Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html Full-Length Exams & PDF Worksheets: www.patreon.com/MathScienceTutor/collections Access The Full 1 Hour 32 Minute Video: bit.ly/3BeeOB3
i am so grateful that you make this kind of vedios if not for you i would have failed my chemistry exams ,my teacher is bad at explaining stuff, he makes it too complex,thank you
I love you, thank you so much for this!!!! Btw, in 10:33 isn't it more correct to say we get Hydrogen Chloride out of this reaction rather than Hydrochloric Acid, considering all of these components that are reacting are in gas form?
Cl and Br both overall are exothermic, but their first steps are both endothermic (though Br is much more endothermic), so this is not a great graph to use. F on the other hand is super exothermic all the way through so it would be better to use this for the rxn proceeding vs energy graph. So, although Cl is less endothermic, it will still more so resemble the product but still be less selective.
fluorine reacts readily and hence is least selective in nature,so it just attaches to the carbon free radical with the least steric hindrance,as in if i have propane and i make it undergo fluorination,the major product would be 1-fluoropropane rather than 2-fluoropropane in case of Iodine,it's very selective in nature and therefore bonds with the carbon free radical which is tertiary in nature(it's more stable due to hyperconjugation),so if i make propane undergo iodination,it's major product would be 2-iodopropane
Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html
Full-Length Exams & PDF Worksheets: www.patreon.com/MathScienceTutor/collections
Access The Full 1 Hour 32 Minute Video: bit.ly/3BeeOB3
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i am so grateful that you make this kind of vedios if not for you i would have failed my chemistry exams ,my teacher is bad at explaining stuff, he makes it too complex,thank you
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Btw, in 10:33 isn't it more correct to say we get Hydrogen Chloride out of this reaction rather than Hydrochloric Acid, considering all of these components that are reacting are in gas form?
You're absolutely right.
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why did you not use the other Chlorine radical instead of the Chlorine molecule for the second propagation step?
Thankyou!! I understood well
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Could you please make a video on Walden inversion
can you do a video on how to set-up calculation for the % of given monobromoalkane product formed
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At 15:00 did he mean to say Br was more reactive than Cl?
no he's right; Chlorine is more reactive than bromine bcuz in group 7 reactivity decreases as you go down the group
28:05
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is this vedio about biology?
No about organic chemistry
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Cl and Br both overall are exothermic, but their first steps are both endothermic (though Br is much more endothermic), so this is not a great graph to use. F on the other hand is super exothermic all the way through so it would be better to use this for the rxn proceeding vs energy graph. So, although Cl is less endothermic, it will still more so resemble the product but still be less selective.
What about the ratios of Flourine and Iodine???
Please 🙏 reply
fluorine reacts readily and hence is least selective in nature,so it just attaches to the carbon free radical with the least steric hindrance,as in if i have propane and i make it undergo fluorination,the major product would be 1-fluoropropane rather than 2-fluoropropane
in case of Iodine,it's very selective in nature and therefore bonds with the carbon free radical which is tertiary in nature(it's more stable due to hyperconjugation),so if i make propane undergo iodination,it's major product would be 2-iodopropane
fluorination in itself is highly exothermic(literally forms bomb),so you wouldnt come across it in most reactions
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CHEM1048