Its safe to say here that a common notion is,the lecturers and assistants around the world have a way of making stuff utterly complicated to understand. Thank you thank you thank you for considering the little students which only try to understand the material.Thank you much.
Dear professor, you made a great video, thank you very much. Your explanation is really clear and simple and you can say in a few minutes more than our teachers in a lot of hours. Greetings from Czech Republic
Assuming the boundary conditions are identical, a column will buckle in the direction of the smallest value of I. The column that looks like a ruler will buckle in the direction of the smallest dimension.
Thank you very much, my teacher did not expain any of this and I was very confused reading thorugh my notes. Your videos are well explained and now everything is getting clear.
@MrZah89 I tried to calculate Pcr (not Pe) and I got 25.24N. Pcr=(Pi^2X5.516X10E3MPaX144mm^4)/(1)(557.3mm)^2. Try that. U must have got your unit wrong. For Prof French, u are great. This is a great refresher for me. It's much easier to listen to u than reading text like Juvinall or Mott.
great again. please add more. can you upload a clip explaining how finite element method is used in computer based design? the approaches , determination steps and understanding outcomes in that report.
columm AB carries a centric load P of magnitude 60kn. cables BC and BD are taut and prevent motion of point B in the xz plane. using euler formula and a factor safety of 2.2 , gelect tension in cable. determine the maz allowable length L...this is the qns
Remember guys, that the column is never truly straight and so the column buckles from the moment you put any compressive load on it, no matter how small. Remember that "buckling" is defined as a column that wishes to worsen its curvature. The Euler buckling load is better described as the maximum allowable end load before the buckling curvature "runs away" and, it fails catastrophically. It is the limit allowable compressive load. It is not the load that initiates buckling.
I'm a bit confused for the rectangle's second moment of inertia, if i instead took b = 4mm and h = 27 mm that would give I =6561mm^4 which is much larger than the square's. Why do you choose b and h in that particular way?
Normally we consider the minimum value of the moment of inertia thus we get the direction of bulckling. But what happens for square cross sections? Since there's equal value of moment of inertia in both ways?
Good video. Got an exam on this soon and it's good to learn something that takes a lecturer 2 hours. P.S. English units? Do you mean imperial? The UK has been metric for over 30 years.
can u please explain me wts the major and wts the minor axis. I cant picture it! wen we say rotation about x-axis, how does the beam rotate? do the flanges bend downwards, or sideways? pls help me out here!
hey prof, can i request to see if you could put up video on buckling in the yz plane and xz plane. and also, explain the formula for inertia Ix if it is in the yz plane and the inertia Iy in the xz plane? thanks!
@1932chevrolet Wow. This thing must be the battleship of the kayak world. I'm away from the office and don't have time to check your calculations. First thing to check is whether you have a thin column or not.
Very informative video! Thanks! One question: I plan to make a metal tubing construction and I want to run some numbers for the horizontal roof beams (the base of the roof trusses). As you gave the formula for "the critical buckling" that seems like a sort of limit, how do I calculate the real buckling value in order to compare it with the critical one?
Very good explanation, but I have a question, the critical load formula serves to determine the load to which the column buckles, But is there any formula or a way of knowing since the column has buckled, ?
We generally assume that a column has little or no load carrying ability after it has buckled. There are some expressions for beam elements with large deformation that might work for buckled beams or columns.
Hi there thanks for the helpful video. I have a question about the Moment of Inertia equation though.[ I = (1/12)*b*h^3 ] How do we know which edge to use as base and which edge to use as height?
The axis for the area moment of inertia is sort of like the resistance of an area element from rotation (or just an point away from the axis). So, you use the distance^3 that would be in the direction perpendicular (or can think of it as away) from the axis of interest. You can think of the other distance multiplier as just adding a multiple amount of lines from the axis of interest with the same sort of rotation resisting value which in sum is the moment of inertia.
+Ramen Van Trough Very good question and here is the very good answer : The rectangular cross section has two moments of inertia Ix and Iy. You must calculate both and select the smaller one. In this example h is 4 and b is 27.
This is taken into account if you are doing LRFD or ASD Assuming you are doing ASD then it would be 1.67. If you were in LRFD you would need to apply load factors to you loads I.E. dead and live.
Its safe to say here that a common notion is,the lecturers and assistants around the world have a way of making stuff utterly complicated to understand.
Thank you thank you thank you for considering the little students which only try to understand the material.Thank you much.
12 years later, thank you so much for this video !
Dear professor, you made a great video, thank you very much. Your explanation is really clear and simple and you can say in a few minutes more than our teachers in a lot of hours.
Greetings from Czech Republic
Make more videos! You teach better than my professor. :-)
Assuming the boundary conditions are identical, a column will buckle in the direction of the smallest value of I. The column that looks like a ruler will buckle in the direction of the smallest dimension.
Thank you very much, your skill as a professor is incredible! Simply direct to the point. Cheers.
Was looking for something on Euler Column buckling that I'm checking on Aircraft stiffened panels. This is just what I needed. Thanks!
Thank you
Your videos have helped me through my class and I got A +
@ARIJ88 I'm glad the video helps. I'm doing more videos every week.
Thank you very much, my teacher did not expain any of this and I was very confused reading thorugh my notes. Your videos are well explained and now everything is getting clear.
@MrZah89 I tried to calculate Pcr (not Pe) and I got 25.24N. Pcr=(Pi^2X5.516X10E3MPaX144mm^4)/(1)(557.3mm)^2. Try that. U must have got your unit wrong.
For Prof French, u are great. This is a great refresher for me. It's much easier to listen to u than reading text like Juvinall or Mott.
nice straight forward explanation
I wish u to be my teacher.. u explained better than mah professor.. old is really gold
Your explanation way is so interesting 👌👌👌👌👌
Higher cross section and shorter length will Greatly increased it's load capacity. To get the critical stress just divide it by area.
great again. please add more. can you upload a clip explaining how finite element method is used in computer based design? the approaches , determination steps and understanding outcomes in that report.
columm AB carries a centric load P of magnitude 60kn. cables BC and BD are taut and prevent motion of point B in the xz plane. using euler formula and a factor safety of 2.2 , gelect tension in cable. determine the maz allowable length L...this is the qns
Remember guys, that the column is never truly straight and so the column buckles from the moment you put any compressive load on it, no matter how small. Remember that "buckling" is defined as a column that wishes to worsen its curvature.
The Euler buckling load is better described as the maximum allowable end load before the buckling curvature "runs away" and, it fails catastrophically. It is the limit allowable compressive load. It is not the load that initiates buckling.
@MrZah89 make sure you put your GPa in as MPa to get the units correct
Is there a way to predict the buckling of a thin walled beam in bending? Such as the wing spar of an aircraft
wow your way better than my structures professor
thank you it is very helpful and I learn a lot from your videos.
I'm a bit confused for the rectangle's second moment of inertia, if i instead took b = 4mm and h = 27 mm that would give I =6561mm^4 which is much larger than the square's. Why do you choose b and h in that particular way?
ur very brilliant explanation all the topics very good sir! i like so much ur teaching.....
Great teaching.. good informative video.. congrats
Normally we consider the minimum value of the moment of inertia thus we get the direction of bulckling. But what happens for square cross sections? Since there's equal value of moment of inertia in both ways?
Good video. Got an exam on this soon and it's good to learn something that takes a lecturer 2 hours.
P.S. English units? Do you mean imperial? The UK has been metric for over 30 years.
Thanks for your perfect explination!, it helps me out a lot. Greetings from the Netherlands.
can u please explain me wts the major and wts the minor axis. I cant picture it! wen we say rotation about x-axis, how does the beam rotate? do the flanges bend downwards, or sideways? pls help me out here!
Thanks so much, can you do one on failing under compression too?
hey prof, can i request to see if you could put up video on buckling in the yz plane and xz plane. and also, explain the formula for inertia Ix if it is in the yz plane and the inertia Iy in the xz plane?
thanks!
Thanks, very well explained buckling
@1932chevrolet Wow. This thing must be the battleship of the kayak world. I'm away from the office and don't have time to check your calculations. First thing to check is whether you have a thin column or not.
Wow. So neat and clear. Thank you!
great demonstration. god bless you
Very informative video! Thanks! One question:
I plan to make a metal tubing construction and I want to run some numbers for the horizontal roof beams (the base of the roof trusses). As you gave the formula for "the critical buckling" that seems like a sort of limit, how do I calculate the real buckling value in order to compare it with the critical one?
Brilliant explanation!
Hey prof. why no deflections of beams/superposition videos??
thank you very much, sir..... Excellently explained.
why don't we use the higher moment of inertia ? for stick 1 ?
it would give a higher Pcritical, even higher than stick 2 provides.
dear sir,
can you please link between this and v.mises stress
can we ignore buckling if we are using v.mises
and what about plastic/inelastic design?
Prof, excellent videos, but Can you tell the difference between linear and non linear buckling ? thnks
How does beam theory or thin sheet theory differ?
how can I know if its global or local buckling ?
when using SAP2000 to calculate Pcr, dividing the frame members makes the results change. why is it so? thank you...
thank you.your teaching is very useful. could you tell how to find the value of deflection at any point in the column under compressive force
Very good explanation, but I have a question, the critical load formula serves to determine the load to which the column buckles, But is there any formula or a way of knowing since the column has buckled, ?
We generally assume that a column has little or no load carrying ability after it has buckled. There are some expressions for beam elements with large deformation that might work for buckled beams or columns.
What about the non symmetric profile. we need to calculate Imin is that right
Excellent!! Could you derive that equation?
sir is it cmpulsry to take minimum moment of inertia ?
if i want to design an eccentric loaded short column, is interaction formula better or secant formula is more suited?
The secant formula would be more appropriate for an eccentric loaded column
E=value is mentioned 800,000 psi is it right value or an assumption.
what is the value considered for final computing the load
if you pick the height for stick one to be 27mm then it's I will be greater than stick two. why?
Hi there thanks for the helpful video. I have a question about the Moment of Inertia equation though.[ I = (1/12)*b*h^3 ] How do we know which edge to use as base and which edge to use as height?
The axis for the area moment of inertia is sort of like the resistance of an area element from rotation (or just an point away from the axis). So, you use the distance^3 that would be in the direction perpendicular (or can think of it as away) from the axis of interest. You can think of the other distance multiplier as just adding a multiple amount of lines from the axis of interest with the same sort of rotation resisting value which in sum is the moment of inertia.
+Ramen Van Trough Very good question and here is the very good answer : The rectangular cross section has two moments of inertia Ix and Iy. You must calculate both and select the smaller one. In this example h is 4 and b is 27.
you find both, and give the minimum
why didn't i get this in the lecture... but now i get it in just under 9 mins. ?
strange..
hi teacher, your videos are really good. could you please create a video about the difference between bending and bucking ?.
it would be more great
so what happens if you rotate the ruler stick cross-sectional shape by its axis 90 degrees so the value of I is greater?
+Rusty Shackleford and then do the empirical test
+Rusty Shackleford The moment of intertia (I) is calculated in the x and y directions, so if you rotate the ruler you would have Ix
yes that makes sense. cheers
nice explained
Very good!
Thank you very much!
suppose you were given a load and a factor of safety. how do those fit?
This is taken into account if you are doing LRFD or ASD Assuming you are doing ASD then it would be 1.67. If you were in LRFD you would need to apply load factors to you loads I.E. dead and live.
Very usefu, thank you!
nice work.
Thank you!
Thanks alot sir 💕
Thank you.
very helpful !! thanks !
why only one side it's bending even both sides are same ex: a ruler bends in one direction
why only one side is bending even both sides are same ex: a ruler bends in one direction if we apply compressive force
Great video ! :)
Nice.............................
Prof French put “meter” instead of “mm”
Thank you sir
thank you very much ^^
brilliant
Genius
thank u sir
the difference is due to the cross sectional area... cross sectional shape :|
top video
the cables are like this / || \
umm good video but i think you made a small mistake with stick 1 with 4m should be 4 mm.
better
Sir you are funny.
you make a mistake to write h=4m, but it is h=4mm
+sadrul hossain Are you serious ?
h=4m, if you are Civil Eng. Im sure u can see its 4mm not 4m thickness ! jeeez !
Wao budhe
Very good!
Thanks. I'm glad you liked the video :-)