Ladder operators in angular momentum

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  • เผยแพร่เมื่อ 5 ก.ย. 2024
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    📚 Ladder operators allow us to increase or decrease a component of angular momentum by a discrete amount hbar. These operators are extremely useful because angular momentum is indeed quantized. In this video, we derive a long list of properties of ladder operators that will prove extremely useful in our study of angular momentum.
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    ⏮️ BACKGROUND
    Hermitian operators: • Hermitian operators in...
    Compatible observables: • Compatible observables...
    Angular momentum: • Angular momentum in qu...
    ⏭️ WHAT NEXT?
    Angular momentum eigenvalues: • Angular momentum eigen...
    ~
    Director and writer: BM
    Producer and designer: MC

ความคิดเห็น • 101

  • @armalify
    @armalify 3 ปีที่แล้ว +26

    HELLO, PHYSICS IS BEAUTIFUL WHEN THERE ARE BRILLIANT PEOPLE LIKE YOU.

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  3 ปีที่แล้ว +1

      Thanks!

    • @jacobvandijk6525
      @jacobvandijk6525 ปีที่แล้ว

      YOU ARE TOO DUMB TO JUDGE WHETHER SOMEONE IS BRILLIANT, MATE.
      BECAUSE SHE DOES NOT RECOGNIZE THIS. SHE HAS HER LIMITS TOO.

  • @trickytn2322
    @trickytn2322 3 หลายเดือนก่อน +3

    I was stuck in this topic for more than a week, and i have tried learning it through different books and lecture notes. In books, the notations were really confusing and some steps were skipped.
    I had to pause video many times, it really helped and cleared a lot of confusion. There is no confusion for now atleast, and i feel so relaxed right now.
    God bless you professor, love from pakistan.

  • @vrendus522
    @vrendus522 4 หลายเดือนก่อน +2

    Thank you Professor M. Into Q.M. about two years now. Am getting bitten bad, very interesting. Your teaching is riveting & gain my attention. Good stuff. Daniel Blatecky USA

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  4 หลายเดือนก่อน

      Glad you like it, and good luck with your learning!

  • @brotherstech3901
    @brotherstech3901 2 ปีที่แล้ว +5

    This is the only video in internet, that made me understand ladder operators thoroughly.
    Thank you ma'am

  • @MajidMohammad2
    @MajidMohammad2 2 ปีที่แล้ว +3

    This was more clear than a chapter in Sakurai. Well done

  • @adithyabharath2608
    @adithyabharath2608 9 หลายเดือนก่อน +1

    your channel is criminally underrated, hope you go viral soon

  • @ritiktanwar901
    @ritiktanwar901 2 ปีที่แล้ว +4

    I was always scared of this topic but you made it crystal clear to me thankyou professor

  • @lmhyeok
    @lmhyeok ปีที่แล้ว +2

    This channel is GOLD

  • @amaljeevk3950
    @amaljeevk3950 ปีที่แล้ว +2

    If i pass QM paper,that will be only because of this channel ❤

  • @goopyt267
    @goopyt267 2 ปีที่แล้ว +2

    i really appreciate , teaching full quantum mech with so much detailed explaination is too much sufficient and interesting for any student to generate a spark to study more of it. :)
    thank you so much and i request u to please keep making more and lot like this for different topics too, i am lovin it

  • @dineshhomedrawing2678
    @dineshhomedrawing2678 2 ปีที่แล้ว +2

    Thanks mam....🙏💜,from India...

  • @richardthomas3577
    @richardthomas3577 ปีที่แล้ว +1

    As always, excellent! In particular, I thought the derivation of the normalization constants for the kets produced by action of the ladder operators was very helpful! Thank you!

  • @DrDeuteron
    @DrDeuteron 3 หลายเดือนก่อน +1

    1:39 my 1st real QM teacher was Stan "the man" Mandelstam, and he had a great South African accents and would say: Jay eye Jay jay minus Jay jay Jay eye is eye epsilon eye jay kay Jay kay...so often it is as burned into my mind as much as ay squared plus bee squared is sea squared.
    He also would say "Dee Toop Sigh Dee feet or phi" for start of the angular momentum operator in position rep.

  • @thetrivialphysics879
    @thetrivialphysics879 3 ปีที่แล้ว +3

    Great! You guys deserve more subscribers!!!

  • @milicitrus
    @milicitrus 2 ปีที่แล้ว +1

    Thank you so much, you saved my course, your videos are so clear, kind regards from Mexico 🙏

  • @DrDeuteron
    @DrDeuteron 3 หลายเดือนก่อน +1

    Ladder operators are not just discrete, they are like ladders because each step is the same size, and you can fall off either end. I know math ppl call that last one nilpotent, but idk where to go with that.

  • @deepvision8877
    @deepvision8877 3 ปีที่แล้ว +4

    This explanation is clear for the most part, but I believe the primary reason behind using ladder operators want quite clear. I still don't understand why they are needed.
    Perhaps there could be an example of showing the importance of the concept of ladder operators with working with angular momentum before introducing them.
    For example, the QHO has ladder operators for the hamiltonian as we know that there are energy levels and so would make calculation of energies easier if we expressed the operators as a product of two operators where one raises the energy and the other lowers.
    Apart from that this was a great video.

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  3 ปีที่แล้ว +2

      Thanks for the feedback! We always try to balance the amount of content with the length of the video, and to keep them in the range 10-25 min we have to present the topics in a somewhat piecemeal fashion. However, the idea is that each video is part of a larger whole, with relevant links in the video description and also in the corresponding playlists. In this particular example of angular momentum ladder operators, we use them thoroughly in the related video on angular momentum eigenvalues, where you can start to see their importance:
      th-cam.com/video/t7x6vt6xkAI/w-d-xo.html

    • @quantum4everyone
      @quantum4everyone 2 ปีที่แล้ว

      They are used for exactly the same reasons as in the harmonic oscillator, which is to factorize the operator you are trying to find the eigenvalues for. In the harmonic oscillator, one factorization works of the form A*A+E. For angular momentum, there are three terms J^2=(J+J-+J-J+)/2+J3^2. Whenever an operator can be factorized in terms of one operator and its adjoint, one can find the eigenvalues purely from algebra. This is very powerful and is why they are employed here. It is just more complicated here because the factorization is into the sum of three factorizations rather than just one. But it can still be done.

  • @noelwass4738
    @noelwass4738 ปีที่แล้ว +1

    This is such excellent content that you have here. I appreciate it. I am not taking any courses in quantum mechanics, but it is something that interests me. I very much like the explanations using Dirac notation to derive algebraically the results that you do. You explain very well not only what you are doing but why.

  • @YossiSirote
    @YossiSirote ปีที่แล้ว +1

    Excellent

  • @irshadahmadi6497
    @irshadahmadi6497 2 ปีที่แล้ว +1

    very helpful video for me. thank you for uploading

  • @ramaavadhani5942
    @ramaavadhani5942 ปีที่แล้ว +1

    You are the best!! thanks a lottttt

  • @swansurt1350
    @swansurt1350 2 ปีที่แล้ว +1

    Really well explained! Thanks!!

  • @-thesmartboard8984
    @-thesmartboard8984 ปีที่แล้ว +1

    Thanks for the clear math ❤

  • @armalify
    @armalify 3 ปีที่แล้ว +3

    We kindly suggest to you to address the concept of Clebsch Gordan Coefficients sometime soon. Thanks !

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  3 ปีที่แล้ว +1

      We are planning a full series on angular momentum, including addition of angular momenta, so we should hopefully get to Clebsch Gordan coefficients soon!

    • @samuelnarciso1
      @samuelnarciso1 3 ปีที่แล้ว +2

      @@ProfessorMdoesScience This will be AMAZING ! You guys are turning in reference in QM.

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  3 ปีที่แล้ว +1

      Thanks!

  • @user-rp5kd5iv1z
    @user-rp5kd5iv1z 7 หลายเดือนก่อน

    you are the top G!

  • @niko-yarey
    @niko-yarey 2 ปีที่แล้ว +1

    Thank you so much!!, nice work you got here, I appreciate it 🙂

  • @guoxinxin693
    @guoxinxin693 3 ปีที่แล้ว +1

    Crystal clear! Thanks!

  • @ernek89
    @ernek89 3 ปีที่แล้ว +1

    Awesome material. Thank you!

  • @madhuverma5998
    @madhuverma5998 2 ปีที่แล้ว +1

    Beautifully explained 🙂

  • @fridamarielundjeppesen5577
    @fridamarielundjeppesen5577 2 ปีที่แล้ว +1

    Really good video again - just one question: Why is there a vector accent on J^2? It is not a vector is it?

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  2 ปีที่แล้ว

      You are correct that J^2 is not a vector, it is the scalar product of a vector with itself, which overall gives a scalar. We could write in a variety of ways (e.g. J (dot) J, J1^2+J2^2+J3^2, etc), and we use the shorthand notation J^2 as it is one of the most commonly used ones. I hope this helps!

  • @krishanpatel1794
    @krishanpatel1794 2 ปีที่แล้ว +2

    Also do you have a video proving the two red equations at 20:44

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  2 ปีที่แล้ว

      Yes, for that what we need is to show that mu=m*hbar and that lambda=j(j+1)*hbar^2. These two results are demonstrated in the video on eigenvalues:
      th-cam.com/video/t7x6vt6xkAI/w-d-xo.html
      I hope this helps!

  • @workerpowernow
    @workerpowernow 3 ปีที่แล้ว +1

    great video, thanks

  • @marit903
    @marit903 2 ปีที่แล้ว +2

    Thanks a lot for all these great videos. Do you also have a video where you explain why mu is m times hbar and lambda = j(j+1)hbar^2?

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  2 ปีที่แล้ว +2

      We do! You can find the details in this video: th-cam.com/video/t7x6vt6xkAI/w-d-xo.html
      In general, if you follow the videos in the order in which they appear in the various playlists, then we build the knowledge step by step:
      th-cam.com/users/ProfessorMdoesScienceplaylists

    • @robbiewilliamson9783
      @robbiewilliamson9783 ปีที่แล้ว

      @@ProfessorMdoesScience ah that was a struggle for me too. i think you have ladder operators before the angular momentum eigenvalues video in the playlist. At least that's the order it shows up to me.

  • @Upgradezz
    @Upgradezz 2 ปีที่แล้ว +1

    Smashed the like button!

  • @khedot6291
    @khedot6291 ปีที่แล้ว +1

    Hi there, i understand that we need a normalization constant N₊ so that we can set J₊|λ,µ> = N₊ |λ,µ+ħ> (15:55). But why exactly is that given by the norm of J₊|λ,µ> ? (18:30)
    Thank you for the great video!

    • @khedot6291
      @khedot6291 ปีที่แล้ว +1

      I also don't see how J₊J_ =J²-(J_3)²+ħJ_3 is derived

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  ปีที่แล้ว

      For the derivation of J+J-, the first step is:
      J+J- = (J1+iJ2)(J1-iJ2)
      This simply uses the definitions of J+ and J- in terms of J1 and J2. The next step is:
      (J1+iJ2)(J1-iJ2) = J1^2 + J2^2 + i(J2J1-J1J2)
      This is obtained by multiplying through the two terms in the left hand side, just like you would (a+b)(a-b) = a^2 + b^2 + ba - ab, and note that J2J1 is not equal to J1J2 as the operators don't commute. The next step is realising that the last term in the expression above is simply the commutator of J1 and J2:
      i(J2J1-J1J2) = -i(J1J2-J2J1) = -i[J1,J2]
      so that we end up with:
      (J1+iJ2)(J1-iJ2) = J1^2 + J2^2 - i[J1,J2]
      The next step is to realise that [J1,J2] = i*hbar*J3, a result we derive in this video:
      th-cam.com/video/Bo5qoaLsBOE/w-d-xo.html
      This means we end up with:
      (J1+iJ2)(J1-iJ2) = J1^2 + J2^2 - i*(i*hbar*J3)
      Using i^2=-1, we have that -i*(i*hbar*J3) = hbar*J3
      This means that:
      (J1+iJ2)(J1-iJ2) = J1^2 + J2^2 + hbar*J3
      Finally, by definition, J^2 = J1^2 + J2^2 + J3^2, so that we can write J1^2 + J2^2 = J^2 - J3^2. Replacing this in the equation above, we get:
      (J1+iJ2)(J1-iJ2) = J^2 - J3^2 + hbar*J3
      And this is the end of the derivation.
      I hope this is clearer, and in general I would recommend watching the videos in the order provided by the corresponding playlists, so that you are familiar with any results we quote.

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  ปีที่แล้ว +1

      For the norm question, the key is that the eigenstates |lambda,mu> and |lamba,mu+hbar> are normalised, so they have norm one. Therefore, if we apply the operator J+ on |lambda,mu>, we may in general end up with a state with a different norm, and we call that state N+|lambda,mu+hbar>. This means that |N+|^2 gives the norm of the new state. I hope this helps!

    • @khedot6291
      @khedot6291 ปีที่แล้ว +1

      @@ProfessorMdoesScience Thank you for the detailed answer! i watched the other videos, but this identiy in particular was trickier to me. The second one is also clear now!

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  ปีที่แล้ว

      @@khedot6291 Glad to hear it is clearer now! :)

  • @RafaxDRufus
    @RafaxDRufus 3 ปีที่แล้ว +2

    Thank you

  • @krishanpatel1794
    @krishanpatel1794 2 ปีที่แล้ว +1

    Which video that you mentioned in the video has the eigenvalue of the angular momentum operators?

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  2 ปีที่แล้ว

      You can find the link in the video description, but it is this one: th-cam.com/video/t7x6vt6xkAI/w-d-xo.html

  • @oraange
    @oraange 2 ปีที่แล้ว +1

    15:58 I'm having a hard time to understand the ket notation | lambda, mu+h>, how come ? Is it the same reason as for the translation operator ? Could you please detail me a similar exemple, I would appreciate it ! Thank you in advance ! Outstanding vid btw

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  2 ปีที่แล้ว +2

      Glad you like it! In principle we could label kets in any way we find convenient. When we have eigenkets, we typically label them using the associated eigenvalue. For example, if we have an eigenvalue "a" for an operator A, then we write the associated eigenket as |a>, and the eigenvalue equation would be A|a>=a|a>. In the video, the states are simultaneous eigenkets of two operators (J^2 and Jz), so we use the two corresponding eigenvalues for the labels, separated by a comma. Specifically, |lambda,mu+h> means that this is an eigenket with J^2 eigenvalue lambda and with Jz eigenvalue mu+h. I hope this helps!

    • @oraange
      @oraange 2 ปีที่แล้ว +1

      @@ProfessorMdoesScience Wonderful explanation ✨! Thanks you a lot!

  • @markushehlen7288
    @markushehlen7288 2 ปีที่แล้ว +1

    At 17:35 in the video you introduce an equation for the norm. How is this derived?

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  2 ปีที่แล้ว

      The norm of a vector (ket) is related to its length, calculated using the scalar product of the vector with itself. We introduce the basics behind these ideas in this video:
      th-cam.com/video/hJoWM9jf0gU/w-d-xo.html
      I hope this helps!

  • @ILsupereroe67
    @ILsupereroe67 2 ปีที่แล้ว +1

    In the playlist "angular momentum", this video and the next (the one on eigenvalues) seem to be reversed.

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  2 ปีที่แล้ว +1

      We actually have them in this order on purpose. The idea is that we first introduce the ladder operators, and we show that, in general, they raise/lower the mu eigenvalue by a factor of hbar, where mu is kept general. The derivation of this result does not require that mu has the actual value it takes for angular momentum, hence we can do this derivation first. With this result, we can then figure out the actual values that lambda and mu take in the next video (the one on eigenvalues). I hope this helps!

    • @ILsupereroe67
      @ILsupereroe67 2 ปีที่แล้ว +1

      @@ProfessorMdoesScience I see! What got me confused is that at 11:39 you say "As we discuss in the video about eigenvalues, it turns out..." and I misheard it as "as we descussED" (and I think there was some more places where you mention results that are derived in the other video, so at some point I was under the impression I was supposed to have already watched that!). Thank you!

    • @ILsupereroe67
      @ILsupereroe67 2 ปีที่แล้ว +1

      BTW these videos are AMAZING!

  • @alimimuhammes5258
    @alimimuhammes5258 4 หลายเดือนก่อน

    Pls try and use dirac notation

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  4 หลายเดือนก่อน

      We do actually use Dirac notation often, see for example the first video where we introduce it:
      th-cam.com/video/hJoWM9jf0gU/w-d-xo.html
      I hope this helps!

  • @ManojKumar-cj7oj
    @ManojKumar-cj7oj 3 ปีที่แล้ว +1

    You guys should get more subscribeers ❤️

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  3 ปีที่แล้ว +1

      Thanks for watching! We are growing steadily, and one way you can support us further is by telling your friends! :)

    • @ManojKumar-cj7oj
      @ManojKumar-cj7oj 3 ปีที่แล้ว +1

      @@ProfessorMdoesScience alright I'll ❤️

  • @AliAhmed-wc8tk
    @AliAhmed-wc8tk 3 ปีที่แล้ว +1

    you blew up my mind then took my heart ♥♥♥♥♥.

  • @charlieklausmeier9222
    @charlieklausmeier9222 3 ปีที่แล้ว +4

    Do a series teaching me stuff! Just live stream lessons. My wife had a religious education and I had a crappy us public education. My dad was a pharmaceutical biochemist, i would thrive with a good instructor.

    • @ProfessorMdoesScience
      @ProfessorMdoesScience  3 ปีที่แล้ว +1

      We are hoping to expand the resources we provide, perhaps including live sessions, but it will still take a while for us to get there. In the meantime, I hope you enjoy the videos!

    • @charlieklausmeier9222
      @charlieklausmeier9222 3 ปีที่แล้ว +1

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    @snjy1619 9 หลายเดือนก่อน +1

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  • @jacobvandijk6525
    @jacobvandijk6525 ปีที่แล้ว

    AGAIN, THIS IS NOT AN OPERATOR: 1:06. IT IS A VECTOR AND PLAYS NO ROLE IN QM. ONLY ITS COMPONENTS ARE OPERATORS (AS WELL AS L^2) !!!

  • @jamesmonteroso824
    @jamesmonteroso824 3 ปีที่แล้ว

    you are so beautiful