Thanks for the lesson. I do have some questions. Assume I have an horizontal cylindrical tank Ø1250 x 3000mm and it is almost full of water. (Water level stays at 1,035m from the bottom of the tank) This tank is also supported by 2 feets on its ends, each feet have 0,1m² of area. This tank will be submitted to negative pressure. Visual representatiom: _____________ |____________| (both vertical bars represent the support feet Do the reaction "pressure" of the both feets + the reaction of the water coloumn + atm pressure have influence on this calc, in means of external pressure? Here are my calcs: Internal pressure = -0,026 barg (-0,0026 MPa man) water column pressure of water inside tank = 0,010 MPa Feet "pressure" on the bottom of the shell = 0,1986 MPa (value for one feet) In this case, doing the balance, I got: - 0,0026 + 0,010 - 0,1986 MPa = -0,1911 MPa of inside pressure (or vacuum) The "P" value I got from appliyng these calculations show me that my max pressure should be 0,116 MPa @ #6mm thickness. Could you help me, I think I'm mixing concepts.
Thank you so much sir for sharing knowledge. I have one doubt that how you calculated design pressure 0.1Mpa. If my chamber is under vacuum of 2 mbar then what will be the external pressure?.
Why not taking OD as per ASME B36.10 or B36.19 for respective material n why -12.5% mill tolerance in not added in market available thickness which should be greater than min wall thickness required ?
Thanks for the lesson.
I do have some questions.
Assume I have an horizontal cylindrical tank Ø1250 x 3000mm and it is almost full of water. (Water level stays at 1,035m from the bottom of the tank) This tank is also supported by 2 feets on its ends, each feet have 0,1m² of area. This tank will be submitted to negative pressure.
Visual representatiom:
_____________
|____________| (both vertical bars represent the support feet
Do the reaction "pressure" of the both feets + the reaction of the water coloumn + atm pressure have influence on this calc, in means of external pressure?
Here are my calcs:
Internal pressure = -0,026 barg (-0,0026 MPa man)
water column pressure of water inside tank = 0,010 MPa
Feet "pressure" on the bottom of the shell = 0,1986 MPa (value for one feet)
In this case, doing the balance, I got: - 0,0026 + 0,010 - 0,1986 MPa = -0,1911 MPa of inside pressure (or vacuum)
The "P" value I got from appliyng these calculations show me that my max pressure should be 0,116 MPa @ #6mm thickness. Could you help me, I think I'm mixing concepts.
Sir always come with great clarity
Thank you @Ankit
Great and amazing thank you for such a learning video.
Our pleasure!
Thank you very much sir. God bless you.
Thank you.
Thank you so much sir for sharing knowledge.
I have one doubt that how you calculated design pressure 0.1Mpa. If my chamber is under vacuum of 2 mbar then what will be the external pressure?.
2 mbar
Hi sir can you explain how to calculate Ls slen in stiffener
Why not taking OD as per ASME B36.10 or B36.19 for respective material n why -12.5% mill tolerance in not added in market available thickness which should be greater than min wall thickness required ?
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