OMG looking back on this paper its CRAZY how good of a prediction this was i reckon this paper got me an extra 5 marks MINIMUM if anyone is in year 1 looking at this make sure to complete as much of his tricky questions series and his predicted papers most underrated maths teacher
this was massive, just finished it night before the exam at 10pm. Got some stuff to cover in the morning, but feeling a lot more confident in stuff that I struggled with before this paper. Thank you Mr Astbury!
you're the absolute GOAT for this paper, helped me gain a lot of confidence and im doing a few more as a warm up to the exam this afternoon. good luck everyone!!
thank you so much! please may you make a predicted paper 2 using just madasmaths questions like you did last year 🙏🙏? i would find that extremely useful
Hey. I've just completed this paper and I wanna do practise for the topics I didn't do well on but I can't for the life of me find this playlist with all the topics you talk about at the start of the video. Also you're a life saver these papers are carrying me through a-levels rn
Sorry, I didn’t explain that very well. I meant my past papers playlist. Each paper has the topics in the description for each question so you can look at the description and select the topic you want to do
Thankyou for this paper and video!! Turned off my adblocker for this, you deserve all the revenue you can get from it! Got 120/150 80% which I'm very happy with. Know exactly which ones to work on too which is invaluable!
Thank you for this ! For that parametric question to prove that theyre in a straight line - i would have never thought to make a linear equation. i just found the derivative of both x and y and said they were multiples of eachother....
For those who don’t why it can swap the limits over by multiplying a negative in a definite integrals, think at it like this. It will get [b] -[a] as an answer of a definite integrals where (b) substitutes the upper limits to the variables and (a) substitutes the lower one. So if you multiply it by negative. You will get [a] - [b]. So as it is now using the lower limits minus the upper limits, it is equivalent to swapping the limits while the integration parts.
34:20 instead of calculating gradient and y-intercept, i did log(base 10)3 and got 0.477 then checked the graph and did 10^2.9 to get N. will this allowed bcz i got sth similar ~794 ????
Yeah I did it just from the LHS, if u turn the cot^2 and tan^2 into sin's and cos's and then make them have a common denominator it goes quite smoothly
Yeah word like i had no clue how to start from the RHS but i saw your comment and re did the question from the LHS converting cot and tan into sins and cos and it cancels really nicely to give cos2x/1/4 Sin^2x = the ans
yes just convert into sin and cos and then ull notice when u add the 2 fractions the numerator will have a difference of 2 squares, just factorise and with some relatively simple algebraic manipulation ull get the answer
on question 4b wouldn't it be easier to just use the graph drawing a line up from 3 days which is log3, then find where that meets the line and equals about 2.9 in terms of logN, so then rearrange to make 10^2.9 which comes out to 794
Hi, thanks so much for making this paper! For q17a) is it possible to do parametric differentiation to get a gradient of -4 and therefore having a constant gradient proves that any point (x,y) will lie on a straight line?
Thanks for another paper! Just wondering for question 4b could you just find the value for log3 on the graph and then draw a line to the corresponding logN value and do 10^ whatever value you get?
for question 17 - can i prove its a straight line by showing dy/dx = k? i remember doing that somewhere but don't know if it was for parametrics or not
thank you so much for this! quick q, is there a mark scheme for this paper ???? just wanted to check what the alternative methods were for a few of the qs. thank you again!!!!
for part c on the last question, couldn't you just sub in the t=0 and t=pi/2 into the y=4sint as the range of y(t) will be the same as the range of f(x). I got the same answer of 0
For question 5 can’t you make 2 in the form log base 3, 9 since their equivalent then multiply 9 and 4x then raise both sides to the power of 3 and still get the same answer?
sir for Q)17, since it says for all points x and y can you sub in any values of T into both x and y, find the gradient between any two pairs of coordinates and then make a equation from there as I still ended up with y=-4x+2
I might be being stupid but how did you get -2/3 for the gradient on 18a) when i sub in pi/4 into the same equation i get -0.6597, so very similar but not -2/3
Alternative method for 1C leading also to k = 11/4... Consider the triangle from the centre of the circle to B to A. If angle CAB is theta, tan theta is 1/2. Consider the triangle from A horizontally to the right, then up to C, with the angle at A being alpha. cos alpha is 3/ root 5 x r. tan (arccos 3/root 5 x r + arctan 1/2) = gradient 2. From here, r = 3 root 5 over 4. Using the result from part B, k is 11/4 or -19/4, but as from the diagram k is greater than 0, k = 11/4.
1:42:39 lets say for example, the bounds had remained the same for part b) ii). would the estimated area just be 10.52 + 2? so 12.52? im not sure if this makes sense
No it wont be 12.52 but don't worry as they'll never ask a question where the bounds remain the same but the graph is horizontally translated (in a trapezium rule question) because it is literally impossible as you don't have enough information to do it as you dont have the actual equation of the curve - it's just called f(x)
for question 2a, my immediate thought was to use dot product and modulus to find the angle, i know it is not in the spec but do you think i could get any marks if i use that method instead? thanks so much!!
@29:30 instead of using quotient rule i tried splitting up the fraction and it became 350/9 e^kt + 350 and i got T as 2.7 days ( which is wrong). so can i use this method and get the right answer???
Most accurate predicted paper I’ve ever seen at A-Level
babe wake up, new astbury paper just dropped
😂
Without doubt my favourite comment of all time 😂👏❤️
OMG looking back on this paper its CRAZY how good of a prediction this was i reckon this paper got me an extra 5 marks MINIMUM if anyone is in year 1 looking at this make sure to complete as much of his tricky questions series and his predicted papers most underrated maths teacher
so sad that i only found out about you this week. you’re an incredible teacher. thank you
Just finished Paper 2. WOW!! Mr Astbury you're amazing. This mock was EXACTLY like the exam. thank you so much 🤙🤙
this was massive, just finished it night before the exam at 10pm. Got some stuff to cover in the morning, but feeling a lot more confident in stuff that I struggled with before this paper. Thank you Mr Astbury!
You got this! 💪
I watched this in the morning before paper 2 and wow it really helped. Thanks for the amazing walkthrough!
you're the absolute GOAT for this paper, helped me gain a lot of confidence and im doing a few more as a warm up to the exam this afternoon. good luck everyone!!
Good luck!
Thank you so much for these predicted papers! Just finished Paper 2 this afternoon and your videos helped so much 🙏🏾🙏🏾🙏🏾
Thank you so much!! Good luck everyone
THIS PAPAER WAS SOOO ACCURATE
U absolute legend u predicted so many stuff and it came up
THIS WAS SO ACCURATE 🙏🏾🙏🏾
michelle boooooooooooooo!
we got 2024 astbury paper 2 2024 before gta VI 🔥🔥
This joke is getting out of hand now
To think not long from now we’ll all be off at uni and be playing said gta VI is mind boggling to ke
@@mycota-5336 at uni is crazy im gonna be at waitrose
12:32AM but I must finish the kings video
thank you so much! please may you make a predicted paper 2 using just madasmaths questions like you did last year 🙏🙏? i would find that extremely useful
^^
that first circles question killed me
your cooked
@@RobinHrper nah bro that was by far the hardest question, the rest were fine
why are there ads every minute ;; painful af
but very useful tysm!!
J Cole of maths on top
hes so humble
@@albie898 Mr.Astbury McDonalds meal with a side of water
im soo cooked.
same but f it imma just get a job at a warehouse at this point, uni aint for me
adam johnson my idol you were better in a sunderland shirt
Nah ur good bro you’ll do well
Ppl like you are the same ones who would get 70/100 tho? Just shut up
Giving up already is crazy
This was really accurate thank you !
Hey. I've just completed this paper and I wanna do practise for the topics I didn't do well on but I can't for the life of me find this playlist with all the topics you talk about at the start of the video. Also you're a life saver these papers are carrying me through a-levels rn
Sorry, I didn’t explain that very well. I meant my past papers playlist. Each paper has the topics in the description for each question so you can look at the description and select the topic you want to do
Thankyou for this paper and video!! Turned off my adblocker for this, you deserve all the revenue you can get from it! Got 120/150 80% which I'm very happy with. Know exactly which ones to work on too which is invaluable!
Legend! 80% that’s great! 🙌
hey where did you find the playlist he talks about at the start with the practise questions sorted by topic?
Thank you for this ! For that parametric question to prove that theyre in a straight line - i would have never thought to make a linear equation. i just found the derivative of both x and y and said they were multiples of eachother....
But is that method you mentioned also valid????
you saved my grade, goat.
thanks
The first question threw me off quite a little lol - surely that would be near the end of a paper 🤣
Yeah! I forgot to mention that I didn’t order the questions by difficulty like in a real paper. Just by topic
thats a common Q1 big guy
@@RobinHrperBro just likes lying 😂😂😂😂 bros gonna be stressed now
@@dam3717 I mean it is only 3 marks and involves just subbing y into the circle, so it might be. Probably more than 3 marks though
@@dam3717bro stressing everyone out😭😭😭 love the soad pfp tho that album is fire
Thank you so much this prediction was perfect
just sat the paper very helpful do u have paper 3 predicted🙏
Thank you this made me more confident with my exam, still pooing myself though
Iteration already came up in paper 1 - Newton Raphson method. Great paper though, really helpful and great walkthru video. Thanks
newton raphson is a different topic to iteration. yeah they are both in numerical methods but are still different
W predicted bro it was hella accurate.
honestly this a goated paper thank you mr astbury💪🏾💪🏾
Happy to help!
Thank you so much Sir! These were great questions, challenging and helped me learn so much!!
I have never seen the DI method before (1:35:00) is it your own personal thing?
Thank you so much!!! This was extremely helpful!
thanks goatsbury class paper as usual
saved my grades, bloody legend
Thanks Mr Astbury that was amazing session!!
For those who don’t why it can swap the limits over by multiplying a negative in a definite integrals, think at it like this. It will get [b] -[a] as an answer of a definite integrals where (b) substitutes the upper limits to the variables and (a) substitutes the lower one. So if you multiply it by negative. You will get [a] - [b]. So as it is now using the lower limits minus the upper limits, it is equivalent to swapping the limits while the integration parts.
34:20 instead of calculating gradient and y-intercept, i did log(base 10)3 and got 0.477 then checked the graph and did 10^2.9 to get N. will this allowed bcz i got sth similar ~794 ????
i did this too
i did this too
i did this too
Is there no other better way to solve question 9 by working on the left hand side without the tan formulae? I'd rather use anything but that. 50:44
Yeah I did it just from the LHS, if u turn the cot^2 and tan^2 into sin's and cos's and then make them have a common denominator it goes quite smoothly
Yeah word like i had no clue how to start from the RHS but i saw your comment and re did the question from the LHS converting cot and tan into sins and cos and it cancels really nicely to give cos2x/1/4 Sin^2x = the ans
yes just convert into sin and cos and then ull notice when u add the 2 fractions the numerator will have a difference of 2 squares, just factorise and with some relatively simple algebraic manipulation ull get the answer
I mean thanks for the paper but bloody hell I think I have watched 50 adverts by now.
thank you sm for helping. lifesaverrrrrr
Take a shot every time you watch a midroll ad
Fr tho😭😭
idc hes tha goat imma give him his ad revenue
we love you sir
i fw u heavy vro ❤️
on question 4b wouldn't it be easier to just use the graph drawing a line up from 3 days which is log3, then find where that meets the line and equals about 2.9 in terms of logN, so then rearrange to make 10^2.9 which comes out to 794
why are there ads every second bare frustrating
yeah fam its a madness
Hi sir, will you be offering any discounted rate for your paper 2 revision sessions recordings tomorrow? Thanks.
question 9 is AWFUL
good luck all
Hi, thanks so much for making this paper! For q17a) is it possible to do parametric differentiation to get a gradient of -4 and therefore having a constant gradient proves that any point (x,y) will lie on a straight line?
my teachers never said anything about swapping the intervals of an integral when you multiply the inner function by negative one. what
Yeah I had no idea either my skl doesn’t even teach 😢
well if you need help understanding, just remember that between a and b R = f(b)-f(a) so logically -R = f(a)-f(b) so you can swap around the intervals
my teachers never said anything about dumbos like you lowering the boundaries for the rest of us (phew)
For question 17- I rearranged x for t and subbed into y but got y= -12x - 6. Is it wrong to do the opposite substitution?
THANK YEWWWWW SO MUCH LITERALLY A BLESSING
no worries if not, but is there a mark scheme to the paper so I can see how the marks were spread out
How can I ever repay youuu thank you
on the last question part c. why isn't it + or - 4 making the range -4 -> 4
Thanks for another paper! Just wondering for question 4b could you just find the value for log3 on the graph and then draw a line to the corresponding logN value and do 10^ whatever value you get?
hi sir, for that last parametric integration question, is that the hardest the topic gets?
Q6a)
The graph transformation I think is wrong,
There is no change in minimum value
love this guy man
for question 17 - can i prove its a straight line by showing dy/dx = k? i remember doing that somewhere but don't know if it was for parametrics or not
Yes, that would work just fine
thank you so much for this! quick q, is there a mark scheme for this paper ???? just wanted to check what the alternative methods were for a few of the qs. thank you again!!!!
yes^^ please
for part c on the last question, couldn't you just sub in the t=0 and t=pi/2 into the y=4sint as the range of y(t) will be the same as the range of f(x). I got the same answer of 0
for Q5 36:00 why can't we do 3^LHS = 3^RHS which cancels out the logbase3 giving us 5x+7=4x+ 3^2 and x=2
Hi sir, how many marks do your reckon is required to get an A?
for question 18 part a, aren't you meant to findd the negative reciprocal of the gradient?
no only for the normal this is tangent
tangent is the same gradient
Way too many ads here :/
Q2 HELP
Why did you leave it as root 49 rather than changing it to 7?
No reason in particular! They are equivalent
Q6 you dont have to workout P?
Top G, thanks man
For question 5 can’t you make 2 in the form log base 3, 9 since their equivalent then multiply 9 and 4x then raise both sides to the power of 3 and still get the same answer?
yeah thats fine to do
sir for Q)17, since it says for all points x and y can you sub in any values of T into both x and y, find the gradient between any two pairs of coordinates and then make a equation from there as I still ended up with y=-4x+2
thanks so much for the vid, helped loads
For Q15 (c) can it be simplified any further?
I might be being stupid but how did you get -2/3 for the gradient on 18a) when i sub in pi/4 into the same equation i get -0.6597, so very similar but not -2/3
late but it might be a calculator error because i also got -2/3, are you sure that you put sec as 1/cos?
do i still get marks for using dot product on question 2?
For question 4b why cant you just read off the graph from log3days to get logN?
Will there be an OCR predicted paper like this?
Sir i can’t find your second predicted paper that you were supposed to do today
for last q when u sub in f(-2) dont u get the y values to be +-4 therefore range is -4
yes could someone explain, I thought this too
when you sub in f(2) you get f(x) to be 0 as you just sub in the limits given for the domain into the equation you proved in part b
34:22 is subbing in T=3 to logT and then using the x and y values to find it wrong? do you have to use the equation
Alternative method for 1C leading also to k = 11/4...
Consider the triangle from the centre of the circle to B to A. If angle CAB is theta, tan theta is 1/2. Consider the triangle from A horizontally to the right, then up to C, with the angle at A being alpha. cos alpha is 3/ root 5 x r. tan (arccos 3/root 5 x r + arctan 1/2) = gradient 2. From here, r = 3 root 5 over 4. Using the result from part B, k is 11/4 or -19/4, but as from the diagram k is greater than 0, k = 11/4.
why is the gradient the same 1:50:37 , shouldn't it be the negative reciprocal since it is a tangent?
gradient is same for tangent, its negative reciprocal for the normal.
1:42:39 lets say for example, the bounds had remained the same for part b) ii). would the estimated area just be 10.52 + 2? so 12.52? im not sure if this makes sense
No it wont be 12.52 but don't worry as they'll never ask a question where the bounds remain the same but the graph is horizontally translated (in a trapezium rule question) because it is literally impossible as you don't have enough information to do it as you dont have the actual equation of the curve - it's just called f(x)
@@Wasif-xd5mx ohhh okay thank you!!!!!
how is C equal to a third in the partial fractions question wouldnt it be 0?
Where can I get the mark scheme for your madasmaths predicted paper?
My goat
At 2:01:25 when doing reverse chain rule to find R, why do we only integrate sin³t and not cost
Reverse Chain Rule Prob
For question 11 part c, would k=0 also work because it will intersect only the two minimum points?
it asks for a range so it's looking for the 16e^7/2
for question 2a, my immediate thought was to use dot product and modulus to find the angle, i know it is not in the spec but do you think i could get any marks if i use that method instead? thanks so much!!
any valid method will get marks if you get it right. no matter its in the spec or not. :3
Further content can still get you marks as long as you get the right answer, don't worry
Why don’t you include modulus
Why am I not getting the same answer when I dot product the vector angle for q2?
Nvm I realised the vectors have to be facing away from each other or I just 180- my answer
Mr Astbury >>>>>
thank u so much
21:49 1/15ln12
the goat 🙏🙏🙏
@29:30 instead of using quotient rule i tried splitting up the fraction and it became 350/9 e^kt + 350 and i got T as 2.7 days ( which is wrong). so can i use this method and get the right answer???
You cannot split a fraction like that. (a+b)/c = a/c + b/c but a/(b+c) there is nothing you can do with, it cannot be "split".
@@josephheldenhammer ohhh thanks i'll remember not to do that in paper 2
Sir please please do the maddas question predicted paper 2 please
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