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3^x*3^x*3^x=36 x=Log[3,1.3recurring]+2=(2+2Log[3,2])/3
Thank you
It’s in my head.
Write Your answer.
0,(3)lg36/lg3.NOTE. The equation has complex roots too.
❤❤❤❤❤❤🇹🇳
3^x+3^x+3^x=36.It is =3×3^x=36.So 3^x=36/3. 3^x=12.=3^x=3^2+3.
Since Mathematical notation suddenly are not coming. Earlier the numbers were on top when I click. Now it comes triangular without maths notations.
Там не +, а ×
3^x*3^x*3^x=36 x=Log[3,1.3recurring]+2=(2+2Log[3,2])/3
Thank you
It’s in my head.
Write Your answer.
0,(3)lg36/lg3.
NOTE. The equation has complex roots too.
❤❤❤❤❤❤🇹🇳
3^x+3^x+3^x=36.It is
=3×3^x=36.
So 3^x=36/3.
3^x=12.
=3^x=3^2+3.
Since Mathematical notation suddenly are not coming. Earlier the numbers were on top when I click. Now it comes triangular without maths notations.
Там не +, а ×