Critical Buckling Load (Example 1) - Mechanics of Materials

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  • เผยแพร่เมื่อ 19 ธ.ค. 2024

ความคิดเห็น • 107

  • @amiruperera829
    @amiruperera829 2 ปีที่แล้ว +3

    just amazing the way u drop them so clearly into our heads.

  • @Drewsky-A
    @Drewsky-A 6 ปีที่แล้ว +30

    you teach in 5 to 15 minutes that which my professors couldn't get through in 5 to 15 lectures

  • @elextwo2190
    @elextwo2190 7 ปีที่แล้ว +2

    Brother, I've searched the 7 seas for an explaination on this topic !! Thanks heaps man. Your a stallion among mules.

  • @RizkyYozia
    @RizkyYozia 4 ปีที่แล้ว +1

    Clearest explanation so far. I don't know you but u save my life, thank you so much.

    • @structurefree
      @structurefree  4 ปีที่แล้ว

      structure fuh-reezy makes life easy!

  • @unapologeticallyafrikan3906
    @unapologeticallyafrikan3906 7 ปีที่แล้ว +1

    You are just best at transferring your knowledge to others. Keep up the good work. I really enjoyed this.

  • @joannanicholson2540
    @joannanicholson2540 10 ปีที่แล้ว +4

    You are a genius. Given me back 10 hours of my life. Halle-freaking-llujah.

  • @dareoism
    @dareoism 10 ปีที่แล้ว +30

    If only my lecturer was as interesting as you......

  • @MadJDMTurboBoost
    @MadJDMTurboBoost 7 ปีที่แล้ว +5

    5:10 A pin only rotates on one axis, doesn't that mean that in this case the k value for x is 0.5 (fixed-fixed)?

  • @x9rtu3os1t8
    @x9rtu3os1t8 4 ปีที่แล้ว +1

    Omg its such a nice memory !!! Thank you A Lot , Keep it going !! Anyway wishing u the BEST.

  • @Exorcisto1
    @Exorcisto1 11 ปีที่แล้ว +4

    What I understood is :
    - We use Euler formula when the Buckling stress is less than or equal to the Yielding stress and this case applies for long columns only [ high slenderness ratio ( Kl/r ) ]. In reality we might use intermediate or short columns so for the intermediate and short columns we use Tables based on empirical equations to find the Allowable Buckling Load by comparing it with the value of
    ( Kl/r ) of the column under study.
    - The moment of Inertia with respect to x-x was (Ix) less than (Iy) , the x-x axis is called the weak axis and the y-y axis is called the strong axis so logically the buckling failure starts from the weak axis , in practice the use Bracing in the side of the weak axis to strengthen it and minimize Buckling effect.

  • @chikas4811
    @chikas4811 10 ปีที่แล้ว +1

    This is such a great video. Thanks for your clear explanation!

  • @saeedsnne
    @saeedsnne 10 ปีที่แล้ว +2

    You sir, are beast. Thanks for the upload. Great help

  • @mashudurathogwa701
    @mashudurathogwa701 8 ปีที่แล้ว +6

    You make learning really fun :'' '')

  • @structurefree
    @structurefree  11 ปีที่แล้ว

    are you referring to the effective length factor, K, or a buckling factor of safety?

  • @peiying0718
    @peiying0718 3 ปีที่แล้ว

    Thank you for the clear steps ❤️❤️

  • @WHY70122
    @WHY70122 5 ปีที่แล้ว +1

    Here I am again watching you vids for the PE four years after. I was asking myself the same question: why not use P= pi^2 EA/ (Kl/r)^2 . Scroll down the comment section only to find out I asked the same questions four years ago. LOL.

    • @structurefree
      @structurefree  5 ปีที่แล้ว

      Welcome back!!! Mechanics never gets old. Good luck on your PE exam!

  • @Zaidkarajeh
    @Zaidkarajeh 9 ปีที่แล้ว +1

    I am working on a project where I have to design a wheel using spokes. I am cross referencing a previous design and for some odd reason the spokes are curved toward the bottom. How would I calculate the Pcr of a curved spoke? Thanks!

  • @Souliee
    @Souliee 11 ปีที่แล้ว

    Yes, the Euler cases requires a ideal column. Imperferctions are usally included in the partial coefficients.

  • @tomrose4560
    @tomrose4560 11 ปีที่แล้ว +1

    Do you have any videos on how to calculate the buckling factor for a frame?

  • @NowayJose1993
    @NowayJose1993 5 ปีที่แล้ว +1

    Dude your the real MVP!

  • @فتحوجيهالدين
    @فتحوجيهالدين 5 ปีที่แล้ว +1

    Thank you so much for helping us.
    You are great.
    Allah bless you.

  • @0Sebek0
    @0Sebek0 11 ปีที่แล้ว +1

    Thank you, does buckling happen even if the column remains perfectly stable?, I mean with no initial bending or excentricity of the load

  • @MichaelWilson-xc1uk
    @MichaelWilson-xc1uk 10 ปีที่แล้ว +1

    Dear structure free
    Very interesting talk.
    Can you use this mathematics to determine the buckle point in any given stock or the s&p 500 or the DJIA? If you look at the 2008 GFC, 1987 selloff or the 1929 crash would this buckle point appear in the mathematics do you think?
    Any kind thoughts appreciated.

    • @structurefree
      @structurefree  10 ปีที่แล้ว +1

      That's an interesting question. I know that people use differential equations to try and model the market and there is the discipline of mathematical finance. I'm more of a buy and hold investor. If I could predict the future.....hmmmmmm....ballin.

  • @nzuzomal4545
    @nzuzomal4545 9 ปีที่แล้ว +1

    Thanks for this example it was great but how come when I use the formula in regards to Length Pcr= [(pi)^2.E.I]/(KL)^2 I get a completely different answer, and in which case should I use which formula ? I'm mainly confused because the two formulas are so similar and I'm not sure when I'd need the other one

    • @structurefree
      @structurefree  9 ปีที่แล้ว

      Not sure where you are going wrong. You should get the same answer either way. Hmmmmmm.

    • @andromeda45
      @andromeda45 8 ปีที่แล้ว

      +structurefree I think we should have choose the minimum of the slenderness ratios,not the maximum..

    • @adityagarg190
      @adityagarg190 8 ปีที่แล้ว +2

      If you substitute r for sqrt(I/A) in the second formula and solve, you end up exactly with the first formula. The reason you use r is to determine which plane of axis the buckling is going to occur in, if your cross section is something simpler (like a circle) then you can just use the first one. (I know you've probably long passed this course, but hopefully someone else finds this helpful).

    • @animasaurus2007
      @animasaurus2007 8 ปีที่แล้ว

      Thanks a lot mate, I was just getting confused about the same thing!
      Awesome of you to answer!

  • @TheBlue312
    @TheBlue312 6 ปีที่แล้ว +1

    I got a question: Why is Ix and Iy over 12 instead of 3? I know that if you use parallel axis theorem then its over 12 but you add A(dy)^2/A(dx)^2.

  • @Rockstar1376
    @Rockstar1376 9 ปีที่แล้ว +3

    Helped me a lot, thanks!

  • @SampleroftheMultiverse
    @SampleroftheMultiverse 10 ปีที่แล้ว +1

    I have been studying an effect that I observed many years ago in my teens. In the last few year I have learn about Euler’s column and contain column studies. I think my observation is a variation of his contained column theory. Is my variation well known and studied? As of late, it’s starting to look like a good model of the particle in a box problem. Maybe I am just trying to read too much into it but it has some interesting proprieties that I think people in the know should look at.

    • @SampleroftheMultiverse
      @SampleroftheMultiverse 4 ปีที่แล้ว

      th-cam.com/video/wrBsqiE0vG4/w-d-xo.html the engineer test video is not as exciting as yours but I hope you find in interesting. Hope you will try the effect and or comment on it. I think it rate as a variation of Euler’s contain column work. Yes-no maybe?

  • @loganrooks4957
    @loganrooks4957 9 ปีที่แล้ว +1

    Do you have any videos on web shear and flexural buckling for box girders? Also, I'm not sure if you are Canadian or not but I am from the University of Toronto and our civ102 professor (Michael Collins) derived equations for shear cracking in reinforced concrete which are used by our provincial and federal code for concrete structures (and I think he recently managed to get it adopted by the Americans due to its improved accuracy over the ones currently used) and I was wondering if you could do a few videos on those ones.

    • @structurefree
      @structurefree  9 ปีที่แล้ว

      +Logan Rooks i do not. looks like you may want to read some research articles and dissertations to figure out how to use those equations.

  • @carultch
    @carultch 9 ปีที่แล้ว +1

    If you calculate that a column will both yield and buckle at the same applied load, does it have the ultimate capacity to carry that load?
    And if not, how do you calculate the ultimate capacity of an intermediate column? A column which has a yield strength and an ultimate strength in the same vicinity.
    Are buckling and yielding both independent failure modes for a column?
    Or in the event of an intermediate column, does a combined failure mode occur?

    • @structurefree
      @structurefree  9 ปีที่แล้ว +1

      +carultch the euler buckling equation has a lot of assumptions built into it (linear elastic material, no crookedness, etc.) unless the column is more like a pedestal (really really small slenderness ratio), it will buckle first. There is also inelastic buckling behavior which typically occurs as you decrease slenderness ratio and that topic is typically covered in a second course in mechanics or an introductory design course.

  • @rahulroyale001
    @rahulroyale001 8 ปีที่แล้ว +1

    thank you for this nice explanation! can you please upload pics or pdf along with videos that will help us a lot.

  • @kianakm1226
    @kianakm1226 4 ปีที่แล้ว +1

    OMG. You are so great
    Thanks.

  • @x9rtu3os1t8
    @x9rtu3os1t8 9 ปีที่แล้ว +1

    can someone refer me to this course videos /examples/anything?
    please?hello?
    thanks.

  • @arifwicaksana1957
    @arifwicaksana1957 6 ปีที่แล้ว +1

    very helpful man, thanks a lot !. you fucking save my semester man

  • @demonhive1o1
    @demonhive1o1 8 ปีที่แล้ว +2

    hi first of I gotta say I'm loving the video. I just wanted to ask a weird question... how can the beam be pinned in both the x-x plane and the y-y plane lol nothing major, it made for an easier example. for that to be true it would have to be on a ball joint or something right?

    • @structurefree
      @structurefree  8 ปีที่แล้ว

      +demonhive1o1 thanks. You are right, it would have to be a ball joint to truly be pinned about both axes.

  • @stillzbreh
    @stillzbreh 8 ปีที่แล้ว +3

    yoooo! could you organize your videos into a playlist that builds on concepts from the last video? p.s. best videos online for strengths by far

  • @sinakontshiqa8172
    @sinakontshiqa8172 9 ปีที่แล้ว +1

    is it fair for an industrial engineering student who is doing internship to calculate bucklings loads??

    • @carultch
      @carultch 9 ปีที่แล้ว

      Sinako Ntshiqa What do you mean by "fair"?

  • @arestes
    @arestes 4 ปีที่แล้ว

    Hi! Thanks for this clear explanation. Just a question: for an arbitrary shape of the cross section, how should I compute the radius of gyration? with respect to centroidal axes only (and then find the maximum of KL/r? Is mohr's circle necessary here to find the minimum moment of inertia (but that would mean that K would change... I'm confused).

  • @noel_tk
    @noel_tk 8 ปีที่แล้ว +1

    Thank you for your videos! Can we have a Castigliano's Theorem explanation and example please? Really confusing

  • @natemargolis8956
    @natemargolis8956 8 ปีที่แล้ว

    I have a quick question on the moment of inertia. Where does the (1/12) come into play and do you have any videos explaining the moment of inertia? I've watched some but don't really understand how to calculate it

    • @Randomkloud
      @Randomkloud 3 ปีที่แล้ว

      probably too late to help you but for other people, moment of inertia is a geometric property meaning it is only related to the dimensions of the object. you can obtain it by integrating the (distance squared from the neutral axis) of every point on the plane. Think of it like finding the area under a graph, we know that we have to integrate the function within a certain range (definite integration). That is wat is happening under the hood. But if you have a graph of a very simple equation, say y = 1 , you would simply have a straight line and the area under it would just be a rectangle whose area you can determine by just (base, which is any range of x values) x (height, in this case 1) .
      Likewise, for area moment of inertia you have formulae for a lot of simple shapes , for a rectangular cross section it would be (base x height)/12 .The 1/12 came from when we performed the definite integration of the (distance squared from the neutral axis) of every point on the plane.

  • @aftabnabi1507
    @aftabnabi1507 5 ปีที่แล้ว

    Sir which moment of area will be used min. Or max.

  • @carolinamendez1053
    @carolinamendez1053 ปีที่แล้ว

    I need clarification Please: I keep seeing that the critical buckling formula does not include a radius of gyration only the critical stress formula. Why is the radius of gyration used here in the critical buckling formula?

    • @structurefree
      @structurefree  ปีที่แล้ว

      The radius of gyration is directly related to the moment of inertia. You can use either definition.

  • @abdomohsen6204
    @abdomohsen6204 4 ปีที่แล้ว

    What ,s equation to calculate buckling factor?

  • @pedjal.7456
    @pedjal.7456 7 ปีที่แล้ว

    hi,
    what are you using to capture handwriting in your videos-iPad?
    thanks

  • @jamilladambo
    @jamilladambo 7 ปีที่แล้ว

    Why do we have a moment of inertia about both axis?

  • @TheHeartsDuff
    @TheHeartsDuff 10 ปีที่แล้ว +1

    why is the buckling 0.7xL?

    • @TheHeartsDuff
      @TheHeartsDuff 10 ปีที่แล้ว

      but why

    • @structurefree
      @structurefree  10 ปีที่แล้ว

      TheHeartsDuff see the comment by stuart doyly...it's pretty good.

    • @carultch
      @carultch 9 ปีที่แล้ว

      TheHeartsDuff 0.7 is approximately equal to half of the square root of two. In fact, the k-factor for this condition is supposed to be sqrt(2)/2.
      In the condition of fixed-pinned, draw the shape that the buckling takes, and construct the sine wave shape that can meet the fixed bottom and pinned top. You will see that in order to get a vertical tangent at the bottom, while the top is free to be oriented in any direction, the way to do this is to reduce the "wavelength" of the sine curve by a factor of sqrt(2)/2 from a pinned-pinned buckling shape.

  • @cschow2438
    @cschow2438 7 ปีที่แล้ว +1

    Hi Structurefree,
    Thank you for your videos, they are awesome. Keep it up!
    But i have one question about this video. I know that the yield stress is given, but is there anyway to calculate it? or it is so a material property which is found out empirically?
    Cheers
    Sam

  • @salwan6153
    @salwan6153 11 ปีที่แล้ว

    hello... i have been waiting for your new video!!! I have a request if you may allow me ,pleas do some videos in R C designing .. i mean take a small project like two story building and show us how to design the members all together ...i woul appreciat that ... thank you so much...

  • @haseeburrahman321
    @haseeburrahman321 6 ปีที่แล้ว

    Excuse me sir what does (1000mm/m) means? In step # 3

  • @nicholelonyon4303
    @nicholelonyon4303 3 ปีที่แล้ว +1

    What if you don't know the Length value ?

    • @structurefree
      @structurefree  3 ปีที่แล้ว

      The column length and cross section properties are important to calculating the buckling load.

  • @ozoozo3301
    @ozoozo3301 10 ปีที่แล้ว +2

    I LOVE Structurefree!!

  • @WHY70122
    @WHY70122 10 ปีที่แล้ว +1

    I don't understand why you would have to use the variation of the Euler's equation to solve this problem. Demonstration purposes? The P = pi^2EI/(KL)^2 is much easier and quicker to use.

    • @structurefree
      @structurefree  10 ปีที่แล้ว +6

      WHY70122 It really doesn't matter either way. I personally like to use the slenderness ratio (KL/r) since it is a dimensionless measure of slenderness for a given member. It makes it convenient to compare column members, also the AISC manual uses the slenderness ratio in its tables and in the specifications and provides values for the radius of gyration in the cross-section properties table.

  • @x9rtu3os1t8
    @x9rtu3os1t8 9 ปีที่แล้ว +1

    dear sir brother do you have some examples with (springs K) too??
    oh yeah i love you!!

  • @ahmadsayah8073
    @ahmadsayah8073 8 ปีที่แล้ว +1

    i got exam on this tomorrow, hope me the best

  • @Souliee
    @Souliee 11 ปีที่แล้ว +1

    Woho! A new video! Been waiting for this. :D

  • @MosesvandenBerg
    @MosesvandenBerg 7 ปีที่แล้ว +1

    You are a LEGEND!

  • @MominahG
    @MominahG 2 ปีที่แล้ว

    Sir I think that your KL/r max value is wrong i calculate it is 14.5 and 3.63 if im wrong then please sir Guide me

  • @YesHerself
    @YesHerself 8 ปีที่แล้ว

    hi, can you do an example of buckling in 3D?

    • @structurefree
      @structurefree  8 ปีที่แล้ว

      +teynerdy do you mean buckling in about both axes of a column? Technically all buckling calcs consider both axes of buckling.

    • @structurefree
      @structurefree  8 ปีที่แล้ว

      +teynerdy do you mean buckling in about both axes of a column? Technically all buckling calcs consider both axes of buckling.

    • @YesHerself
      @YesHerself 8 ปีที่แล้ว

      no, i mean buckling in the xy, xz and yz planes.

  • @muazbaharin2964
    @muazbaharin2964 4 ปีที่แล้ว

    guys why the K is 0.7L? is that value is fixed?

  • @coolstuff8857
    @coolstuff8857 10 ปีที่แล้ว +1

    haha thanks for a good tutorial :) You're very funny btw

  • @user-in6fy4oy3y
    @user-in6fy4oy3y 3 ปีที่แล้ว +1

    I'm in third year architecture and my structures prof stole screenshots from this video to use as his entire tutorial lol

    • @structurefree
      @structurefree  3 ปีที่แล้ว

      Ha, ha, ha! Did he/she at least give a shout out? Structure chika-chika freeeee!

  • @almasrey66
    @almasrey66 9 ปีที่แล้ว +1

    u the best pro..

  • @kaganakin4477
    @kaganakin4477 7 ปีที่แล้ว +1

    good job

  • @TheBeatnikAndrew
    @TheBeatnikAndrew 10 ปีที่แล้ว +1

    Helpful video, but dear god, why do all math/science explanation/tutorial videos have the WORST audio/microphones used of all videos on TH-cam?

    • @structurefree
      @structurefree  10 ปีที่แล้ว +5

      I thought the sound was good on this one. What kind of microphone would you recommend?

    • @TheBeatnikAndrew
      @TheBeatnikAndrew 10 ปีที่แล้ว +1

      Haha, It doesn't bother me if it doesn't bother you :) As for a microphone I'm not sure, just one that doesn't pick up on so much of the "p-uh" and breath-y sounds. Again, thanks for the helpful video!

  • @abuamar5557
    @abuamar5557 8 ปีที่แล้ว +28

    In your face 😂

  • @yakupaktas1222
    @yakupaktas1222 8 ปีที่แล้ว +1

    WHATS K ?

    • @Tee.NZ.07
      @Tee.NZ.07 8 ปีที่แล้ว +1

      length of the bow-curved deflection of the column (under load) depending on the end conditions..i.e. pinned-pinned k= 1,fixed-fixed k=.5, fixed-free k=2, fixed-pinned k = .7 (depending what book u read). kL is termed the equivalent length....

  • @yeiown1
    @yeiown1 7 ปีที่แล้ว

    man i fucking love you..

  • @Ray4Fun
    @Ray4Fun 10 ปีที่แล้ว +7

    sucker ~~~~

  • @simphiwemalinga5869
    @simphiwemalinga5869 6 ปีที่แล้ว

    Thank you

  • @mechporn
    @mechporn 10 ปีที่แล้ว +1

    love it :)

  • @mohamedakl9159
    @mohamedakl9159 10 ปีที่แล้ว

    why 0.7
    ?????????????

    • @stuartdoyly7798
      @stuartdoyly7798 10 ปีที่แล้ว +4

      Its a little complicated to explain with out a diagram but its the deflected shape that particular support configuration forms when load is applies compared with the standard configuration the Pinned-pinned support or k=1.0. The k=0.7 basically means that that proportion of L acts like the standard Pinned-Pinned support. This is known as its effective length factor. Since the formula used is derived from the pinned-pinned support the beam has to act the same way.
      here's a list of common k values:
      Pinned-Pinned = 1.0
      Fixed-Pinned = 0.7
      Fixed-Fixed = 0.5
      Fix-Free = 2.0

  • @azharhajdarevic2888
    @azharhajdarevic2888 4 ปีที่แล้ว

    Elastostatika MEF 2020

  • @robertaquino6274
    @robertaquino6274 8 ปีที่แล้ว +3

    ahy peroque facill jajajsal2

    • @structurefree
      @structurefree  8 ปีที่แล้ว +2

      bienvenido, estructura libre!!!

  • @IlliamAmiill
    @IlliamAmiill 11 ปีที่แล้ว

    hey dude, ive been looking through your impressive vids for some way of calculating the dispersion of a force through a shaped wheel. if you have a moment look through
    ://scratch.mit.edu/projects/10186511/
    inside the script, costume 2 of the core structure sprite
    or just play and click on the core to see the math in the background and click on that math to see the picture. any help is appreciated :D

  • @velidenizkarabacak
    @velidenizkarabacak 7 ปีที่แล้ว +1

    structurefreeee! 😂😂

  • @MsCaliforniaOne
    @MsCaliforniaOne 10 ปีที่แล้ว

    WTF? Time to watch the Kardashians.