equations in handbook still help. Its the same thing you wrote, but set pressures =0 & W=0, and you can solve for resultant forces in x and y directions
Hi Dani, just use this link here it will direct you to the page in FE Handbook 10.0.1 ----> www.cee.msstate.edu/wp-content/uploads/fe-handbook-10-0-1.pdf#page=203
This was a quite helpful video ...Such a pinpoint material for my fluid mechanics I exam ....Best for practice
Nice! I am glad to see it help. Keep up the good work!
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th-cam.com/video/GZmiaMZv1g8/w-d-xo.html
equations in handbook still help. Its the same thing you wrote, but set pressures =0 & W=0, and you can solve for resultant forces in x and y directions
f=-(.126)(999.7)(25cos(135)-25)= 5375 in the direction dictated by the handbook(+), which in the problem is negative
Brilliant stuff, very helpful. Thanks for the effort!
You're welcome! Thanks for watching.
th-cam.com/video/GZmiaMZv1g8/w-d-xo.html
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What page are those tables on? 4:27
Hi Dani, just use this link here it will direct you to the page in FE Handbook 10.0.1 ----> www.cee.msstate.edu/wp-content/uploads/fe-handbook-10-0-1.pdf#page=203
th-cam.com/video/GZmiaMZv1g8/w-d-xo.html
amazing videos !!!!!
Thank you!
th-cam.com/video/GZmiaMZv1g8/w-d-xo.html
Thanks a lot brother!
Why you didn't use the continuity equation to solve it?
How would you do that? Genuinely curious
Post more of all subjects!
I try my best sorry.
@@directhubfeexam wasn't meaning in a rude way these are very helpful videos
@@slagwolf7 Thank you so much!
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