Cantilever Beam Problem 3: Draw Shear Force and Bending Moment Diagram [SFD and BMD] by Shubham Kola

In this video we are going to Learn about How to draw Shear Force diagram [SFD] and Bending Moment Diagram [BMD] for cantilever beam of 1.5 meter long carries uniformly distributed load of 2 kilo Newton per meter and point load of 3 kilo Newton.
This problem we are going to solve it, in 3 simple steps.
1. Calculate the values of support Reaction.
2. Calculation of Shear force
3. Calculation of Bending Moment
Timecodes
0:07 - Problems on Shear force and Bending Moment Diagram [SFD and BMD] for Cantilever Beam
1:10 - Convert uniformly distributed load into point load
1:55 - Calculations of Reaction forces for Cantilever Beam
3:29 - Shear force Calculations for Cantilever Beam
10:21 - Bending Moment Calculations for Cantilever Beam
12:22 - Sagging Effect and Hogging Effect for Cantilever Beam
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Your Queries :-
How to calculate shear force for cantilever beam carries uniformly distributed load and one point load
How to calculate bending moment for cantilever beam carries UDL
How to draw shear force and bending moment diagram for cantilever beam
You can also watch separate videos for Shear Force and Bending Moment Problems on 4 types of beams -
Cantilever Beam - • Cantilever Beam: Shear...
Simply Supported Beam - • Simply Supported Beam:...
Overhanging Beam - • Overhanging Beam: Shea...
Simply Supported Beam with Uniformly Distributed Load - • Uniformly Distributed ...
You can also watch Playlist on Shear Force and Bending Moment Solved Problem
Shear force and Bending Moment Diagram Solved Problems - • Shear force and Bendin...
Faculty - Shubham Kola
Email ID - [e-mail]
From - Maharashtra ( India )
TH-cam Channel ( Shubham Kola ) - / @ifinfotech
Disclaimer -
video is for educational purpose only. Copyright Disclaimer Under Section 107 of the Copyright Act 1976, allowance is made for "fair use" for purposes such as criticism, comment, news reporting, teaching, scholarship, and research. Fair use is a use permitted by copyright statute that might otherwise be infringing. Non-profit, educational or personal use tips the balance in favour of fair use. The content in this video is collected from books, media, internet space etc. This is strictly for educational and information purposes and is not intended to be advice or recommendation of any kind whatsoever. The faculty is not a subject expert. The faculty is sharing his knowledge in the form of videos. The faculty giving small basics information on mechanical engineering topics. We endeavour to keep the information up to date and correct, we make no representations or warranties of any kind, express or implied, about the completeness, accuracy, reliability, suitability or availability with respect to the video or the information, related graphics contained in the video for any purpose. any reliance you place on such information is therefore strictly at your own risk. In no event will we be liable for any loss or damage without limitation, indirect or consequential loss or damage, or any loss or damage whatsoever arising from loss of data or profits arise out of, or in connection with, the use of this video.

[@suhassuhas7891]

❤

[@rak7856]

Very nice sir❤

[@ifinfotech]

Thanks

[@shiwanthabandara4840]

Dear sir ,at point C bending moment 1.25÷2 is 0.625 but you put 0.0625 is it mistake.

[@LwaziMchunu-sc3ex]

amazing

[@shiwanthabandara4840]

Dear sir at point C 1.25÷2 is 0.625 but you put 0.0625. It is mistake?

[@Nikhil-gx2lt]

its -0.5*0.125 = -0.0625

[@morgegangkak4446]

Bakwaas explanation