Part 2: UV Visible Spectroscopy: Absorption Laws (Lambert's Law and Beer's Law)

[@kasimhussain9935]

your simplicity won my heart sir

[@Gajanan585]

What a explanation sir maja aagaya Ekdam concept clear hogya

[@aanchalsharma5264]

Why I didn't found ur videos before
Really ur explaination is just awesome

[@pkclasses100]

You might have not searched in TH-cam. BTW please go through the playlist of our channel, you will get videos on other topics too.

[@dushyanthraj1112]

Thank u very much sir
I love your way of explaining the concept

[@rukhsanabashir1852]

My fvrt most sir Allah khush rkhy

[@kinjalpatel4387]

Sir u r blessing for us🙏😅

[@tasnuparifa8735]

Thank you sir!This was very helpful...

[@SaniaJarora-yy1hk]

Thankyou so much sir . Really really helpful 🙏🙏🙏

[@AyushSingh-pn2kb]

Awesome sir best understand by you sir❤️

[@Lizzeeyyy]

Thanks for the simple explanation. really really helpful

[@rajeshsandu4921]

Well explained sir ur hard work is well recognised all pharma students 🙏🙏🙏🙏❤️❤️

[@rudanimukesh]

Voice May Bracking Sometime, But Well Explained And U R A Master

[@sambitdas5065]

It's really easy sir 🙏🙏🙏🙏☺️☺️

[@rahulmaheshwari6189]

Sir thank u so much
I'm big fan of you after this video
I am very happy

[@pkclasses100]

Rahul Maheshwari
Thank You for the appreciation.
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[@rajairshad7813]

Concepts making easy to understand ty

[@vivekananda6902]

Thank you sir really explanation is good , sprb sir .....

[@Cg_vbstyle14]

I hope you always bright the future of all students👦📖🎒

[@inklisanpatel8847]

Thanks sir for this lecture..well explained easy to understand

[@pkclasses100]

Inklisan Patel
Thank You for the appreciation.
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[@harshapriya8209]

Thank you Sir 😇😇 very well understood

[@anitasoni8494]

very nice explanation sir

[@pkclasses100]

Thank you!!!!!!!
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[@snehalborde3867]

Thank you so much sir it's very easy and helpful

[@toxicshivamgamer9930]

Nice and easy explantion

[@pritykarmakar4937]

Thank you so much sir 🙏

[@santoshkumaryadav3616]

Thank you so much sir for making this video 🙏

[@Nazreen_k]

Aapka face dekh k lagta hai k aap bht pareshan rhte hain...baki aap pdhate bht accha hain... Thank u

[@pkclasses100]

😂😂 Aisa nahi hai bilkul.... Camera ke samne serious ho jata hai face.
Kabhi live milenge to doubt clear ho jayega 😍

[@Nazreen_k]

@@pkclasses100 ..hehehe okay! kal mera exam hai sir... Beer-lambert's law smjh nhi aa rha tha to aapki videos dekh rhi hu...

[@namratakvaghasiya6104]

Txs sir super explain

[@Vlogs...Travel12345]

Sir ,Why extinction term is used instead of absorptivity ?

[@Omkar-pr8ck]

Why spectra is like bench curve ?

[@balarajut9091]

Nice explanation sir....plz upload principle of refractive index detectors

[@pkclasses100]

balaraju t
Will upload later. Thank You.

[@farahmanzoor6962]

why transmitance decrease exponentially in beer's law??

[@kavyap1622]

U r video really help me a lot to get a good marks😍 m very big fan of u sir, d way u r teaching is awesome 👌👌

[@pkclasses100]

That's great, glad to know.
May I know your institute name?

[@kavyap1622]

KLE Nijalingappa society

[@-euniceMititi]

You are the best

[@Showkat_Dar]

I got confused by the log thing.I mean what is the need to put a log there.

[@tonystark-do6pb]

Ty somuch sir u explain very well

[@ananyasharma7203]

I cannot understand the fact why absorbtion = incident radiation/trasmitted radiation.shouldn't it be absobrtion = incident - transmitted because at the end the amount of incident =absorbed light+emitted light. Can you plz clarify it.

[@PawanKumar-kt4vh]

Ye baat to mujhe bhi samajh nahi aayi 😂

[@wemad4volleyball317]

Wow what an explanation sir. Thank u so much

[@meljindanish227]

Sir ur explanation is super.. Sir if percentage transmittance is 0 then absorbance is? How to do this calculation

[@proteinengineering007]

Abs. = - (log T)

[@sethfrekinrollins7293]

Sir I need the video on structural elucidation of simple organic compounds using UV and it's techniques...please help Sir...

[@anjalic6671]

Tqsm sir..huge respect

[@osmanibrahim9390]

wow what is an amazing explanation sir, thank you a lot for your great effort. once thank you

[@pkclasses100]

Thank You for the appreciation.
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[@chemistryintelugu3496]

Yes sir but some crd and od curves and octent rule and Halo ketones upload video or pdf

[@pkclasses100]

I will do that part in future.

[@expergefactor4352]

I think sir u have made a little mistake in statement of Lambert-Beer's law." Then the decrease in the intensity of INCIDENT RADIATION is directly proportional to the concentration as well as thickness of solution

[@shivohamsharma7863]

great video.now i m understand this concept......thanks sir

[@pkclasses100]

Welcome!!!!!!!
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[@vaishalisharma6859]

This video help me a lot in solving questions regarding these laws.
Thank you sir

[@pkclasses100]

Welcome!!! Watch videos for other topics too.

[@sphiwehlophe6840]

How do you convert E=1500/M/cm to L/mol/cm??

[@indupathania839]

What will be the sample solid, Or liquid

[@pkclasses100]

Always liquid

[@reetadevi7243]

Sir..plz upload video on hplc.....and also on instruments...like uv.kf.ir..hplc...with diff. Models

[@pkclasses100]

Already uploaded, please go through the playlist.

[@reetadevi7243]

Sir your video r very usefull for every body....can u plz....send or reupload these video...on my mail [e-mail]

[@mahbubachowdhury4260]

Tnx a lot sir..live long

[@mahesherra4986]

Super 🙏🙏🙏👍👍👍

[@prabhchemistrytips803]

Really helpful 😊

[@pkclasses100]

Thank you dear, keep uploading good contents.. my best wishes.

[@abhilashgowda3259]

sir u must use SI units while solving the problems

[@pkclasses100]

✔️👍

[@humayraadiba9530]

Yes ...i also think so

[@THEONLY9274]

Will i be able to use this in 2nd year

[@THEONLY9274]

Please reply 🙏🙏

[@himanshusingh4850]

Sir what is factor in spectrometer

[@rajput9s764]

Thanks sir😊😊😊

[@aanchalsharma5264]

I am ur new subscriber 😊
Thanks for wonderful explaination

[@pkclasses100]

Welcome to our channel!!!!!!!
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[@sandeeppant2060]

Sir can this uv spectroscopy series is used for bsc 3rd sem orgainc chemistry chapter (electromagnetic spectrum absorption spectroscopy )

[@pkclasses100]

Yes... It can be used. 👍

[@sandeeppant2060]

Dr. Puspendra Classes sir thanks these lectures are very useful for clearing the exam 🙏

[@suhaib1412]

Sir How is equation of Absorbance derived i.e, A=Log(I°/I)

[@writerbythought2603]

Sir ! Some points are disturbing with respect to Dr. Jagdamba singh's book of organic chemistry vol. ||

[@pkclasses100]

You can mail me the details, so we can resolve the problems/ deviations (Mail ID: [e-mail])

[@DipakPatil888]

You can mail me the details, so possible to comment (Mail ID: [e-mail]). Otherwise, put the questions/doubt here only.

[@jayadevajmera5168]

Nicecsir

[@shaguftaparveen3619]

Thank you soo much sir

[@arpanmaity4883]

Sir what is the meaning of monochromatic radiation???

[@pkclasses100]

Having single wavelength

[@arpanmaity4883]

Thank u sir..

[@Ironman1234-D]

A=log(lo/l)not lo/I

[@zahiddar3547]

thanks
sir why you write A=log10

[@pkclasses100]

That is logarithm of 10 base.

[@amitkumardangi5856]

Sir thanks soooooo much

[@pkclasses100]

Amit Kumar dangi welcome

[@pharmaaone1347]

tq so much sir.

[@pkclasses100]

Welcome dear

[@sidharthsharma6067]

Thank you sir

[@virendraindian5775]

Thank you sir... Jai Hind

[@pkclasses100]

Jai Hind 🇮🇳

[@ghanshyamchanpura2956]

good, thax

[@gstkasolution2313]

if A=(Io/I) THEN HOW A=LOG (Io/I)

[@chemistryintelugu3496]

Sir upload more videos in uv spectra

[@pkclasses100]

Total 8 videos are available in the playlist of UV-Visible Spectroscopy. Have you seen all?

[@bageshwardham.464]

So you can try to explain in easy way and simple way

[@VivekKumar-vi6xd]

Sir please try to make vedios in Hindi language so that it will be esay for us to understand

[@milindmakade3768]

Sir thank you

[@neelembatoolneelem839]

Welldone sir

[@sahilpatel6699]

A is equal to I zero devided by I
T is equal to I divided by I zero
So A = 1/T aaisa Nahi ho jata ?
To A = log (1/T) kaise le sakte haie hum.
Ye thoda samaj me Nahi Aaya sir...
A = log(1/T) ye kaise Likha sir ?

[@sahilpatel6699]

Ek taraf log kaise le sakte haie hum , agar log Lena hi haie to dono side Lena padta haie na sir , ye concept me confusion aa rahi haie

[@sahilpatel6699]

A = I ° /I
Aur
A = log (I°/I)
Ye kaise ho Sakta haie ?

[@momonishsiddiqui3488]

Nice

[@_r.i.y.a.s.a.h.u_]

Thank You so much sir .........

[@danishs2494]

Shadi m nhi Jana hai 😂

[@nagalakshmiveerla7057]

Thanku you sir

[@pkclasses100]

Welcome!!!!!!!
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[@sushilkumar-ss3lh]

Iski pdf file h kya sir

[@dushyanthraj1112]

👌👌👌👌👌

[@soulminivlog]

these frequent ads are very irritating

[@sahilmalik7294]

Kisi k pass notes milee ge kya m.phacy k

[@arshadiqbal3840]

Wldon sir g❤❤❤❤❤

[@abhijeet2153]

hey everyone, the correct thing is, the incidence light = I. and transmitted light is I , he is wrong in the video plzz rectify

[@aryansinghji676]

How it is possible?
You are telling Incident light = I as well as transmitted light = I
You are totally wrong.

[@abhijeet2153]

@@aryansinghji676 i said I. SEE THEEK SE

[@aryansinghji676]

@@abhijeet2153
Incident light is always denoted by I● (I zero) because nothing absorbed from that light And transmitted light is denoted by I.
Sir is absolutely correct.
Please check the book.

[@sarbjotsandhu8509]

siraaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
waheguru mehar kree

[@pkclasses100]

Thank you

[@strikergaming007]

I know advertisment makes your money but try not to put them in important points.. its really distracting and not at all helpful

[@pkclasses100]

Thank you for understanding the concept of advertisement.
Very soon I will enable the join button and members will get exclusive video and those videos will be advertisement free.

[@superhitmovielive9977]

Sirji hindi me pdao ye please

[@pkclasses100]

S. Entertainment
Future me jarur koshish karenge. Tab tak English me dekhiye. Thank you.

[@bageshwardham.464]

You are only write on the board not explain easy way

[@pkclasses100]

Please watch our latest videos and animations, hoping they may be useful.
This was my starting videos.
Thanks

[@BrotherThamue]

Thank u Sir

[@mathapumounika1929]

tq u very much sir

[@beenabharati6372]

Thnx sir

[@theoceanbrain9053]

Thanks alot sir

[@shikhaprajapati5822]

Thank you so much sir

[@Misschemistry438]

tq so much sir