IUPAC Nomenclature 12 || Naming Of Bicyclo and Spiro Compound || For Competetive Exams
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11 chap 12 || IUPAC Nomenclature 01 || Some Basic Principles and Naming Of Alkanes JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 02 || Complex Substituents and cYcLo Alkanes JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 03|| Naming Of Alkens and Alkynes JEE MAINS/NEET
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• 11 chap 12 || IUPAC No...
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IUPAC Nomenclature 10 | Naming of Polyfunctional Compound | MOre than One Functional Group JEE /NEET
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11 chap 12 || IUPAC Nomenclature 01 || Some Basic Principles and Naming Of Alkanes JEE MAINS/NEET
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11 chap 12 || IUPAC Nomenclature 02 || Complex Substituents and cYcLo Alkanes JEE MAINS/NEET
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11 chap 12 || IUPAC Nomenclature 03|| Naming Of Alkens and Alkynes JEE MAINS/NEET
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11 chap 12 || IUPAC Nomenclature 04 || Functional Groups with Secondary Suffix JEE MAINS/NEET
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11 chap 12 || IUPAC Nomenclature 05 || Naming Of Alcohols JEE MAINS/NEET
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11 chap 12 || IUPAC Nomenclature 06 || Naming Of Aldehyde and Ketone JEE MAINS/NEET
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11 chap 12 || IUPAC Nomenclature 07 || Naming of Carboxlic acid and Aid Halide IIT JEE MAINS /NEET
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11 chap 12 || IUPAC Nomenclature 08 || Naming Of Acid Amide and Ester IIT JEE MAINS / NEET ||
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11 chap 12 || IUPAC Nomenclature 09 || Naming of Cyanides , Amines and Ethers IIT JEE MAINS /NEET
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IUPAC Nomenclature 10 | Naming of Polyfunctional Compound | MOre than One Functional Group JEE /NEET
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11 chap 12 || IUPAC 11 || Naming Of Aromatic Compounds - BeNZeNe Rings IIT JEE MAINS /NEET |
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IUPAC Nomenclature 12 || Naming Of Bicyclo and Spiro Compound || For Competetive Exams
th-cam.com/video/zZAJsddI8os/w-d-xo.html
Sir Ur vedio is very helpful...Mjh pehlu smjh ni araha tha pr ab aagya...Bs Ek Chezz Puchni he apse...K ..Jb Hm Longst se smalest chain Ki trf ja rahe hte jen Jese Apne Example B de Jsme Functnal Grp OH he or sbstituent Bromine he...To Is me Smal numbrng ks ko deni he...Fnctnal Grp ko Keh Sbstituent ko?R likhte kse hen Substitunt ko ya Fnctnal Grp ko?
Ya Phr jsko B Aajye Smal no koi msla ni Substitute ko k Fnctnal Grp ko?Bs ye rule folow krna he..Largest se smalest pr ana he...Cahcje Ksi ko b Sbstutnt ya f.grp ksi ko b smlest numbr ajaye
Sir...Last example Me B To Cooh Or Oh dono fnctnal Grp hen ...To is me Cooh ko Kam Numbrng ari he or Oh Ko Zyada halan k Dono Chain equal hen
Obgog
only one request why u put ur channel name physics vala.....
Who is here after watching the whole 12 video series....
concept is crystal clear..!!
Is 12th series enough jor jee mains?
@@vishnujaju5039 Haan Bhai...par iske baad Apne coaching Ka material bhi padhna aur questions solve Karna jee level k
Completed just now...✌🏻. #crystal_clear
@Ashish Singh wow well done bro but i am stuggling for the completiotion of the syllabus.....but i am sure latest by december i will do it ........let's hope 4 the best...best of luck 4 jee 2021
Yes concept clear
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid (answer of bicyclo compound)
Harjinder Singh bro oxo will come na for ketone as suffix.. formyl is for aldehyde i think.
It will be : 10-bromo-5-vyano-11-ethyl-6-oxo-bicyclo[7.2.0]undecane-4-carboxylic acid.
Am I ryt??
@@omkarrane9696 CHO is aldehyde and that carbon in CHO is not counted so it's name is formyl
@@omkarrane9696 no bro jab count nhi karte to formyl kehte hai
@@omkarrane9696 it is not ketone it is aldehyde CHO
Hw1.
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid.
Hw2.
9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide
Correct dost
Same same
@@AnuragSingh-zc7wt great
I looking for this
@@rahulkhatkar3163 what
To all present and future viewers:
Remember that "keto" is now replaced by "oxo" by IUPAC. In some cases, while giving alphabetical priority, this makes a difference.
Right 💯💯👍😌
can you explain it
thanks dude✨
When keto carbon is not counted, it is termed as oxo.
thanks😊
22:20 the answer of the Christmas tree is 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4- carboxylic acid
Correct me , if I am wrong !! 🤔🤔🤔
Bahut hard bro ..shi h
Bahut hard...shi h..mera v yehi h
Right bro...
Correct ..mera v yhi answer hai
Sahi hai bhai.... You are topper😊
Kindly Poll for next chapter in physics and Chemistry starting 21st November. Poll going in community tab of our channel
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Physics Wallah - Alakh Pandey shm
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@@harshkumar3489 search for sirs channel Physicswallah and then open community tab above...u can find it there...
Heat and thermodynamics sir
Sir some lines for you
"Aapse seekha hai maine behisaab se zyada,
Kisi Thokar kisi vyakhyan(lecture) kisi kitaab se zyada.
.
Jo baitha lagane aapke gyan ka andaaza,
Nikla har nadi, Har samandar har talaab se zyada.
.
Agar gyan hi sabse azeez jaydaad hai to,
Aap ameer ho har seth,har vyapari har nawab se zyada.
.
Ye kuch lafz kahne the kabse, aaj kah diye,
Suna hai lafzo se khushi milti hai kisi khitaab se zyada.”
Osm yrrr .....😍😍😍
bhai sahi khel gya..nice lines
Very nice beautiful
Kuch dino se dekh Raha hoon main..... Kuch dino se dekh Raha hoon main..... Tum TH-cam par time bita rahe ho kitaabon se ZYAADA😂😂😂
@@ShubhamSharma-uu9yn maja nhi aaya bhai bekar shayari h teri😊😊
34:10 Hw
9-Ethyl-6-formyl Spiro[4.5]dec-3-ene-1-carboxamide
Right
👍
1 amido 9 ethyl spiro [4,5] dec 3-ene-6-carboaldehyde
Bhai ethyl ko chota no milna chahiye due to alphabetical preference
@@God..MAHI..7pehle first point of difference ke accordingly numbering karni hoti hai.
Alphabetically numbering Krna last option hai
10 bromo 5 cyano 11ethyl 6 formyl bicyclo(7.2.0) undecane 4 carboxylic acid
🤜🤜🤜🤜
9 ethyl 6 formyl Spiro(4.5) Dec 3 ene 1 carboxamide
🤜🤜🤜
Correct answer 👍
5-cyano nhi ....carbonitrile hoga
@@shreysharma726 Not really bro ! Carbonitrile is used when Cyanide is a PFG(Primary functional group )here Cyanide is just a substituent and as a substituent it takes cyano not carbonitrile .Here PFG is COOH
(Carboxylic acid)
@@AjCreations1 bhai ...first of all ...I'm a boy ...not a babe 😂.....and secondly ...yeah you are right ...it should be cyano ...
@@shreysharma726 Autocorrect bro my keyboard is addicted of using babe 😂 so its just turn into something it should not be 😀
22:15 10 Bromo-5 cyano-11 ethyl-6 formyl bicyclo [7.2.0] undecane-4 carboxylic acid
Shi h
Bilkul sahi❣️
Ye bhi thik h❤❤
Right
I also got the same
At 17:45 sir there will be bicyclo [3.2.1]oct-6-ene-3-carbonitrile.
H.W - 1) ans :-
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
H.W - 2) ans :-
9-ethyl-6-formyl spiro [4.5] dec-3-ene-1-carboxamide
Noice brother ✌️
Right😀😀😀
Correct✅ 👍✌
Waha carbanitrile aayenga not cyano 🤔🤔
Not carboxylic acid instead oic acid is preferable
🅷🆆 1
10-Bromo-5-cyano-11-ethyl-6-formyl Bicyclo [7.2.0] Undecane-4-Carboxylic acid.
🅷🆆 2
9-ethyl-6-formyl Spiro [4.5] Dec-3-ene-1-Carboxamide
𝕿𝖍𝖆𝖓𝖐𝖘
9-Ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide (ans. oh HW 2) hoga bro...
@@abhishekrajshah watch video once again
@@harishkanojiya1551 understand, u r right
@@abhishekrajshah nice brother 👍👍
Bijumani Brahma is right
completed watching all the 12 videos in the list. Honestly, it helped so muchhh. Ab lag rha h ki organic aane lagi h nd it's all bcoz of u Sir!🙏❤️
same here 😂👍
same pichhh...........
Same same😊
Same with me...
Hii
10- Bromo-5-Cyano-11-ethyl-6-formyl bicyclo (7.2.0) undecan-4- carboxylic acid (answer of bicyclo compund)
9-ethyl-6-formyl spiro(4.5) dec-3-ene carboxamide ( answer of spiro compound)
And thanks alakh sir for making our concepts crystal clear. He is the best teacher for physics and chemistry for neet and jee♥️♥️
Sahi hai sahi hai
Bro second galat h
9 ethyl nahi aayega 7 ethyl aayega kyuki alphebitical order dekhte hai
@@H11GAMER alphabetical order ko baad mein preference dete hain numbering mein kon pehele aata hain usko likhte hain
@@manjulasharma1623 ok bro
It's 2023, but these videos of yours are still grabbing all the views. Thank you so much sir for such an amazing content of Organic Chemistry. Hats off to your hard work and patience :)
Yeah paaa ji
Bahut bahut sukriya
Hey are you in 11th ?
@@alakhpandey7470 tu coun be
Hw 2
9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide.
Correct me if i am wrong..
Ya bro... Absolutely right
ठीक है ब्रो
@@sangeethachopra581 aldehyde use as oxo as Subtituents when carbon of aldehyde included in pcc..... Other wise we call it formyl.... So here we use formyl ...hope you got it... Other wise you have to revise lecture once again... 🙏🙏
(9 ethyl 6 formyl spiro [4•5] dec 3 ene carboxamide) is the ans of last que of spiro compound
right bro
Right 👍
Dude wudnt 6 be fr ethyl?
@@077_niveshpandey6 we have to first check the lowest locant rule
@@ainymony8098 no bro cho pehle h
34:15
9-ethyl-6-formyl spiro[4.5] dec-3-ene -1-carboxamide
Where is aldehyde?
@@TinaAhmed-ho1bw formyl is aldehyde
@@TinaAhmed-ho1bw Aldehyde ka Prefix is Formyl
Aapka GOOD kaha h
7-ethyl-10-formyl spiro[4.5] dec-3 ene-1-carboxamide
In larger chain alphabetically ethyl comes first than formyl😊
10-Bromo-5-cyano-11-ethyl-6-formyl Bicyclo(7.2.0)undecane-4-carboxylic acid
Sahi hai
Ryt👍
Yes mine matching too
Sirf ek bande ne answer likha 4 lakh logo me se😅😅
V good
34:08 9 ethyl-6 formyl spiro [4.5] dec-3-ene-1-carboxamide
Yes
💯🤜
@@harshitmohan1760 because here CHO is a substitute not functional group.... If it was functional group then we use carbaldehyde
@@bhumikachauhan5258 hmm I got it.
@@bhumikachauhan5258 Thnx!
So the students who are confused in the second HW
7-ethyl se kaafi log shuruaat kar rahe hain
No dear, after naming the left side cycle and the 4° carbon atom you are going through ethyl that is totally wrong because you must go to CHO group first because it's nearer than ethyl group.
First point difference me ye baat batayi gayi hai .
Jab sab kuch fail ho jaaye tab alphabet ke order me chalna hai.
The right ans is
9-ethyl-6-formyl Spiro [4.5] dec-3-ene-1-carboxamide
@Vladimir Vladimirovich Putin It is my pleasure to help you guys.
Thank you sir for this help
Wrong
thanku
@@itsmylife3692 welcome
2) 9-ethyl-6-formyl spiro [4.5] dec-3-ene-1-carboxamide
Wrong❌
Correct
@@aditiverma5990 answer is
7-ethyl-10-formyl spiro(4.5) dec-3-ene -1- carboxamide
Loking very cute💕💕💕......i tried to stop my hand for writing this comment... But I fail..
@@surbhishivankar hii..
Students after watching all lecture of Alakh sir organic chemistry
School Teacher - what is IUPAC
Le students - Halwa
😅
😂😂
🤣🙌
Then "Patt Se HeadShot"
🤣🤣
@@manishkr.shakya6826 bhot sahi
Q.2 9-ethyl-6-formyl spiro [4.5]dec-3-ene-1-carboxamide
Perfect
10-Bromo- 5-cyano-11 -Ethyl-6-Formylbicyclo(7.2.0)undecane-4-carboxylic acid And 9-Ethyl-6-Formylspiro(4.5)dec-3-ene-1-carboxamide
I think Spiro ans is incorrect
Ans : 7 - ethyl-10- formyl - Spiro ( 4.5) Dec -3-ene carboxamide
Please do correct me if I am wrong
You are not correct brother, check again
It Is Absolutely Correct.
is cyano a substituent or functional group??
@@Isha-te9mf functional group
H.W QUES- (1) 22:18 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
(2) 34:10 9-ethyl-6-formyl spiro [4.5] dec-3-ene-1-carboxamide
QUESTION CORRECTION-
17:50 bicyclo [3.2.1] oct-6-ene-3-carbonitrile
Yes 👍 same
Nice
Ethyl ka numbering pehle aayega[34 :10]
Same bro
@@talkwithstatus999 Correct hai buddy koi galti nhi hai isme
The second home work's Ans is : 9-Ethyl-6-Formyl Spiro [4.5] Dec-3-ene-1-Carboxamide.
Exactly
Right bro
HW:1:
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[ 7.2.0] undecane-4- Carboxylic acid
HW:2:
9-ethyl-6-formyl Spiro [4.5] dec-3-ene-1- carboxamide.
Right
Yes I got the same thing
It's wrong I think cause numbering will be done alphabetically so do check
Answer for Spiro is 7- ethyl - 10 - formyl Spiro [ 4. 5 ] Dec - 3 - ene -1- carboxamide
@@sanjanamishra4389 ok, but
Here "cho "substituent is comes on the 6 th place but alkyl substituent comes on the 7 place so as we know that we first go to lowest no for substituent.
If tie between them substituent then we go through alphabetically
Yes
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo (7.2.0)undecane-4-carboxylic Acid.........love you alakh sir...❤️❤️❤️❤️❤️❤️
👏🏼👏🏼
Great bro
mera bhi yahi aaya
9-ehyl-6-formylSpiro(4.5) dec-3-ene-1-carboxamide(Answer of Spiro compound homework)
7 -ethyl -10 formyl spiro [4.5] dec -3-en carboxaminde
@Seema Parween same answer 👍.
Correct,thank you👍👍👍👍
@@Create_clicks Wrong brother. Number the functional group first. I guess u hv numbered the double bond first.
@@Create_clicks 👍🏻
1St h.w
10-Bromo-5-cyano-11-ethyl-6-formyl bicyclo (7.2.0) Undecane-4-Carboxlic acid
2nd h.w
9-ethyl-6-formyl spiro(4.5) dec-3-ene-1-Carboxamide
Perfect bro
@@sumonisingh6949 tq
@@sachinrajawat7437 brother answer will be 7 _ethyl 10 _formyl Spiro(4. 5) dec_ 3 ene 1 carboxamide
Ek vaari aur dekh lo yrr😊
2nd is right
@@sumonisingh6949 yss
Bicyclo homework answer: 10 - Bromo - 5 - cyano - 11 - ethyl - 6 - formyl bicyclo [7.2.0] undecane - 4 - carboxylic acid
Spiro homework answer: 9 - Ethyl - 6 - formyl spiro [4.5] dec - 3-ene - 1 - carboxamide
Thank you buddy ......I had mistake in Spiro hw I gave 1st no. To double bond ..... Thank you yrrr❤️😎
@@VishalPatil-rg9co Wlcm bhai....We are there for helping each other only....
your 2nd answer is wrong bro we will give small no to ethyl ,not to formyl (go alphabetically while numbering) ....if i am wrong then correct me
in spiro cho connected by ring so carbaldehyde will be used
@@priyanshu7 yup bro ❤️
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid (answer of bicyclo compound)
Loved the whole series sir!!
Bhai C tripal bond N ko sir ne example 3 mei carbonitrile likha hai aur tumne 5-cyano
Mujhe yehi clear nhi hai 🙄😕☹️
Yaha Carbonitrile likhu ya 5-cyano 😕😕😕😕
@@thakurraj9119 are bhai ! o sir likhe hai us jagah pr jab C triple bond N "F.G." rahe lekin is compound me to carboxylic acid functional group hai isliye ye sirf ek substituent hai
ᗷᕼIᗩ ᗯᗩᕼᗩ ᑭᗩ ᗯO ᖴ G Tᕼᗩ Yᗩᕼᗩ Yᗩ SᑌᗷSTITᑌEᑎT ᕼIᗩ
@@thakurraj9119 BHAI CARBON COUNT KIA TOH CARBONITRILE CRBON COUNT NAHU KIYA TOH CYANO
34:10 Homework : 9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide
☑️☑️☑️☑️☑️
Correct
Bicyclo... Hw question k upr wala question meh...For ketone group... When do we use "oxo" and when "keto" ????
@@thegoalchaser4980 when carbon is counted it's called Oxo, when the carbon atom is not counted, its known as keto (rare case)
@@teqarine5752 but we counted the carbon of the ring !!
34:05 answer of the last home work question is 9-ethyl-6-formyl Spiro [4.5] Dec -3- ene carboxamide
Right bro...
Correct
Sabi hai
@@roshnikumari9751 right. 7-ethyl-10-formylspiro[4.5]dec-4-ene-1-carboxamide
@@Hunter_6585 wrong nmbring..
Priorityvise you should give less nmbr to CHO then ETHYL
7-ethyl-10-formyl Spiro(4.5)dec-3-ene-1-corboxamide
10 -bromo-5-cyano-11-ethyl-6-formyl bicyclo[7,2,0] undecane-4-carboxylic acid
Exactly 💯
Cyano: carbonitrile , CN ka C count nhi huaa
@@dktanwer25 ye tab hoga jab CN ko as primary fictional grp dekha jahega. But yaha primary COOH ya ki carboxylic acid hai
11- ethyl pehle aaega n fir 5- cyano ( alphabetical order)
@@samirkumar9674 a, b, c, d, e, "
Kon phele hayega?
Homework answers - this is what I've gotten
1. 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid
2. 9-ethyl-6-formyl spiro[4.5] dec-3-ene carboxamide
Correct
6-carboaldehyde-9-ethylspiro(4.5)dec-3-ene-1-carboxamide
2 one galat hai
7 ethyl 10 formyl..numbering alphabetically
Same bro 🤟
22:20 Bicyclo homework
10-Bromo-5-cyano-11-ethyl-6-formylbicyclo[7.2.0]undecane-4-carboxylic acid
Correct
Correct
Why undecane?
@@manojkumarchaubey3133 Because 11 carbon compounds 😅
Ethanyl
22:20 The answer for the christmas tree is 10-bromo 5-cyano 11-ethyl 6-formyl bicyclo [7.2.0] undecane - 4 - carboxylic acid
Yes, it's correct. 👍
Correct vro 👍
@yoyo Sharma correct ans is
10- Bromo-5-cyano-11-ethyl-6-formyl byclo( 7.2.0)undecane-4-carboxylic acid
😊
@yoyo Sharma carbaldehyde tab ata jab ring se attached functional gp. Ki tarah kaam kare ab to voh substitute hai to formyl hoga
Same ans Mera bhi😁
9-Ethyl-6-formyl Spiro (4.5) dec-3-ene-1-carboxamide
😊😊
Answer of HW-2: 9-ethyl-6-formyl spiro[4.5] dec-3-ene carboxamide
correct
Yes
Correct answer
17:54 mei oct-6-ene ke baad 3-carbonitrile hoga na ??
Glt h
King of organic chemistry is the physics wallah.
And also king of physics.
@@NishaSingh-px1bz from which region u r?
@@muskangoswami9711 I am from Bihar but now I live in Indore. And your name
I m also from that region
Now i m in gujarat ..
34:08
Incorrect ans : - 7-ethyl-10-formyl Spiro [ 4.5 ] dec-3-ene Carboxamide
Correct and : - 9-ethyl-6-formyl Spiro ( 4.5 ) Dec- 3- ene -1-carboxamide
👍👍👍😊😊😊
Nahi bro mera to 9-ethyl-6-formyl spiro[4.5]dec-3-ene-1-carboxamide aa rha h
You are right bro
Thanks 🙏
Bro kyu 1st wala incorrect hai?
@@ShivamKumar-xb6ow kyuki ki aldehyde ka a pehle ataha hai ethyl ke e se ,aur woh ab substituents hai naki FG
9-ethyle , 6formyl , spiro(4.5) dec-3-ene carboxyamide ( ans of spiro hw)
17:35 the name of compound should have been bicyclo[3.2.1] oct-6-ene-3-carbonitril. < 3(position) was missing before carbonitril
U r right bro✔️✔️✔️
Yep
Spiro:- 9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide.🤘
No bro wrong
.......7 ethyl 10 formyl ......
Because it is not funtional group so set as alpha bet ....
@@ayushabd89 plse see again properly!
@@ayushabd89 substituents in 6,9 position have lowest first point of difference than 7,10.position have more priority than the alphabetical order
@uggj
Bhai 6 - formyl nhi 6-oxo. Hoga. Q ki. Aldehyde ka carbon. Count nhi hua hai...
HW : 1
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid
HW : 2
9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide
H.W 2 me
3-ene aayega
HW 1 mei undecane-4-carboxylic acid.. an'e' ka e iss baar omit nahi hoega
@@DTechnoBox
yeah u r ryt
@@abyssal.__.
Thanks for correcting me.....
Mera bhi same hai
answer for 1st hw: 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0]undecane-4-carboxylic acid
2nd h.w: 9-ethyl-6-formylspiro[4.5] dec-3-ene-1-carboxamide
Correct bro
Yeahh🔥 That's correct answer✔🎯
Bhai numbering galat hai baaki sahi hai spiro me ethyl me 6 aur formyl me 9 aayega because e pehle aata hai uske baad f 👌💯💯
Correct ans of 2nd one
7-ethyl-10-formyl Spiro [4.5] dec-3-ene1-carboxamide
Dec 1 ene
Hw:1 10-bromo-5-cyno-11-ethayl -6-formayl bycyclo (7.2.0)undecane -4-carboxylicacid
Hw:2 9-ethayl-6-formayl spiro (4.5)dec-3-en-1-carboxamide
why CONH2 taken priority over CHO??
@@deepakdutta1391 coz acc. to priority order amide comes before aldehydes
@@deepakdutta1391 bcz of priority table it comes over CHO
Bhai ethyl hota hai ethayl nahi aur formyl hota hai formayl nahi.
Dec k baad ene ka 'e' remove nahi hoga.
@@toshitpant3980 ok thankyou bro
9-ethyl-6-formyl Spiro(4.5) Dec-3-ene-carboxamide.
1.
10-Bromo - 5 cyano - 11- ethyl - 6- formyl Bicyclo [7.2.0] undecane - 4 - carboxylic acid
( while taking nitrile as a substitutent carbon must not be counted so it will be cyano)
2.
9-ethyl - 6 formyl spiro [4.5] dec-3-ene -1- carboxamide
( numbering from formyl due to first point of difference) and first point of difference >>>>>>Alphabet
THANK YOU ❤
Hi your answer is correct but there is a mistake instead of 6-formyl you can write 6-carbaldehyde because in this carbon was not get counted
@@archnashukla7870 carbaldehyde is used when aldehyde comes as a functional group and it's carbon is not counted .Here aldehyde acts as a substituent,so formyl is used .
same answer bro
I have lost all my fear of nomenclature.Thank you sir.
Me too
Same
Merko ek baat ab realise hui ki bacchoo ki achi tarah samjhane ke liye teacher ke andar 3 gun hona zaroori h
1st he should himself know all concepts clearly
2nd he should know how to transfer these huge info. In small chunks
3rd know student's first occuring doubts ...
@@namangarg6660 sahi kaha brooo
@@namangarg6660 yaa! Agree naman🤟👍🏿
For spiro ans is
9-ethyl-6-formyl spiro (4.5) dec-3-ene carboxamide
Sai hai mera bhi yahi aaya
methyl?
22:18 hw tree structure answer 10-Bromo-5-cyano-11-ethyl-6-formly bicyclo [ 7.2.0 ]undecane-4-carboxylic acid.
[spiro compound hw] 9-Ethyl-6-formlyspiro [4.5] dec-3-ene-1-carboxamide.
Correct sis
thnks mera tree wala nahi hua tha
@@niladrinaskarnpssbs5903 ☺️
Cyano spelling mistakes and one mistake that is dec-3-ene.. Not dec-4-ene..
@@srikutty7150 oh ya thanku..corrected
H.W.2 = 9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide
bhai yeah 11 classs mai hai topic??
Ha
This is wrong as according to nomenclature ethyl formly se pehle aata hai alphabetically so use pehle no. Milna cahiye wo dono hi substituent hai isiliye alphabetically numbering hogi
@@anuragupadhyay9707 you are right bro
@@anuragupadhyay9707 correct one is 7-ethyl-10-fomyl Spiro[4.5]decane carboxamide
22:20 answer: 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0.]-undecane-4-carboxylic acid
Yes
Yes bro
1) 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid.
2) 9-ethyl-6-formyl spiro[4.5] dec-3-en-1-carboxamide.
2)7-ethyl-10-formyl spiro (4.5)dec-3-ene-1-carboxamide
correct
Answer of HW1:- 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid..
Answer of HW2:- 9-ethyl-6-formy spiro [4.5]Dec-3-ene-carboxamide..
no acid is written after carboxamide
@@TheBoyzzz69 Yeah thanks
✨ HW - 1 ✨
1) 10 - Bromo - 5 - cyano - 11 ethyl - 6 formyl bicylo ( 7.2.0) undecane -4 - carboxylic acid
✨ HW -2 ✨
2) 9- ethyl - 6 formyl Spiro [ 4.5 ] Dec 3-ene 1-Carboxamide
No
Formyl
no oxo yes
Why cyano bro why not carbonitrile
And why undecane why not tridecane
@@ishitatayal2200 bcz cooh have more priority than cyanide
Home work:-1
10-Bromo-5-cyano-11-ethyl- -6- formyl bicyclo [ 7.2.0 ] undecane-4-carboxylic acid .
Home work:-2
9- Ethyl-6-formyl spiro [ 4.5 ] dec-3-ene-1-carboxamide .
Homework 2= 7-ethyl 10- formyl spiro (4.5) dec 3- ene 1- carboxamide
@@Shivanisharma-yx4lz yes this one is correct
@@Shivanisharma-yx4lzyes this I got
@@Shivanisharma-yx4lz correct :- 9- Ethyl-6-formyl spiro [ 4.5 ] dec-3-ene-1-carboxamide
@@Shivanisharma-yx4lz lowest set of locants b/w -> 1,3,6,9 and 1,3,7,10 is the first one.
Lowest set of locants has more priority over alphabetical order
10-bromo-5-cyano-11-ethyl-6-formyl,bicyclo[7.2.0] undecane-4-carboxylic acid is right ans. of H.W.
bhai yeah 11 class mai hai
Did you notice something at 15:40😒😒
Sir ne COOH ko primary functional group le liye or uske baaad numbering ke liye kaha ki function group ko priority doh par😖
Par in the case of Spiro sir ne kaha ki ek baar primary functional group decide ho gaya uske baad functional group or substitutent m koi priority nahi raheti🤔🤔
Please reply if anyone is reading my comment 🙏🙏🙏🙏🙏
thanks
@@prashujoshi8179 ha
@@d.celestio1574 welcome
HW 2. 7-ethyl-10-formyl-spiro[4.5]dec-3-ene-1-carboxamide
Homework answer. (1)10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid. (2)9-ethyl-6-formyl Spiro[4.5]dec-3-ene-1-carboxamide
2 -carbanamide
Or dec-4-ene
Yesh bro ur correct 😂
7-ethyl brother not 9 ethyl
who prefer watching old alakh sir videos than the new one
Both are osm😊😊
ur mom
@@sankhalpsunod4102 epic reply 🤣🤣
@@sankhalpsunod4102 😂😂😂
@@sankhalpsunod4102 ur dad
34:10 hw...
9-ethyl-6-formyl spiro [ 4.5 ] dec-3-ene-1-carboxamide
Right bro
Ryt same ans
6 ethyl 9 formyl spiro(4.5) dec 3 ene 1 carboxamide because alphabetically counting will take place as here CHO will not be considered as functional group
Correct brOOO
galat hai bhai iska 7-ethyl-10-formylspiro[4.5]decane-1-carboxamide .
reason: CHO ko formyl as a substituent and ethyl starts from e so no. from ethyl firstly
Finally IUPAC completed 🥳
Thank you sir❤️
22:15 - 10-bromo - 5-cyano-11ethyl-6-formyl bicyclo [7.2.0] undecane -4-carboxylic acid
Last question- 9-ethyl 6-formyl spiro [4.5] dec-3-ene -1- carboxamide...
Finally IUPAC series complete!!!❤️
Bro alphabet ke hisab se pehle... 6- ethyl
Correct answer: 9-ethyl-6-formyl spiro(4.4)Dec-2-ene-4-carboxamide
@@ananyasubhadarshini1824 first priority functional group ka hota h n... isliye carboxylic acid najdik aayega....to uske idhar se hi numbering krenge n....
Priority order mei phle functional group aata h n...aur ye agar valid nhi hoga uske baad alphabetically count krenge n
Am I right???
@@true_love.7817 bro ye [4.4]kaise aaya
100% absolutely right answer
9 ETHYL 6 FORMYL SPIRO[4.5] DEC-3 ENE 1- CARBOXAMIDE
*Bicycle compound*:10-bromo 5-cyano 11-ethyl 6-formyl bicyclo[7.2.0] undecane carboxylic acid.
*Spiro compound*: 9-ethyl 6-formyl spiro[4.5]dec-3-ene carboxamide
Thank you sir ❤️🔥
Bro i think the bicyclo one is ur correct but it will be undecane- 4- carboxylic acid..u missed the 4
Bro I think your Spiro compound is incorrect as alphabetical preference ke according ethyl ko least no. milna chahiye
According to me it will be
Spiro:- 7-ethyl-10-formyl spiro[4.5] dec-3-ene-1-carboxamide
I agree with you
@@piyushkumar5-aayushkumar8-65 no , first we give no. acc to first point of difference then we see alphabetical order if no option left
22:16 *10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid*
finally completed full iupac nomemclature..tqq... so much alakh sir....
@@sarthakshukla786 are bhai vo aldehyde nhi hai vo ketone hai
@@sarthakshukla786 carbon main chain m count krenge to oxo or nhi krenge to formyl, it is only for aldehyde
@@sarthakshukla786 ketone m aisa kuch b nhi hai, ketone m keto ya oxo m se kuch b likh sakte hai
@Mohd Shaiba likhwaya to tha, par un dono m se kuch b use kr sakte hai
@@sarthakshukla786 are bhai baat vo hi hai, keto likho ya oxo
34:15 9-ethyl-6-formyl spiro(4.5) dec-3-ene-1-carboxamide.
10-Bromo-5-cyano-11-ethyl-6-
formal bicyclo (7.2.0) undecane-4-carboxylic acid
😊😊
sir honesty i have watched all 12 videos of yours
really it helped me a lot
thank uuu so much
it was really gorgeous lecture of yours
once again thank uuuu
You are really a great teacher.....
1) 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
2) 9-ethyl-6-formyl spiro [4.5] dec-3-ene 1-carboxamide
Enjoying your lecture too much sir and also helpful for me...
Thank you so much sir......
numbering kaise kiya bata sakti hai?
here why will we get cyano ? we should get carbonitrile because we are not counting the carbon of cynaide
@@19-adanish93 take bridge head carbon as 1 or 2
after taking 1 or 2 start numbering the largest carbon chain then come to smallest and follow so on..... Hope it helps you
@@ashishreddy5382 samjha samjha ....thanks
@@ashishreddy5382 See in that question -COOH group is also present which has a higher priority than cyanide grp. So we need to consider the -COOH grp. as the primary func. grp. and thus the cyanide grp. becomes the substituent and so its named as cyanide and not carbonitrile....Hope this helps.
H.w. 2:- 7-ethyl-10-formyl spiro[4.5]-Dec3-ene-1-carboxamid
Last answer of bicyclo: 10-bromo-5-cyano-11-ethyl-6-formylbicyclo[7.2.0] undecane-4-carboxylic acid
Hi
If you don't mind , can ask one thing
Right hai beta 😊
@@AjayPal-tu1vm bete English sudar le pehle tab [ can ask something ]
Ekk Number 👍🏻
Well done ✅
7-Ethyl-10-formylspiro [4.5]dec-3-ene-1-carboxamide
💯correct
Harish chandra
Correct
Absolutely correct dost
Correct because follow alphabetical order
10 - bromo - 5 - cyano - 11- ethyl - 6 - formyl bicyclo [ 7.2.0 ] undecane - 4 - carboxylic acid. (H.w Naming of bicyclo compound )
Wrong
same here
Write hai
34:38 H.w. No 2. (((((( 9-ethyl-6-formyl spiro [4.5] dec-3-en-1-carboxamide )))))
abhi pushp ene pura bro
😒.
Last homework answer= 9-Ethyl-6-formyl spiro
[4.5] dec-3-ene-1-carboxamide
Is it correct?
7-ethyl-10-formyl Spiro(4. 5) dec-3-ene-1-carboxamide
Mere khayal se toh ye hona chaiye
32:15 pe bhi sir ne alphabetically wise hi continue kiya tha toh 9-ethyl-6-formyl galat lag raha
@@raptor7s mine correct bro.. Just google the structure
@@rashwonsingkai7955 oh okay thanks for the clarification i was confused
@@raptor7s ok bro.... Bro alphabetically numbering nhi hiwa kyu ki.... Formyl group ethyl group ke mukable jyada close he...
@@rashwonsingkai7955 oh i see..
Q.2) spiro compound H.W
7-ethyl-10-formyl spiro[4.5]dec-3-ene-1-carboxamide
Ans of ques no.2 is 9-ethyl-6-formyl spiro [ 4.5.] dec-3-ene - 1 carboxamide
I hope 7-ethyl-10-formyl spiro[4.5] dec-3-ene-1-carboxamide. Is correct.
I hope this answers is correct
My answer is same...
22:00....
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane 4 carboxylic acid
Tridecane hoga vi... Baki sab sehi hai
After teaching by him we don't need any offline teacher. He is just awesome 😍. Thank you 🤗 so much Sir for doing such a hard work for us 👤.
*Love you Alakh Sir* ♥️
🙌🙌🙌🙌🧿❤🤟
Bicyclo compound HW
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid
Spiro compound HW 9-ethyl-6-formyl-spiro[4.5]dec-3-ene carboxamide
Thank you very much sir for clearing all doubt about nomenclature, Love from Bangladesh
It should be 9-formyl-6-ethyl spiro [4.5] dec-3-ene -1 - carboxamide as first point of difference >>alphabetical order
@@Bhavya_Khatribut yha pr alphabetically numbering nhi hogi na kyuki 6 pr hi substituent mil ja rha h
Ans - 2. 9- ethyl 6- formyl Spiro [ 4 . 5 ] Dec- 3 ene 1- carbamide
carboxamide
That's wrong bcz....acc to albhabetical order u should right 7-ethyl-10-formyl spiro (4.5) dec-3-ene carboxamide
34:10 HW
9-ethyl-6-formyl Spiro [4.5] dec-3-ene-1-carboxamide...🙂
Homework question 2nd it's 7-ethyl-10-formyl-spiro[4.5]dec-3-ene-1-carboamide
You are write bro😊
Hw:1
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo ( 7.2.0) undecane-4-carboxylic acid.
Correct
@@jenilvaghasiya233 yes absolutely right
@@jenilvaghasiya233 can u help me to reach 2k plzzz🙏🙏 subscribe my channel
Correct
@@AmanKumar-vc7wl bhai subscribe me plzzz
At 22:22
1) 10 Bromo 5 Cyano 11 ethyl 6 formyl Bicyclo [7•2•0] Undecane-4- Carboxylic acid
At 34:10
2) 7 ethyl-10 formyl Spiro [4•5] Dec-3- ene-1-Carbamoyl
I think this one is correct...👍
Thankyou so much sir ji
Wrong hai 2nd cho ke or jayenge
@@ravindrachauhan9680 bro alphabetically jao....then you'll get correct answer
2nd is wrong, carbamoyl is used for prifix
Both answers are correct
22:23
Answer to homework question (Christmas tree type) is
10-bromo-5-cyano-11-ethyl -6-formyl bicyclo [7.2.0] undecan-4-carboxylic acid.
Tell if some correction to be done.
I think it will be undecane...
@@baishali01 yeahh..
yaha cyano kyu likhe matlab carbon count nhi hoga to carbonitrile aayega na ?? plz reply
@@homeacount4969 Yeah it would be carbonitirle...
@@homeacount4969 woh prefix name h .... Subsituent ki trah use hua h cyanide main functional grp toh cooh h
The best teacher I have I ever seen....sir u made me loving organic chemistry...❤️❤️
HW 1 (Christmas tree)
10-bromo-5-carbonitrile-11ethyl-6-formyl bicyclo[7.2.0] undecane - 4 carboxylic acid
HW 2
9-ethyl-6-formyl Spiro[4.5] dec-3-en-1-carboxamide
Bhai sahi h yrr !!
Watch lecture 10 to clear your doubts thoroughlly
@kanhai lal sah See carefully at 20:50 , the carbon of cyanide group will not be counted in main chain.
@@tattwashiwani3158 yes and it is not the main functional group so cyano will be used
And last 'e' of dec-3-ene will not be removed as c comes after that
H.w-1:- (22:19)
10-Bromo 5-Cyano 11-Ethyl 6-Formyl Bicyclo[7.2.0]undecane 4-carboxylic acid
H.w-2:- (34:15)
9-Ethyl 6-Formyl spiro[4.5] dec 3-en 1-carboxy amide
CORRECT ME IF I AM WRONG
dec-3-ene-1-carboxamide the e will not be deleted as there is no aeiouy
Can we do 7-ethyl-10-formyl because they both are substituent and by alphabetical ethyl should get priority firstly
@@tannu-xl4fv no
@@tannu-xl4fv no
Hw1
10_bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
Hw-2
9-ethyl-6-formyl-spiro(4.5) dec 3 ene 1 carboxamide
Why undecane
Correct
@@shubhamchouhan7722 I think 6ethyl 9formyl will come
34:00 this was a good question answer I got is 9-ethyl 6-formyl spiro [4.5] dec-3-ene - carboxamide
I guess 7-ethyl-10-formyl Spiro [4.5] dec-3-ene carboxamide hona chahiye kyunki substitutent ko alphabetically numbering Krna hai pehle ethyl then formyl??? Correct me if I am wrong??
@@anjalii9500 Substituents ko low position pr v to rakhna hai
Ethyl wala formyl ki trh adjacent nhi hai 4 degree carbon ke....
Bicyclo compound answ). 10 -Bromo,5-cyano ,11-ethyl ,6-formyl ,Bicyclo [7•2•0] undecane ,4-carboxylic acid
Spiro compound ans : 9-ethyl,6-formyl Spiro[ 4•4] Dec-3-ene carboxamide
carboxamide ki jagah carbamoyl use nhi kar skte kya?
@@aasthasingh1236 Carbamoyl is used when acid amide is a substitutent it's can not be used here. When acid amide is directly attached to ring it's called carboxamide so that will only be used.