no as it STARTS from 4 m high. therefore you only need to calculate the distance from the platform to the highest point, double it and then add the 4 metres from the corresponding height of the platform to the ground. meaning it will travel in three segments. the distance, "s" from the platform to the highest point then that same distance from the highest point to where that platform wld be, then the final 4 metres to the ground
If we are saying up is positive then it is -g. We could also say down is positive and the it would be +g. As long as we are consistent for all of the values it doesn't matter.
But at 1:45 he says acceleration upwards is negative but later in the same example he says going up is positive. In this example, the same direction has two different values?
I was referring to the last question. But I'm wrong, I thought that the ball returns to the ground which is under the 4m long platform from which its being launched. Anyways thanks for the reply, I've got the Applied paper tomorrow I've been revising all week using your videos. Thank you!
You are an exceptional teacher in teaching mechanics 1 and being able to present and derive all the core concepts to understand this module better.
This..this is the greatest channel I’ve encountered. Has helped me a lot in understanding mechanics
you just saved my life yet again ilysm
hi i am facing problem in last example.Can you solve my problem?
@Clark Luke trust issues much
may i ask why at 13:00 the a is -g ? but both are going upwards and if I'm not mistaken you say that upwards is positive?
Once again big up this guy excellent stuff helped me a lot.
thank you so much you rly helped me for my test!!
At 11:09 when the ball is falling, why did you make acceleration negative? I thought if the ball is moving up acceleration is negative.
You can choose to make the acceleration positive - that would make the displacement positive too and the answer would remain the same.
@@mathsgenie7808 ok thanks sir
@@mathsgenie7808 but sir when a ball is thrown upwards and we are to find its upward displacement why do we take the g positive
@@amjadanwar202 g acts downwards, so downward is pos, so up is neg
Very helpful video! Thank you!
23:38 wouldnt you need to add 2 4's??
no as it STARTS from 4 m high. therefore you only need to calculate the distance from the platform to the highest point, double it and then add the 4 metres from the corresponding height of the platform to the ground. meaning it will travel in three segments. the distance, "s" from the platform to the highest point then that same distance from the highest point to where that platform wld be, then the final 4 metres to the ground
why is it -g when the object is falling freely due to gravity? shouldnt it be +g
If we are saying up is positive then it is -g.
We could also say down is positive and the it would be +g.
As long as we are consistent for all of the values it doesn't matter.
It is +g though because it is going downwards and isn’t acting against the way the Particle is falling
@@ryanathwal8819 that's what I was thinking
@@ryanathwal8819 it can be either. he just took the upwards direction as positive which make g negative.
But at 1:45 he says acceleration upwards is negative but later in the same example he says going up is positive. In this example, the same direction has two different values?
Isn't it 2s + 8? You travel the path twice. so 4 is doubled and so is s. Cheers
Could you link the time? I can't see which question you are talking about.
I was referring to the last question. But I'm wrong, I thought that the ball returns to the ground which is under the 4m long platform from which its being launched. Anyways thanks for the reply, I've got the Applied paper tomorrow I've been revising all week using your videos. Thank you!