You are wrong. Final velocity is 0 and initial velocity is 60m/s. Because when the ball is kicked it's 60m/s and then it becomes 0 when it reaches the goal
Glass material are packed in a bubble wrappers whenever there is a jerk or external force they increases the time of collision and hence reduces the force imparted on glass material
Initial velocity (u) of the ball = 0 m/s. Final velocity (v) if the ball = 210 km / sec = 58.33 m/s. And the mass (m) of the ball = 400g = 0.4kg 》》Therefore, IMPULSE (I) = MV - MU (I) = (0.4)(58.33) - (0.4)(0) (I) = 23.33 kg m/s
Speed of B = 210K/h = 210000/3600= 58.3 m/s .... Initial velocity Final velocity= 60m/s Mass of the B = 400g = 0.4 From the formula Impluse= mv- mu 0.4×58.3 - 0.4×60 23.32- 24 = -7/10 nm
i think that if you take ball at rest as reference point then the impulse is 24 kg m/s (if it was paneity ) , but if you take goal as a reference point then the impulse is 0kg m/s
For constant acceleration "a" & V=½(u+v): F∆t~ma·|∆x|/V~(∆K/V)F^ ~Work done per av. speed V, in direction of applied force. ~(½m∆v²/ ½(u+v))F^=m∆v. So, in theory, you could measure the transfer of energy to the wall and this will help you work out the impulse, as long as you know the average speed of the collision.
I am in grade 9th but still I understood each and every concepts and solutions of this video because of your easy explanation. Thanks sir ❤ Answer of that question is -24kg.m/s
Bro the Impulse on the football is 24 kgm/s. This Is because there's no rebound on the football and hence all the values are positive. Anyways, awesome try 👍
Sir! Ball applied 2×0.1= 0.2 kgm/S, moment, and as a reaction wall applied 0.4 kgm/S, momentum, How?? But according to Newton, 3rd Law action and reaction are equal. 2nd Question is that, what's physical meaning of 0.2kgm/S momentum???? Please! Reply, I will be waiting for your reply! Thanks!
The impulse of wall on the ball .Direction of ball is changed that's why velocity chanced . Impulse=∆p =m(v-u) , we take mass as common. =m(-v-u) ,here v is negative And we know that . m(-2-2)=m(-4) I hope you will understand
The answer is 24 kgm/s Solution : Change in momentum = mass * velocity Mass = 400g Velocity= 60 m/s Change gram into kilogram, As kilogram is a SI Unit 400 divided by 1000 = 0.4 kilogram = 0.4*60 =24 kgm/s
sir do u only explain for CBSE class 11 students or even to state syllabus of class 11 and sir pls explain the electricity lesson for class 10 cbse all the difficult sum how to solve them pls sir
#include int main() { // Define constants const double kmph_to_mps = 1.0 / 3.6; // Conversion factor from km/h to m/s // Declare variables double speed_kmph; double mass_kg; // Get user input for speed and mass std::cout > speed_kmph; std::cout > mass_kg; // Convert speed to meters per second double speed_mps = speed_kmph * kmph_to_mps; // Calculate impulse double impulse = mass_kg * speed_mps; // Output the results std::cout
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Final Velocity = 210km/h
= 60m/s.
Initial Velocity = 0 m/s.
Mass of the ball = 400g = 0.4 kg.
Impulse = change in momentum
= MV -- mu
= M(V -- u)
= 0.4(60 -- 0)
= 0.4 × 60 =} 24kgm/s *Ans*
Well bro❤
Well done
Ok thank u
😅😅😅😅
You are wrong. Final velocity is 0 and initial velocity is 60m/s. Because when the ball is kicked it's 60m/s and then it becomes 0 when it reaches the goal
You make Concepts Super Duper Easy! 🥳
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th-cam.com/video/H1tF7a_HXVg/w-d-xo.htmlsi=zPqRxxr72EUGPtpj
Glass material are packed in a bubble wrappers whenever there is a jerk or external force they increases the time of collision and hence reduces the force imparted on glass material
Best videos for A level physics which is hard... concept cleared
Impulse will be change in momentum.
So, Impulse=m(v-u)
=4/10(0-60)
4/10×-60
-24kgm/s.
Why-. It will be +24
coz ball is moving forward in the direction of given force so +24
0 is the initial velocity coz the ball was at rest before it was kicked
0:32
u = 0 m/s, v = 60 m/s
mu = 0.4 kg x 0 = 0kgm/s and mv = 0.4kg x 60m/s = 24kgm/s
impulse = change in momentum = (24 - 0) Ns = 24 Ns
Initial velocity (u) of the ball = 0 m/s.
Final velocity (v) if the ball = 210 km / sec = 58.33 m/s.
And the mass (m) of the ball = 400g = 0.4kg
》》Therefore, IMPULSE (I) = MV - MU
(I) = (0.4)(58.33) - (0.4)(0)
(I) = 23.33 kg m/s
You're videos are amazing, and you even try to respond to every comment 🤯
Thanks
Speed of B = 210K/h = 210000/3600= 58.3 m/s .... Initial velocity
Final velocity= 60m/s
Mass of the B = 400g = 0.4
From the formula
Impluse= mv- mu
0.4×58.3 - 0.4×60
23.32- 24
= -7/10 nm
initial velocity will be 0 coz ball is in rest
I = ∆momentum
=mv - mu
= m(v-u)
= 0.4(60-0)
= 24 Kgm/s or Ns ❤
Sir you are best teacher I ever seen 🎉
Many many thanks!
Outstanding way of teaching
i think that if you take ball at rest as reference point then the impulse is 24 kg m/s (if it was paneity ) , but if you take goal as a reference point then the impulse is 0kg m/s
Akshay Kumar left acting and started teaching physics😂
And he's really doing very well at teaching.
Ha ha :)
Ronny Heberson
Football lovers
Rooney Haberson
Football lovers
😂😂😂😂 can you leave our teacher alone
Wow this man teaches so great much love from Nigeria sir , thank you
G
For constant acceleration "a" & V=½(u+v):
F∆t~ma·|∆x|/V~(∆K/V)F^
~Work done per av. speed V, in direction of applied force. ~(½m∆v²/ ½(u+v))F^=m∆v.
So, in theory, you could measure the transfer of energy to the wall and this will help you work out the impulse, as long as you know the average speed of the collision.
Impulse=mv-mu
m=0.4kg
u=0m/s
v=-60m/s
•°• impulse=0.4{-60-(0)}
=0.4×(-60)
=-24kgm/s
Initial velocity = 0
Mass = 0.4 kg
Speed = 60m/s
So
Impulse = 0.4 *60
Which is 24 kg m/s
Impllulse = change in momentum
u=0gm-m/s^2
v = 400g × 60m/s
= 24000gm-m/s
=24kg-m/s
Impulsive force = 24-0
=24 kg-m/s
I am in grade 9th but still I understood each and every concepts and solutions of this video because of your easy explanation.
Thanks sir ❤
Answer of that question is -24kg.m/s
Bro I'm also in 9th and I knewed most of the thing and also understood everything
Bro the Impulse on the football is 24 kgm/s. This Is because there's no rebound on the football and hence all the values are positive. Anyways, awesome try 👍
Amazing 😍
From Nigeria
Sir! Ball applied 2×0.1= 0.2 kgm/S, moment, and as a reaction wall applied 0.4 kgm/S, momentum, How??
But according to Newton, 3rd Law action and reaction are equal.
2nd Question is that, what's physical meaning of 0.2kgm/S momentum????
Please! Reply, I will be waiting for your reply!
Thanks!
The impulse of wall on the ball .Direction of ball is changed that's why velocity chanced .
Impulse=∆p
=m(v-u) , we take mass as common.
=m(-v-u) ,here v is negative
And we know that . m(-2-2)=m(-4)
I hope you will understand
The answer is 24 kgm/s
Solution :
Change in momentum = mass * velocity
Mass = 400g
Velocity= 60 m/s
Change gram into kilogram, As kilogram is a SI Unit
400 divided by 1000 = 0.4 kilogram
= 0.4*60
=24 kgm/s
Thank you so much sir, your video really helped me understand the concept of impulse.
8:13 24 kg m/s
Super! Right answer!!
Your video is amazing sir
# first comment
Thank you so much 😀
Amazing vido from ethiopia kidanu
Thanks for liking
Impulse=change in momentum
I=mv-mu
I=m(v-u)
Given that
M=400g=0.4kg
V=210kmhr-¹
U=0ms-¹
I=m(v-u)
I=0.4(60-0)
I=24kgms-¹
Fantastic! Correct answer 👍
It's mind blowing, super explanation 🎉
Very helpful sir.
Thank you sir
For. This video
Most welcome
Dear Sir, please clean your teath , its very distracting.
Love ~ Shayan
Great sir ! I am your big fan
Wow ! Thanks
Thank you sir for your reply, could you tell me where did you learn English and what is your fluency secret
WOW! Such an amazing video!!
Thank you 😊
I wish if I can have you as my physics teacher! 😢
Great to hear that you like our videos!
sir do u only explain for CBSE class 11 students
or even to state syllabus of class 11
and sir pls explain the electricity lesson for class 10 cbse all the difficult sum how to solve them pls sir
Thank you sir
Welcome
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thank you very much sir!!!!!!!!
Most welcome!
- 24 kgm/s
The best teacher ever
Waw nice page and tutor❤❤❤❤
I like ur teaching, you make concepts super 👌
momentum = impact ? and impulse = change of momentum ?
An outstanding 🎉🎉 lecture!
Thanks for liking
I can't understand the last question can somebody clarify me please?
thank you sir, love your teachings
I love you teaching
PHYSICS CLASS 12TH LECTURE PLEASE FIR UPCOMING NEW BATCH
Please I want lecture for class 12th physics ISC please sir
Hindi chenal par videos Kyu nahi dalte hai sir please ush par bhi videos Dale
Impulse= 24 kg m/s
Interesting lesson sir.
Thankyou sir❤
Thanks meet you again sr.
The answer is -48 kg m/s❤❤
It is not a rebound. Initial velocity is 0. Try again you should get answer as 24 kg m/s
@ManochaAcademy oh yeah it's my fault thanks for the correction❤️❤️
Impulse(J)=M . Change in velocity J =400 . 0 J =0 ,therefore the impulse is 0 Kg/M.
24 kg m/s
24 kgms^-1
THANK YOU SIR
Ronny Heberson his impulse is 6kgm/s
|∆p| = |mv - mu|
= |0 - 24|
= 24 kgm/s
-24kgm/s
🎉🎉🎉
thankyou so much sir ❤️❤️❤️
48Ans
Sir Make 1chapter in 1shot ❤
Sir you can upload Gravitation chapter class 9 in Hindi Sir please don't ignore
Impulse is 24 Ns
❤
9:01 9:02 🍖😱
0.1×(-2-2) how sir
Ahh😢😢
24 kg.m/s is correct answer of footwall
#include
int main() {
// Define constants
const double kmph_to_mps = 1.0 / 3.6; // Conversion factor from km/h to m/s
// Declare variables
double speed_kmph;
double mass_kg;
// Get user input for speed and mass
std::cout > speed_kmph;
std::cout > mass_kg;
// Convert speed to meters per second
double speed_mps = speed_kmph * kmph_to_mps;
// Calculate impulse
double impulse = mass_kg * speed_mps;
// Output the results
std::cout
Hello It's Jeet
the momentum of the ball kicked by Ronny is 24kgm/s
Am from Pakistan ❤
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Pakistan k kaha se@@AsiyaUsman-y6o
Mai bhi Pakistan se hu isliye
Impulse of Ronny heberson kick is 240 kgm/s
It should be 24 kg m/s. Check your calculation.
Yes , it is my fault in calculation,
Impulse= 0.4×60-0
=24kg m/s
Impulse= MV
Where m= 400g which is equivalent to 0.4kg
Total velocity= 60m/s
So , impulse= MV
Impulse= 0.4*60
Impulse= 24kg m/s
-48
24kgm/s
Which class content
9 th
100 like😊
Thanks!
24kg ms-1
18th like❤
Thanks 👍
@@ManochaAcademy sir can u explain jee phy also
hi
Hi, thanks for watching!
1st like 1st comment 1st view
Super!
24km/s
I=24kgm/s
First
Thanks for watching so fast!
1/15KGM/S
24 Kg m/s
2400 kgm/s
24 kg.m/s
24 kg m/s.
-47.3m/s
show your working
Sir i am from Pakistan but i really like you and swear by Allah that i will share your videos and tell people about you . This is a Muslim and pathan promise
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Great❤🎉
😅
24Kg m/s
Ur homies
-24kgm/s is answer