If we consider √A instead of √𝟑, then how we will solve this question. We require a value to solve this. If you observed we found out the side AC using Pythagoras theorem. With √A, how we can get a particular value. So, it would be difficult to solve this question. Hope you understand the problem here.
Keep Watching! Please reach out to me in the comments section of any video if you have any question on maths. I will get back to you once I see your comments. Thank you!
The question has given that tan A = 1/√𝟑. We know that tan A = BC/AB from the triangle ABC. So, we can write tan A = 1/√𝟑 = BC/AB. Now what we got? We got BC/AB = 1/√𝟑, i.e. BC=1 and AB=√𝟑. Hope you got the point.
cos A cos C + sin A sin C = √𝟑/2*1/2 + 1/2*√𝟑/2 = √𝟑/4 + √𝟑/4 = 2√𝟑/4 = √𝟑/2. Hope you understood this. If still, you have any doubts please feel free to reach out to me again. Thank you for asking this question.
Sir you are so excellent
Thank you so much! 😊
Thank you sir
Welcome! 😊
@@MathsPursuit sr bg fan
Excellent sir...
Tysm sir
Most welcome! 😊
What will be the answer if we take 1/rootA in the place of 1/roor3
If we consider √A instead of √𝟑, then how we will solve this question. We require a value to solve this. If you observed we found out the side AC using Pythagoras theorem. With √A, how we can get a particular value. So, it would be difficult to solve this question. Hope you understand the problem here.
Sir kya samjhye samjh nhi aaya please help karo na 😩🥺
👍
Thank you!
It's help me lot sir
Keep Watching! Please reach out to me in the comments section of any video if you have any question on maths. I will get back to you once I see your comments. Thank you!
@@MathsPursuit okh sir once again thank you ❣️
Sample paper ke baad
I could not understand what you are asking?
Thanku very much sir 👍🏿👍🏿
Most welcome! 😊😊
Thanks bro your explanation is nice and it helped me
Glad to hear that!
Ab=√3 how?
The question has given that tan A = 1/√𝟑. We know that tan A = BC/AB from the triangle ABC. So, we can write tan A = 1/√𝟑 = BC/AB. Now what we got? We got BC/AB = 1/√𝟑, i.e. BC=1 and AB=√𝟑. Hope you got the point.
Thanku sirr 😍😍😍😊
You're welcome.
Thanks for your explanation sir
You are most welcome
Thank you sir l❤️u🙏🙏🙏🙏
Most welcome!
Tell me
cos A cos C + sin A sin C = √𝟑/2*1/2 + 1/2*√𝟑/2 = √𝟑/4 + √𝟑/4 = 2√𝟑/4 = √𝟑/2. Hope you understood this. If still, you have any doubts please feel free to reach out to me again. Thank you for asking this question.
Tq sir
𝓑𝓲𝓻𝓮𝓷𝓭𝓪𝓻 𝔂𝓪𝓭𝓪𝓿
Thank u sir ❣️
Welcome sir bes u sir❤️❤️❤️
Thank you!
Sir please cosA cosC +sina since this answer
Sir please reply madi sir
Thank you sir