Force on a Pipe Bend - Fluid Momentum Example Problem

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  • เผยแพร่เมื่อ 27 ธ.ค. 2024

ความคิดเห็น • 24

  • @MaximillianChristiansen
    @MaximillianChristiansen หลายเดือนก่อน +4

    this was the BEST explanation I've ever seen. couldn't wrap my head around this topic, 13 min later and I'm 100 percent confident in it

  • @adamcherry1117
    @adamcherry1117 11 หลายเดือนก่อน +2

    Thanks, I watched this during the exam

    • @BrianBernardEngineering
      @BrianBernardEngineering  11 หลายเดือนก่อน

      I hope your exam was open book / open internet. Otherwise you may want to keep that to yourself :P

    • @adamcherry1117
      @adamcherry1117 11 หลายเดือนก่อน

      @@BrianBernardEngineering yes of course haha

    • @adamcherry1117
      @adamcherry1117 11 หลายเดือนก่อน

      @@BrianBernardEngineering from CFD

  • @bkq1
    @bkq1 ปีที่แล้ว +1

    A.M.A.Z.I.N.G video, love the enthusiasm and attention to each detail!

    • @BrianBernardEngineering
      @BrianBernardEngineering  ปีที่แล้ว

      Thanks so much for saying. Your TA Indy is usually more of a "big picture" kinda kitty, but in this case of the Reynolds Transport Theorem, he's all about the details.

  • @stevenkanguya5087
    @stevenkanguya5087 6 หลายเดือนก่อน +1

    one of the best explanation i have ever heard,thank you very much am humble 🙏

  • @douglaswilson-p6o
    @douglaswilson-p6o 4 หลายเดือนก่อน

    This is such a well produced video, really should have more views!

    • @BrianBernardEngineering
      @BrianBernardEngineering  4 หลายเดือนก่อน

      That's very kind to say, thank you so much for watching.

  • @ahmed12op
    @ahmed12op 2 หลายเดือนก่อน

    @4:17 What if you have a nonuniform flow? You need to include the integration over the control surface.

    • @BrianBernardEngineering
      @BrianBernardEngineering  2 หลายเดือนก่อน

      Yes, this is correct. It would have been better if I had explicitly written "uniform flow" in my assumptions section, since I was making that assumption here, which makes the integral trivial.

  • @sunflower_2002_
    @sunflower_2002_ หลายเดือนก่อน

    is right positive because you already determined a coordinate system with y axis positive upwards and x-axis positive to the right? Because when calculating over a tee pipe, you would determine the coordinatesys. another way?

    • @BrianBernardEngineering
      @BrianBernardEngineering  หลายเดือนก่อน

      Yes, I defined my xy coordinates positive Right and Up, default style. You could rotate these for a different problem where it makes sense, my choice was convenient, but ultimately arbitrary.

  • @NexiOHome
    @NexiOHome 8 หลายเดือนก่อน

    Ive been an engineer for about 3 years now, absolutely love it. Best explanation I've come across... what is your background?

    • @BrianBernardEngineering
      @BrianBernardEngineering  8 หลายเดือนก่อน +7

      Your TA Indiana is just a regular kitty - no formal training at all - entirely self taught. For me - I was a nuclear power officer on submarines in the us navy. That was my first job after college. Nowadays, I have a phd in mechanical engineering, and I teach at Schreiner University in Kerrville, TX. Thanks so much for watching.

    • @NexiOHome
      @NexiOHome 8 หลายเดือนก่อน

      @@BrianBernardEngineering i would love some examples of an isentropic nozzle and its relation with static air temps at different points in the nozzle. How do the temps differ? especially, being isentropic (trick question?) Also, tie in the mach number at a specific point IN the nozzle. Want to see an example??

  • @jaredflint2915
    @jaredflint2915 2 หลายเดือนก่อน

    If the pressure at the outlet was Patm, would we consider it then? Since the cross sectional area at the outlet is different?

    • @BrianBernardEngineering
      @BrianBernardEngineering  2 หลายเดือนก่อน +1

      I would almost always recommend working in terms of gage pressure, which makes Patm = 0, and can be ignored.

  • @weaamshaheen3024
    @weaamshaheen3024 4 หลายเดือนก่อน

    Why do we use gauge pressure? And not the abs

    • @BrianBernardEngineering
      @BrianBernardEngineering  4 หลายเดือนก่อน

      It's usually the difference in pressure that actually matters. Pressure inside something pushes outward, atmospheric pressure pushes inward. The difference is important since you are summing forces in the two different directions to get a net force due to gauge pressure. This is why you don't actually measure atmospheric pressure usually. Atmospheric pressures changes a bit everyday due to weather. Since we only care about the gauge pressure, it doesn't matter exactly what the reference points absolute pressure is.

    • @louhokok3474
      @louhokok3474 2 หลายเดือนก่อน +1

      ​@@BrianBernardEngineering If the pressure at the outlet was Patm, would we consider it then? Since the cross sectional area at the outlet is different?