Simple 💁🏻♂️
From what I remember, this rule only applies if you’re dealing with fractions. I’m having to review this for series and sequences in Calc 2, but I promise it’s not that bad despite what others will say!
It is soooo obvious... They grilled us with the squeeze theorem, so I stopped paying attention at all, even when fancy limits started and got my worst grade at maths ever. 😊
😳...Okay. I will be starting this course soon and doing research. I just saw you solve equations with only the first part of the problem as if the rest of the equation doesn't exist. 🤦🏿♀️ Please help me understand.
It won’t be because x is approaching infinity, x will be a large value, but say x was approaching 3 with this same function. Then the limit would not exist because as it approaches from the left y goes to negative infinity, and from the right it goes to positive infinity.
Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible however with 0 this is not true
F(X)>g(X)=infinite
F(X)
Yeah 😊
Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible
I dont get this concepts
@@bibibinafnaf1638 i think it only works when the limit approaches infinity
You can also think of it as omitting the non-leading terms.
That ending nearly gave me a heart attack
LMFAO
jumpscare
Jumpscare outro 😂
I'm sorry for that 😁
@@SerBee_29 but it's so cool 😭💗 you're so cool
Bro this is wild. I wish my professor didn’t make us show work
I have NEVER had someone explain this to me so simply. You, sir, are a legend and a hero.
Thanks ☺️❤️
I remember limit being much much much more difficult than this, thank you for this.
Thanks❤️
Most limits are not this easy 😂 Those are limits where x approaches infinity, they are the easiest
You are exceptional, thanks a million 🙏
Welcome ☺️
Simplified this for me thanks!
Thanks 😊
Brother love and respect from India ❤
😊❤️
thanks! clear and concise!
Thanks ☺️❤️
teaching more than my calculus teacher
U just helped me pass exams thanks
Wow. Nice ❤️
Thank you very very much 👏👏
I learn something very important today
Wow. Grateful for this😊
MENTALLY DEFINITELY 🎉🎉
But this is only possible when the limit x tends to infinity.
otherwise it would be easier, but in that case it will almost always be a zero division. At least in school
Yes
he is 'sneakily' using LHopital's rule here, which is only for 0/0 and inf/inf form. depending on functions, there may be some limits that get 0/0 or inf/inf by approaching a constant too
U can do the same to -inf, doing a substitution. Or even with 0, if u wanna use negative coeficients
Hi , your a good #teacher, I #wish #I’d had you in my #classroom
Thanks ☺️❤️
Thanks a lot . It is best trick I think 🤔 ❤❤❤❤
You're welcome.
genius 👍
much easier way to get the answer gl bro
Thanks for giving shortcut i was trying to solve methodologically
You're welcome ☺️
Thanks ❤
❤️😊
Good.🙏❤
Thanks ❤️
This is really cool
Thanks ☺️
I just hope there is no step marking in exams for this
yourrrrr decrrreeee is nice
Thanks 😊
If the highest order of the denominator is same with numerator, you only need to divide the coefficient of the highest order (coef. numerator/coef. denominaror)
Yeah
Infinity, 0 and 4
the is very similar to horizontal asymptotes
Genius
amazing video
Thanks 😊
The slim Jim method!
Wow
Nice man thanks
You're welcome. Thanks.
عالی
sure
Wow!
Thanks 😊
Thanks because you are very shorted and explained us the way very easy
Thanks for the compliment 😊
@@SerBee_29 sir you Know My teacher also teaches me this today . I am a class 12 th student from India . In which class you are studying this ?
@@alwaywithtech7560thanks. I am from the Philippines. I am teaching Calculus in the tertiary level.
Good explanation ,
Also, when does it equal negative infinity?
When the difference between dominant exponents is odd, and X approaches negative infinity. If said difference is positive, the limit is always positive infinity, regardless of which infinity X approaches.
Sir plz upload more video of the shot trick
Wow I just learned it for about 15s.
Thanks 😊
❤ thanks dear
Welcome ❤️
But when we have the same coefficients up and down...we just divide their coefficients ❤
Just took x ( or x 's higher power) common from both numerator and denominator.
After that common x 's will be cancelled, after that put the limit directly.
Simple 💁🏻♂️
Yeah
Sir more videos pa po 🫡
The slim Jim method
Do these tricks work for all questions have limit x->∞ ?
From what I remember, this rule only applies if you’re dealing with fractions. I’m having to review this for series and sequences in Calc 2, but I promise it’s not that bad despite what others will say!
You are a GOD
💙
Solved all three que in 5 seconds
Limit of a function makes me like the topic"calculus" but you almost put me in difficulty here😔😔
It is soooo obvious... They grilled us with the squeeze theorem, so I stopped paying attention at all, even when fancy limits started and got my worst grade at maths ever. 😊
❤🙂
Please can we solve like this only when lim x is at infinity
Hahahahha gagiks nagulat si me
Haha 😅
Thank uu, i really got this but before i was a little bit confused
damn bro,wtf, how did all my teachers not tell me something so simple 😭💔
thanks man 🙏
You're very welcome 😊
As an Indian I confirm we can solve such ques while sleeping
Wow, nice. We Filipinos can't do that.
How about kung may sign?
do the same rules apply when x approaches -infinity?
Yeah
💀❤️
Salamat💞
Thanks ☺️❤️
Is this possible only when x tends to infinity?
wtf I was literally about to look for a video on this and this popped up my in my feed
How about with square root?
when does ot give negative infinity
When there is negative sign
limits are so easy
😳...Okay. I will be starting this course soon and doing research. I just saw you solve equations with only the first part of the problem as if the rest of the equation doesn't exist. 🤦🏿♀️ Please help me understand.
I wish u posted this a year ago
Thats for horizontal asymptotes tho
this looks alot like asymptotes :000
infinity
2
This is good for multiple choice FE exams tho
Yeah, very effective ❤️
does it only work if x approaches to infinity or does that mean any number?
If x approaches to infinity only
What happens when u use l hospitals rule ?
this is just LHopitals here. when we keep applying LH rule, the highest power will remain, hence putting the limit as per LH rule.
Show us the graphs
Bes on continues
Where did you get the 4?
Coefficient of the leading term
When is it - infinite then?
So if the numerators power is more than the denominator it's infinite. ....but if the denominator's power is greater....then its =0
Yeah
how bout when its negative infinity
4÷ 2 is 8
Sir in number 1, wat if x is equal to -3?
It won’t be because x is approaching infinity, x will be a large value, but say x was approaching 3 with this same function. Then the limit would not exist because as it approaches from the left y goes to negative infinity, and from the right it goes to positive infinity.
is this for real? what my teacher taught me has many solutions
Yeah of course
○○/○○=undefined ?
is this only when x ~> ♾️ ?
Yeah
L’ hopital
It's not wrong we 4 - 2 : is 2
Is this legal
mental L'Hopital's rule
Why?! Isn't it workable??
do the same rule when x approaches to -0?
nope
rationalise it
No, try to calculate it. If you end up with the indeterminate forms 0/0 or inf/inf, use l'Hopital's rule, if you've learned it.
Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible however with 0 this is not true
Always the Asian one ☠️
Hihi. Thanks 😁❤️
L hospital rule bhi koi cheez hai 😂😂
What if it's x---0 sir
If x tends towards 0, try to calculate it, if it fails and you get the indeterminate forms 0/0 or inf/inf, you may want to apply l'Hopital's rule.
Bhaiya Aap angrej hai kya
Can you explain us
Why the limit of first problem is infinity ♾️ ?
यह तुम्हारे देश मे भी हे क्या?😂
A limit of a fraction can’t be equals to zero
Yes it can wdym
lim as x→∞ of 1/x=0
Thanks for the example my man
Arre you indian
Filipino
Wow