It appears you have not gone through the full video. I did mention that they are instantaneous values and not absolute values. You are right , ( + ) & (- ) are used for DC only and not for ac. But for understanding the practical basics I have tried to explain that way. + mentioned in ac means positive half cycle and - means negative half cycle. Confining to book knowledge only , doesn’t help in understanding the practical use. P &N doesn’t play any role in this explanation.
The buck diagram is not correct for AC single phase system. Both ways shown will boost the voltage. Also a 12 volt secondary will not buck 12 volts. It will be less. A 20:1 would buck close to the secondary voltage but a 7.5:1 would not be.
I’m sorry sir but your video is categorically incorrect for the “buck”. Additionally, where a boost will add the secondary voltage to the primary, bucking will not simply subtract the voltage. Its clear you have any experience connecting and testing real auto transformers. Where you are categorically wrong is thinking there natural polarity on the secondary side. As soon as you connect the line to voltage to secondary (which is what makes it an auto transformer) the polarity is set by that connection. Your theory is correct in relation do DC circuits but again, not correct for buck. I connect buck boat transformers multiple times a year in the real world. You are wrong and shouldn’t be teaching this. A 230 x 12 transformer is a 19.17:1 transformer. So while it will boost 12 volts making 242 volts, it will buck only 10.97volts creating 219.03 volts. I hope that helps your understanding. Please ask me questions or study more on your own.
@@johnbelt7676 It is a simple way of autotransformer principles. The primary is fed with 230v. The secondary develops 12v. While the secondary is connected in series in phase, the voltage is added, and while connected in series in out of phase it is subtracted. For better understanding purposes, however, they are represented in + ve and -ve polarities which are in fact are instantaneous values. Where is the problem?
@@johnbelt7676 Ask ChatGPT this and you will get the answer. "In an AC system if voltage A = 230volts RMS and B = 12volts RMS. What is the total voltage say C , if B is in series in phase with A? Similarly what is the voltage in C while B is in series in out of phase with A?"
@@johnbelt7676Here is the answer from chatGPT. In an AC circuit, when two voltages are in series, the total voltage is the algebraic sum of the individual voltages. This means that if voltage B is in series with voltage A, the total voltage C will be: In-phase (additive): C = A + B = 230 volts RMS + 12 volts RMS = 242 volts RMS So, when voltage B is in series and in-phase with voltage A, the total voltage C is 242 volts RMS. Now, when voltage B is in series and out of phase with voltage A, you need to consider their phase relationship. If they are out of phase by 180 degrees, they will subtract from each other. In this case: Out of phase (subtractive): C = A - B = 230 volts RMS - 12 volts RMS = 218 volts RMS So, when voltage B is in series and out of phase with voltage A (180 degrees out of phase), the total voltage C is 218 volts RMS.
Sir your explanation is superb. Best teacher
Thanks
सर आप सच में बाहोत नॉलेज है।।।you are great
I shiva Bahut aacha laaga jo aap ko padand ayaa.
@Beckett Alec would you like to sell your girlfriend?
Thanks for the video, very clearly explained 👍👍👍
Nice explanation sir
बाधाइ हो महाशय,हिन्दी मे जानकारी देने केलिये ।
Thanks
Very nice explanation
Thanks
AC voltage terminal denote P - N. (. Phase and Neutral) D.C volt +/-
It appears you have not gone through the full video. I did mention that they are instantaneous values and not absolute values. You are right , ( + ) & (- ) are used for DC only and not for ac. But for understanding the practical basics I have tried to explain that way. + mentioned in ac means positive half cycle and - means negative half cycle. Confining to book knowledge only , doesn’t help in understanding the practical use. P &N doesn’t play any role in this explanation.
Also look into the comments on this video those who have gone through in full. Please listen to the same video in my English mode channel.
Great sr
Thank you.
thanks 🙏
My pleasure
The buck diagram is not correct for AC single phase system. Both ways shown will boost the voltage. Also a 12 volt secondary will not buck 12 volts. It will be less. A 20:1 would buck close to the secondary voltage but a 7.5:1 would not be.
It appears you have not followed the explanations and simulations. Please listen carefully. You can find the same in my English version.
I’m sorry sir but your video is categorically incorrect for the “buck”. Additionally, where a boost will add the secondary voltage to the primary, bucking will not simply subtract the voltage. Its clear you have any experience connecting and testing real auto transformers. Where you are categorically wrong is thinking there natural polarity on the secondary side. As soon as you connect the line to voltage to secondary (which is what makes it an auto transformer) the polarity is set by that connection. Your theory is correct in relation do DC circuits but again, not correct for buck. I connect buck boat transformers multiple times a year in the real world. You are wrong and shouldn’t be teaching this.
A 230 x 12 transformer is a 19.17:1 transformer. So while it will boost 12 volts making 242 volts, it will buck only 10.97volts creating 219.03 volts.
I hope that helps your understanding. Please ask me questions or study more on your own.
@@johnbelt7676 It is a simple way of autotransformer principles. The primary is fed with 230v. The secondary develops 12v. While the secondary is connected in series in phase, the voltage is added, and while connected in series in out of phase it is subtracted. For better understanding purposes, however, they are represented in + ve and -ve polarities which are in fact are instantaneous values. Where is the problem?
@@johnbelt7676 Ask ChatGPT this and you will get the answer. "In an AC system if voltage A = 230volts RMS and B = 12volts RMS. What is the total voltage say C , if B is in series in phase with A? Similarly what is the voltage in C while B is in series in out of phase with A?"
@@johnbelt7676Here is the answer from chatGPT. In an AC circuit, when two voltages are in series, the total voltage is the algebraic sum of the individual voltages. This means that if voltage B is in series with voltage A, the total voltage C will be:
In-phase (additive):
C = A + B = 230 volts RMS + 12 volts RMS = 242 volts RMS
So, when voltage B is in series and in-phase with voltage A, the total voltage C is 242 volts RMS.
Now, when voltage B is in series and out of phase with voltage A, you need to consider their phase relationship. If they are out of phase by 180 degrees, they will subtract from each other. In this case:
Out of phase (subtractive):
C = A - B = 230 volts RMS - 12 volts RMS = 218 volts RMS
So, when voltage B is in series and out of phase with voltage A (180 degrees out of phase), the total voltage C is 218 volts RMS.
Buck boost Transformer H1 H2 H3 H4 X1 X2 X3 X4 VIDEO BANAYE SIR
Not able to understand. What is H! H2 H3 etc?
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