Degree of Kinematic Indeterminacy of Beams Neglecting Axial deformation
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- เผยแพร่เมื่อ 5 ก.พ. 2025
- Concept of Kinematic indeterminacy / Degree of Freedom & Problems on Degree of Kinematic indeterminacy of Beams Neglecting Axial Deformation [ HINDI ] Structural analysis - 2
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very very accurate. my whole cioncept is clear now. thanks brother.
Helpful for engineering students
Tnq Soo much bro....nice information.....👏👌👍
Degrees of freedom are the possible ways by which a rigid joint would move(i.e. either translation or rotation or both).
For fixed support, there are three reactions available viz. 2 translation and 1 rotational. Thus, the degree of freedom is zero.
For hinge support, there are two reactions available viz. both translation and there is not rotation allowed. Thus the degree of freedom is 1(i.e. 1 rotation).
For roller support, there is only one reaction normal to the surface over which the roller rests reactions. Thus, the degree of freedom is 2(i.e. 1 rotation and 1 translation).
For an internal hinge, there are 4 degrees of freedom available(i.e 2 translations and 2 rotations).
For a 2 dimension rigid joint or free end, the number degree of freedom at a joint is 3 (one rotation
and 2 translations).
CAD means considering axial deformation.
NAD means neglecting axial deformation.
For calculating the Degree of kinematic indeterminacy by considering axial deformation by using the degrees of freedom, then first observe the entire structure and then add the degrees of freedom depending upon the constraints in the structure(viz. fixed support, hinge support, roller support, rigid joint or any internal hinge).
For example, if a beam has one fixed support, one internal roller and hinge support, and an overhang over the hinge, then the Degree of kinematic indeterminacy by considering axial
deformation by using the degrees of freedom is DIK=0(fixed support) + 2(roller) + 1(hinge) + 3(overhang= free end) = 6.
For calculating the Degree of kinematic indeterminacy by neglecting axial deformation(NAD) is DIK(NAD) = DIK(CAD)-number of members in the structure.
In the above example of the beam, there are three members viz first from the fixed support to the internal roller, second from the internal roller to the hinge support and the third is the overhang. Thus, the DIK(NAD)=6-3=3.
The formula for calculating the Degree of kinematic indeterminacy by considering axial deformation is DIK=3*J-R+I.
Here, J=number of joints in the structure including any internal hinge.
R= number of reactions actually acting on the structure.
I= number of internal hinges.
There is no such formula as what Mr. Ganesh had mentioned in the above video for calculating the degree of freedom by neglecting axial deformation(NAD.
You may be correct. But there are some question asked in the gate and ese. Which is accurate with this formula.
Excellently explained all concepts 👍👍
Bhai bahut badiyaa main nepal se huh...
Very good teaching
If internal hinge is supported by 3 members in that case no.of moments are exists.
Thanks to give easy tricks
Sir why you have not considered free end as a joint ?
Tq Sir continue your videos
Awsome trick sir
Sir 3 beams wale problem mein dk=5 hoga not 6 because at join only 1 rotation will be there if axial deformation is neglected but you have consider 2( vertical displacement and rotation).final answer is dk=1+1+3(i.e., at hinge , at joint, at internal hinge)
If i am correct please reply anyone
@@sgulnar4681 yes I've got the same answer...............and have the same confusion.
Thank you so much sir jee
10:36 it is a frame.
So nk= 3j- r- m +A
nk=4
bro Degree of freedom to nehin ayega axially rigid hoga to but reaction kyun neglect kar rahe ho?
thanks bro :)
Check the Playlist of SA-2 For More Videos ( Link in the Description Box )
One joint - 3 DOF
Thank you sir
Sir when we have to use 2j-r+A and 3j-r+A if only Dk find out karnr bola to?
Use 3j ! If it is asked axial def neglected or beams are inextensible only then use 2j
19.:50 vertical kaise ayega, sirf rotation ayega na horizontal aur vertical ko fired hai
same
Sir in a question it is given that beam is subjected to transverse loading is there a need to neglect axial deformation or not for static indeterminacy and kinetic indeterminacy
pls reply sir
If one end is free then how to solve it??
Bhai degree of freedom (axially) ko neglect karna hai na . Lekin hamne toh reaction ko neglect kar diya.
Confusion dur karo bhai.
Ya fir questions me degree of freedom axially ko neglect karne bola to axially REACTION bhi automatically neglect hota hai kya ?
Sir internal hinge joint pe ata h kya
Haa.. internal Hing should be considered as joint while Calculating Total no. Of Joints ( J )
@@GaneshShegar sir static interminancy me internal hinge ko joint consider Ni krte Kya??
❤❤❤❤❤
Sir koi esko 3J-R-m se bhi solve krte hai wo sahi hai kya
Just formula is enough
Kya karwaya ..pura confused kar diya ..
Clear samjh nhi aaya
Sir wrong hai....
Confusing
Answer wrong ho rahe hai sir
You might be doing wrong, Plz re check
App 2*3-3+1=4 aa raha hai....which is right
Seems to be wrong
Thank you sir