it is absolutely correct Boron hydrogen bond contributes two electrons. Carbon hydrogen bond contributes 3 electrons. (That is in carboranes). So 2CH= 2*3=6 3BH=3*2=6
Sir can't we just replace the carbon by a BH unit..then the cluster type will be arachno..I may be wrong but sir I think there's something wrong with the calculation
Sir if SEP = NO of vertices... In this qstn if IAM solving no. Of SEP I get 13 but as u said according to vertices it is 12 .. Can u plz explain it sir
Sir... I m admirer of ur video... You really doing a good job bt honestly speaking its sort of different or may b confusing for me to understand this as its different method.... As far as I knw there is a formula to predict skeleton pair..... bt still unable to solve questions related to skeletal pair for transition metal complexes....kindly upload more videos related to this topic.... Thanks
Sir,Here you r coverting Me group to Isolobal group. So only vertices will be from C2 and B10 in the formula.. Me group are not forming the vertices. I think in that you sir
Here I'm talking about how much electron it will donate to skeletal framework, that's why I didn't took 5 electrons for CH unit. CH donates 3 electrons to framework and BH donates 2 Thats why 2CH=3BH
Priti Smita, this was just a problem solved.. I've made a video on Wade-Mingos rule... Kindly watch that... There I've discussed about number of vertices and all...
Here I'm talking about number of electron donated in the polyhedral skeletal framework of carborane. In case of Carborane only we have to use this method, When I said CH=5 that was number of valence electrons in it. Both the things are different. 👍
Jolly Balel, When we talk about electrons contributed by a unit in skeletal system, then, one BH unit contributes 2 electrons whereas one CH unit contributes 3 electrons. This we can say 2CH=3BH as eventually we get 6 electrons in both cases.
It's not about the number of valence electrons, it's about the number of electrons contributed in the structure, BH contributes 2 electrons and CH contributes 3 electrons
See.. According to wade rules each CH unit contributes 3 electrons to the structure and each BH unit contributes 2 electrons. So, 3BH=2CH units. 3×2=2×3 electrons.
It's not about the number of valence electrons, it's about the number of electrons contributed in the structure, BH contributes 2 electrons and CH contributes 3 electrons So it's 2×3=3×2 electrons
but sir when to use
2ch=3bh and when to use
c=bh ?? plz telll
We know CH is isolobal with BH2. But this hasn't been applied here. Why so? Can you explain when to apply which rule??
(Me)3C2B10H10= (H)2(BH)2 B10H10
=B12H14....closo...CH3 replace by H.....Same concept repeated somewhere net or gate ...Don't remember...Is it right ?
2CH=3BH?
2*5=3*4
10=12?
Sir how it is equal, can you please explain me.
Thank you.
you are absolutly right, how is this possible
Yaa.. Something is wrong
It is a formula. It is not wrong. Though i dont know how. But its true
B atomic number 5 where as c 6....so for equalise
it is absolutely correct
Boron hydrogen bond contributes two electrons. Carbon hydrogen bond contributes 3 electrons. (That is in carboranes).
So 2CH= 2*3=6
3BH=3*2=6
sir from which book I will followe that valuable for me and getting such things
www.chemohollic.com/2016/06/complete-list-of-reference-book-in.html
Sir , please give the link of calculating no. of vertices.
Sir can't we just replace the carbon by a BH unit..then the cluster type will be arachno..I may be wrong but sir I think there's something wrong with the calculation
Yes you can do it like that as well, keeping Me as side chains
Sir by replacing C with BH, we are getting Arachno. How is this wrong, since there's no option too?
Sir not understood this question plz explain 2CH=3BH
sir what will be the dissociation energy of H2 molecule in eV if ground state energies of H atom (-13.6eV) and H2 molecule(-31.7) are given??
Sir if SEP = NO of vertices...
In this qstn if IAM solving no. Of SEP I get 13 but as u said according to vertices it is 12 ..
Can u plz explain it sir
Ch3 donates one electron to skeletal structure
When i put c=BH den not find the same answer as trick u done
C2B3H5 in which I put c=BH den find the answer"""plz clear my doubt
Exactly ....i have the same doubt
I have also that same doubt
Sir... I m admirer of ur video... You really doing a good job bt honestly speaking its sort of different or may b confusing for me to understand this as its different method....
As far as I knw there is a formula to predict skeleton pair..... bt still unable to solve questions related to skeletal pair for transition metal complexes....kindly upload more videos related to this topic....
Thanks
Hlo sir kya hum is question ko valence e- count vale method se baat kar sakte hai?
how to calculate 2CHunit equal to3 BH unit ?
So much confusing is it...have seen that you had faced same problem on 3 yrs ago.. hope now itz clear to you...can you explain it mam ?🙏
Sir,Here you r coverting Me group to Isolobal group. So only vertices will be from C2 and B10 in the formula.. Me group are not forming the vertices. I think in that you sir
If CH3 gr is not a part of skeleton framework then why it is considered in calculating the TVE? Please explain
Here I'm talking about how much electron it will donate to skeletal framework, that's why I didn't took 5 electrons for CH unit. CH donates 3 electrons to framework and BH donates 2
Thats why 2CH=3BH
sir, isme SEP find karke shape find nai par sakte ?
Sir I couldn't understand the no of vertices part..
Kindly give Mora example regarding how to calculate no of vertices
Priti Smita, this was just a problem solved.. I've made a video on Wade-Mingos rule... Kindly watch that... There I've discussed about number of vertices and all...
Sir I have already seen this video.bt there is no explanation about no of vertices.
There is discussion about SEP.
Is SEP = no of vertices
yes the values given there for SEP is also showing number of vertices.
Ok..thank u sir
You're welcome 😊
Sir in isolobal video , you said CH is 5 , bt here how you are calculating CH is 3
Here I'm talking about number of electron donated in the polyhedral skeletal framework of carborane.
In case of Carborane only we have to use this method,
When I said CH=5 that was number of valence electrons in it.
Both the things are different. 👍
Ok sir, how you calculating CH 3 , BH 2 , or we just have to remember,
No these are known values and you've to remember them.
According to wade' s rule CH gives 3
Its 5....4 frm c and 1 frmH
Ch3 replace by H
Sir will you please explain a little about the concept of 2CH=3BH
Jolly Balel,
When we talk about electrons contributed by a unit in skeletal system, then, one BH unit contributes 2 electrons whereas one CH unit contributes 3 electrons.
This we can say 2CH=3BH as eventually we get 6 electrons in both cases.
Sir plz give more examples of electron contribution of this nature.
cH=5,BH=4 is it or not
It's not about the number of valence electrons, it's about the number of electrons contributed in the structure, BH contributes 2 electrons and CH contributes 3 electrons
PEC=TVE-2n (n=b+c)
n =no. of vortices
PEC/2=skeletol eletron pair. =13=(n+1) closo.
this mangos rule for carborane
What is PEC
(PEC)Poly electron count
How the 2CH become 3BH ? would u please explain
Read out comments I've answered it many a times.
very nice explaination sir
No of vertices = SEP - 1
Does not understand Vetices
sir 2(c-H)=3(B-H) ,how
See.. According to wade rules each CH unit contributes 3 electrons to the structure and each BH unit contributes 2 electrons.
So, 3BH=2CH units.
3×2=2×3 electrons.
But in wade rule they said one carbon is equal to BH, you followed this in your wade rules, why not in this example
initially I had a also doubt like you but then I found the answer 2(C-H)=3(B-H)
initially I had a also doubt like you but then I found the answer 2(C-H)=3(B-H)
Bhaktahari Nayak sometimes we take valence electron...BUT here u have taken electron contribution for CH ..how to know when to use which..pls explain.
Dodeca mean 12 ...y u say for 8
No metal is equal to vertices
Dn't understand vertics
2 CH= 3BH ...How..??
It's not about the number of valence electrons, it's about the number of electrons contributed in the structure, BH contributes 2 electrons and CH contributes 3 electrons
So it's 2×3=3×2 electrons
All 'Bout Chemistry sir but how will we know where to use this bcoz we usually write cH = BH2