You are wrong. Final velocity is 0 and initial velocity is 60m/s. Because when the ball is kicked it's 60m/s and then it becomes 0 when it reaches the goal
Glass material are packed in a bubble wrappers whenever there is a jerk or external force they increases the time of collision and hence reduces the force imparted on glass material
While teaching impulse using ball bounce example you said we can take any direction of motion of ball is positive and other as negative My question here is why we can take any direction as positive according to sign convention rule motion along right or upward side should be taken as positive and motion along left or downward side should be taken as negative please explain me
1st ball goes in upward direction with initial velocity of 2 ms means positive direction. 2nd ball comes in downward direction hence we take final velocity as negative.
The answer is 24 kgm/s Solution : Change in momentum = mass * velocity Mass = 400g Velocity= 60 m/s Change gram into kilogram, As kilogram is a SI Unit 400 divided by 1000 = 0.4 kilogram = 0.4*60 =24 kgm/s
Speed of B = 210K/h = 210000/3600= 58.3 m/s .... Initial velocity Final velocity= 60m/s Mass of the B = 400g = 0.4 From the formula Impluse= mv- mu 0.4×58.3 - 0.4×60 23.32- 24 = -7/10 nm
Final velocity=60m/s Initial velocity=0m/s Mass of ⚽ =200g Solution:; Impulse= change in momentum =Pf-pi =(60m/s×0.2kg)-(0m/s0.2kg) =0.2kg(60m/s. - 0m/s) =12kgm/s
For constant acceleration "a" & V=½(u+v): F∆t~ma·|∆x|/V~(∆K/V)F^ ~Work done per av. speed V, in direction of applied force. ~(½m∆v²/ ½(u+v))F^=m∆v. So, in theory, you could measure the transfer of energy to the wall and this will help you work out the impulse, as long as you know the average speed of the collision.
I am in grade 9th but still I understood each and every concepts and solutions of this video because of your easy explanation. Thanks sir ❤ Answer of that question is -24kg.m/s
Bro the Impulse on the football is 24 kgm/s. This Is because there's no rebound on the football and hence all the values are positive. Anyways, awesome try 👍
i think that if you take ball at rest as reference point then the impulse is 24 kg m/s (if it was paneity ) , but if you take goal as a reference point then the impulse is 0kg m/s
Sir! Ball applied 2×0.1= 0.2 kgm/S, moment, and as a reaction wall applied 0.4 kgm/S, momentum, How?? But according to Newton, 3rd Law action and reaction are equal. 2nd Question is that, what's physical meaning of 0.2kgm/S momentum???? Please! Reply, I will be waiting for your reply! Thanks!
The impulse of wall on the ball .Direction of ball is changed that's why velocity chanced . Impulse=∆p =m(v-u) , we take mass as common. =m(-v-u) ,here v is negative And we know that . m(-2-2)=m(-4) I hope you will understand
Initial velocity (u) of the ball = 0 m/s. Final velocity (v) if the ball = 210 km / sec = 58.33 m/s. And the mass (m) of the ball = 400g = 0.4kg 》》Therefore, IMPULSE (I) = MV - MU (I) = (0.4)(58.33) - (0.4)(0) (I) = 23.33 kg m/s
sir do u only explain for CBSE class 11 students or even to state syllabus of class 11 and sir pls explain the electricity lesson for class 10 cbse all the difficult sum how to solve them pls sir
![เปิดบ้าน นาราเครปกระเทย 1 ไร่ ขายขาดทุนหลัก10ล้าน เอามาใช้หนี้!!! l [Nickynachat]](http://i.ytimg.com/vi/0jz84VFWVP4/mqdefault.jpg)
For LIVE Classes, Concept Videos, Quizzes, Mock Tests & Revision Notes please see our Website/App
👉Our Website: bit.ly/2KBC0l1
👉Android App: bit.ly/3k48zdKManocha Academy
The impulse is -48kgm/s
Final Velocity = 210km/h
= 60m/s.
Initial Velocity = 0 m/s.
Mass of the ball = 400g = 0.4 kg.
Impulse = change in momentum
= MV -- mu
= M(V -- u)
= 0.4(60 -- 0)
= 0.4 × 60 =} 24kgm/s *Ans*
Well bro❤
Well done
Ok thank u
😅😅😅😅
You are wrong. Final velocity is 0 and initial velocity is 60m/s. Because when the ball is kicked it's 60m/s and then it becomes 0 when it reaches the goal
u = 0 m/s, v = 60 m/s
mu = 0.4 kg x 0 = 0kgm/s and mv = 0.4kg x 60m/s = 24kgm/s
impulse = change in momentum = (24 - 0) Ns = 24 Ns
You make Concepts Super Duper Easy! 🥳
Glad you like them!
Glass material are packed in a bubble wrappers whenever there is a jerk or external force they increases the time of collision and hence reduces the force imparted on glass material
While teaching impulse using ball bounce example you said we can take any direction of motion of ball is positive and other as negative
My question here is why we can take any direction as positive according to sign convention rule motion along right or upward side should be taken as positive and motion along left or downward side should be taken as negative please explain me
1st ball goes in upward direction with initial velocity of 2 ms means positive direction. 2nd ball comes in downward direction hence we take final velocity as negative.
Impulse will be change in momentum.
So, Impulse=m(v-u)
=4/10(0-60)
4/10×-60
-24kgm/s.
Why-. It will be +24
coz ball is moving forward in the direction of given force so +24
0 is the initial velocity coz the ball was at rest before it was kicked
0:32
The answer is 24 kgm/s
Solution :
Change in momentum = mass * velocity
Mass = 400g
Velocity= 60 m/s
Change gram into kilogram, As kilogram is a SI Unit
400 divided by 1000 = 0.4 kilogram
= 0.4*60
=24 kgm/s
Wow this man teaches so great much love from Nigeria sir , thank you
G
Speed of B = 210K/h = 210000/3600= 58.3 m/s .... Initial velocity
Final velocity= 60m/s
Mass of the B = 400g = 0.4
From the formula
Impluse= mv- mu
0.4×58.3 - 0.4×60
23.32- 24
= -7/10 nm
initial velocity will be 0 coz ball is in rest
Best videos for A level physics which is hard... concept cleared
Sir you are best teacher I ever seen 🎉
Many many thanks!
V=210km/s=60m/s
mass of foot ball=400 gram =400/1000=0.4
Impulse = mv-mu
Impulse= m(v-u)
Impulse= 0.4(60-0)
Impulse= 24kgm/s
The answer is not applicable as we don't know the final velocity may be it rebounded untill reached the other goal keeper.
Final velocity=60m/s
Initial velocity=0m/s
Mass of ⚽ =200g
Solution:;
Impulse= change in momentum
=Pf-pi
=(60m/s×0.2kg)-(0m/s0.2kg)
=0.2kg(60m/s. - 0m/s)
=12kgm/s
0.2 kg ❌
0.4 kg✅
Getting this teacher teaching live today is a great chance
I use to watch his teachings always
Thanks
th-cam.com/video/H1tF7a_HXVg/w-d-xo.htmlsi=zPqRxxr72EUGPtpj
U=0m/s V=60m/s Mass of the ball =0.4kg
M(v-u)
0.4kg (60-0)
0.4 x 60
24kgm/s.
For constant acceleration "a" & V=½(u+v):
F∆t~ma·|∆x|/V~(∆K/V)F^
~Work done per av. speed V, in direction of applied force. ~(½m∆v²/ ½(u+v))F^=m∆v.
So, in theory, you could measure the transfer of energy to the wall and this will help you work out the impulse, as long as you know the average speed of the collision.
Impllulse = change in momentum
u=0gm-m/s^2
v = 400g × 60m/s
= 24000gm-m/s
=24kg-m/s
Impulsive force = 24-0
=24 kg-m/s
practicality is his strategy. he makes a complicated concept simpler. Thanks chemistry tutor
Initial velocity = 0
Mass = 0.4 kg
Speed = 60m/s
So
Impulse = 0.4 *60
Which is 24 kg m/s
I am in grade 9th but still I understood each and every concepts and solutions of this video because of your easy explanation.
Thanks sir ❤
Answer of that question is -24kg.m/s
Bro I'm also in 9th and I knewed most of the thing and also understood everything
Bro the Impulse on the football is 24 kgm/s. This Is because there's no rebound on the football and hence all the values are positive. Anyways, awesome try 👍
Outstanding way of teaching
Impulse=mv-mu
m=0.4kg
u=0m/s
v=-60m/s
•°• impulse=0.4{-60-(0)}
=0.4×(-60)
=-24kgm/s
You explain things very well
i think that if you take ball at rest as reference point then the impulse is 24 kg m/s (if it was paneity ) , but if you take goal as a reference point then the impulse is 0kg m/s
Amazing vido from ethiopia kidanu
Thanks for liking
You're videos are amazing, and you even try to respond to every comment 🤯
Thanks
Sir! Ball applied 2×0.1= 0.2 kgm/S, moment, and as a reaction wall applied 0.4 kgm/S, momentum, How??
But according to Newton, 3rd Law action and reaction are equal.
2nd Question is that, what's physical meaning of 0.2kgm/S momentum????
Please! Reply, I will be waiting for your reply!
Thanks!
The impulse of wall on the ball .Direction of ball is changed that's why velocity chanced .
Impulse=∆p
=m(v-u) , we take mass as common.
=m(-v-u) ,here v is negative
And we know that . m(-2-2)=m(-4)
I hope you will understand
I = ∆momentum
=mv - mu
= m(v-u)
= 0.4(60-0)
= 24 Kgm/s or Ns ❤
8:13 24 kg m/s
Super! Right answer!!
Thank you so much sir, your video really helped me understand the concept of impulse.
Impulse=change in momentum
I=mv-mu
I=m(v-u)
Given that
M=400g=0.4kg
V=210kmhr-¹
U=0ms-¹
I=m(v-u)
I=0.4(60-0)
I=24kgms-¹
Fantastic! Correct answer 👍
It's mind blowing, super explanation 🎉
Thanks for the super easy explnation
Amazing 😍
From Nigeria
Very helpful sir.
Thank you sir
For. This video
Most welcome
Initial velocity (u) of the ball = 0 m/s.
Final velocity (v) if the ball = 210 km / sec = 58.33 m/s.
And the mass (m) of the ball = 400g = 0.4kg
》》Therefore, IMPULSE (I) = MV - MU
(I) = (0.4)(58.33) - (0.4)(0)
(I) = 23.33 kg m/s
The answer is 24kgm/s
I really enjoy this videos🎉
The best teacher ever
Sir why impulse is needed
Great sir ! I am your big fan
Wow ! Thanks
Thank you sir for your reply, could you tell me where did you learn English and what is your fluency secret
Thankyou sir❤
Waw nice page and tutor❤❤❤❤
I love you teaching
Thank you sir
Welcome
Your video is amazing sir
# first comment
Thank you so much 😀
48Ans
WOW! Such an amazing video!!
Thank you 😊
An outstanding 🎉🎉 lecture!
Thanks for liking
thank you very much sir!!!!!!!!
Most welcome!
Thanks meet you again sr.
24 kgms^-1
THANK YOU SIR
I like ur teaching, you make concepts super 👌
The answer is -48 kg m/s❤❤
It is not a rebound. Initial velocity is 0. Try again you should get answer as 24 kg m/s
@ManochaAcademy oh yeah it's my fault thanks for the correction❤️❤️
Interesting lesson sir.
thank you sir, love your teachings
momentum = impact ? and impulse = change of momentum ?
Please I want lecture for class 12th physics ISC please sir
I wish if I can have you as my physics teacher! 😢
Great to hear that you like our videos!
thankyou so much sir ❤️❤️❤️
sir do u only explain for CBSE class 11 students
or even to state syllabus of class 11
and sir pls explain the electricity lesson for class 10 cbse all the difficult sum how to solve them pls sir
PHYSICS CLASS 12TH LECTURE PLEASE FIR UPCOMING NEW BATCH
I can't understand the last question can somebody clarify me please?
Ronny Heberson his impulse is 6kgm/s
-48
|∆p| = |mv - mu|
= |0 - 24|
= 24 kgm/s
❤
Am from Pakistan ❤
Me also
Are you Muslim
Same 😊
Pakistan k kaha se@@AsiyaUsman-y6o
Mai bhi Pakistan se hu isliye
🎉🎉🎉
Sir Make 1chapter in 1shot ❤
Impulse:- ( -24 kgm/ s
Collision of two balls 💀
Impulse= MV
Where m= 400g which is equivalent to 0.4kg
Total velocity= 60m/s
So , impulse= MV
Impulse= 0.4*60
Impulse= 24kg m/s
0.1×(-2-2) how sir
Ahh😢😢
24 kg.m/s is correct answer of footwall
answer is 48 kgm/s
Wrong 😂
The answer is 24
24kg ms-1
Akshay Kumar left acting and started teaching physics😂
And he's really doing very well at teaching.
Ha ha :)
Ronny Heberson
Football lovers
Rooney Haberson
Football lovers
😂😂😂😂 can you leave our teacher alone
Sir you can upload Gravitation chapter class 9 in Hindi Sir please don't ignore
I just solved it and got 24kgm/s
9:01 9:02 🍖😱
1:43 who watched in 0.25x 😂
24km/s
Impulse(J)=M . Change in velocity J =400 . 0 J =0 ,therefore the impulse is 0 Kg/M.
Impulse is 24 Ns
the momentum of the ball kicked by Ronny is 24kgm/s
24 kgm/s
Hindi chenal par videos Kyu nahi dalte hai sir please ush par bhi videos Dale
hi
Hi, thanks for watching!
1/15KGM/S
-24kgm/s
Hello It's Jeet
100 like😊
Thanks!
Dear Sir, please clean your teath , its very distracting.
Love ~ Shayan
Impulse of Ronny heberson kick is 240 kgm/s
It should be 24 kg m/s. Check your calculation.
Yes , it is my fault in calculation,
Impulse= 0.4×60-0
=24kg m/s
Which class content
9 th
24 Kg m/s
😅
18th like❤
Thanks 👍
@@ManochaAcademy sir can u explain jee phy also