Step-by-Step Proof 🔥🔺 Perpendicular bisectors of a triangle are concurrent (meet at same point)

Welcome to our educational channel #mathemafia. In this video, we will prove a fundamental theorem of geometry:
Perpendicular Bisectors of a Triangle are Concurrent (meet at the same point called circumcenter).
What is the Perpendicular Bisector Concurrency Theorem?
This theorem states that when you draw the perpendicular bisectors of the three sides of a triangle, they all intersect at a single point known as the *circumcenter*.
Why This Video Is Important:
This theorem is a very important theorem of geometry (triangles). The result of this theorem is the basis of many more theorems of geometry. Hence it is recommended to every student, teacher and scholar who wants to dive deep in the field of *Geometry*.
What You Can Expect:
Intuitive Visuals: We have used clear, visual representations (colourful triangles and animations) that help you visualise and understand the proof with utmost clarity. Double coloured (red and black) stylus has been used to visually segregate the different parts of the proof.
Step-by-Step Guidance: This video tutorial includes a very detailed explanation of the theorem with all parts explained and solved separately.
Interactive Learning: Feel free to increase or decrease the pace of the video that suits to your style of learning. It is always recommended to pause the video in between to grasp the concept whenever you feel it bit heavy.
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#Mathematics
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#Circumcenter
#ConcurrencyTheorem
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#MathematicalTheorems
#PerpendicularBisectors
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Chapters:
00:00 About this theorem
01:14 Point of intersection (O) of two perpendicular bisectors is equidistant from all vertices
08:38 Proving line joining the mid point of third side and point O is perpendicular bisector
11:57 Conclusion
12:36 Circumcenter - Why circle passes though all vertices

[@krishsolanki5430]

Sir can you explain ✓x² is |x| and when to consider negative I'm really confused with this

[@Mathemafia]

Remind me next week.
I am restarting video creation.

[@krishsolanki5430]

@@Mathemafia Certainly sir...Thanks♥️

[@krishsolanki5430]

@@Mathemafia Sir u told me to remind
...

[@Mathemafia]

@@krishsolanki5430 Thanks Krish. I have already prepared the slides and will try to create tutorial on Monday. Hopefully by Tuesday you will get it.

[@Mathemafia]

Hi Krish I created the video but I am not happy with the final output. So I will explain it in written. The square root of a non negative real number always return a positive value. So square is always positive (or zero) for any real number, hence its square root will be positive (or zero) as well. On the other hand |x| also restuns the positive value. So for real numbers, they are always same. But not for the complex numbers.

[@MukeshKumar-kw4si]

Gud morng Sir..Sir aapne Class 9th ka Chapter 9 Area of Parallelogram and Triangles nahi karwaya h plz wo krwa do pura Chapter jo Old book m h..please🙏

[@Mathemafia]

Wo to ab syllabus mein hi nahin hai. Why do you want it?

[@MukeshKumar-kw4si]

@@Mathemafia Hamare yhan syllabus change ni hua h wo hi h..maximuk jagah syllabus change ni hua h..bs CBSE board ni kiya h...hmare yhan state board h or wo syllabus change ni krta..jab tak NEP2020 puri tarah lagu ni ho jati..jo ki next year s hogi.

[@Mathemafia]

Ohk. But meri taraf se to abhi isko banana mushkil hai. Aap please mere videos ki wait mat karna.

[@manat666]

HI SIR

[@Mathemafia]

Hello

[@manat666]

@@Mathemafia SIR HAVE U UPLOADED 6TH CHAPTER????

[@Mathemafia]

@@manat666 which class? Tell me name of the chapter.

[@Mathemafia]

@@manat666
Class 9, Chapter 6 - th-cam.com/play/PLHipvIKLGDdelntjtyMcfX2ITpPb-tpJb.html
Class 10, Chapter 6 - th-cam.com/play/PLHipvIKLGDdcSb1wTeRER46Rhdq8jkzcD.html

[@Mathemafia]

@@manat666 You can also visit www.mathemafia.com to search and watch any class 9, 10 chapter.

[@samarkhan5295]

Sir aap ke digital board hai toh aap old maths 😊😊😊😊 video ko board per solve ker doo