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Ang continuation sa pagsolve sa problem na ito ay ang Part 2 - Series Parallel / Complex Circuit Problem
galing ng pagkakaturo hindi ko alam bat d nila na gets hahaha
the only Kenyan here for learning purposes
Thanks a lot.
Thank you po
on this circuit if we omit 80 ohm resistance how we can get Rtotal,v,I
1/(1/300)+(1/200) kaya naging 120 nasa formula yan
Then paano naman po makukuha lahat amperes ng lahat resistor na po iyan? Iisahin isahin rin po ba sya? And fanun din po ba sa voltage? Iisahin isahin po din iyon?
Yes . Nasa part2
Sir pede paki specific pano po nakuha ung 120 ohms?😅
Ok sir, (300 × 200)÷(300+200) = 60000÷500 = 120
Electric banyan or electronic?
Ito ay basic concept ng electrical at electronics.
paano nakuha ang 120ohms sir
Ganito po sir. 1--------------------------------- = 120 ohms1/300 + 1/(50+150)
parasan bat may 28v dun sa unahan
Ito ay sample problem ng ating subscriber at ang 28V ay supply voltage sa circuit.
Ang continuation sa pagsolve sa problem na ito ay ang Part 2 - Series Parallel / Complex Circuit Problem
galing ng pagkakaturo hindi ko alam bat d nila na gets hahaha
the only Kenyan here for learning purposes
Thanks a lot.
Thank you po
on this circuit if we omit 80 ohm resistance how we can get Rtotal,v,I
1/(1/300)+(1/200) kaya naging 120 nasa formula yan
Then paano naman po makukuha lahat amperes ng lahat resistor na po iyan? Iisahin isahin rin po ba sya? And fanun din po ba sa voltage? Iisahin isahin po din iyon?
Yes . Nasa part2
Sir pede paki specific pano po nakuha ung 120 ohms?😅
Ok sir,
(300 × 200)÷(300+200)
= 60000÷500
= 120
Electric banyan or electronic?
Ito ay basic concept ng electrical at electronics.
paano nakuha ang 120ohms sir
Ganito po sir.
1
--------------------------------- = 120 ohms
1/300 + 1/(50+150)
parasan bat may 28v dun sa unahan
Ito ay sample problem ng ating subscriber at ang 28V ay supply voltage sa circuit.