Olympiad Geometry Circumcenter Example 2

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  • เผยแพร่เมื่อ 25 ม.ค. 2025

ความคิดเห็น • 8

  • @Imranahmed08
    @Imranahmed08 22 ชั่วโมงที่ผ่านมา

    Could you please help me out
    In this geo problem for finding more elegant soln , although I have already solved it but its kind of too long ,
    ABCD is a cyclic quadrilateral with side lengths as follows. AB = 6 cm, BC = 12cm , CD = 3 cm and DA = 6 cm.let the intersection of AB and CD be "E" and intersection of CB and AD be "F". Find the length of EF

    • @OlympiadGeometry-2024
      @OlympiadGeometry-2024  3 ชั่วโมงที่ผ่านมา

      you can prove that triangle EAD is similar to triangle ECB and triangle FDC is similar to triangle FBA. Then you can calculate that EA=4 and ED =5, FD=10 and FC=8. Then you know that triangle EDF is similar to triangle ADC, therefore, AC// EF. AB^2+BC^2-2AB*BC*cos ABC=AD^2+DC^2+2AD*DC*cos ABC. So cos ABC=3/4. Then AC=6sqrt2. So EF=10sqrt2.

    • @OlympiadGeometry-2024
      @OlympiadGeometry-2024  3 ชั่วโมงที่ผ่านมา

      Not sure if my method is the best solution. And if you want I can open a new playlist as problems from audience to solve it publicly. No pressure, only if you are willing to.

    • @Imranahmed08
      @Imranahmed08 2 ชั่วโมงที่ผ่านมา

      My soln was kind very similar to yours
      Soln.
      •By power of point of "E"
      ( EA)(EB)=(ED)(EC).......(1)
      • Notice that CA is angle bisector of angle《DCB in triangle 🔺️ ECB
      (ED+DC)/(BC) = (EA)/(AB)...(2)
      From eqn 1 and 2
      We get ED=5 ; EA=4
      Apply meneluas theorem In 🔺️ EBC and with line A-D-F
      We get CF=8
      Using cosine rule in triangle 🔺️ AED We get Cos(《EAD) = -9/16
      ==> Cos(《ECF) = 9/16
      To finish use cosine rule in triangle FEC

    • @Imranahmed08
      @Imranahmed08 ชั่วโมงที่ผ่านมา

      And regarding to a new playlist for your youtube family and specially for me I would highly encourage your effort toward your hardships for us
      And at last I want you to start a new separate playlist on geometry, where we can send you problem's or doubt so that you can explain them in your video's.
      &
      ❤Thanks for your response

  • @3.28thunsudaruangnoot7
    @3.28thunsudaruangnoot7 12 ชั่วโมงที่ผ่านมา

    Excuse me could you please help me
    If PN is the perpendicular from any point P to the radical axis of two circles the centers of which are A, B, and PQ, PR are the tangents from P to the circles, then PQ Power of 2 - PR Power of 2 = 2 PN ΑΒ.
    CONSTRUCTION: Draw PM ꓕ AB, and join PA, AQ, PB, BR

    • @OlympiadGeometry-2024
      @OlympiadGeometry-2024  3 ชั่วโมงที่ผ่านมา

      I’m not sure if I understand the problem set but it looks like there’s no definition of point N. We only know PN is perpendicular to radical axis. But how to define where N is?

    • @3.28thunsudaruangnoot7
      @3.28thunsudaruangnoot7 2 ชั่วโมงที่ผ่านมา

      @ Point N is from drawing a horizontal line, drawn to point P. We can determine the length, but anyway I still can't solve this geometry problem😭