Great trick! For those interested: There are 54 ways to roll four dice (ignoring the ordering of the dice). Of those 15 combos have four different numbers. Of those, 10 combos contain a 6; but only 6 combos can use the 6 as the first die - the other 4 combos need the 6 to make 7 in the middle (with a 1 die). Ultimately, 4 combos can use a 5 as the first die, 2 combos can use a 4, 2 combos can use a 3, and one combo (4321) must use a 2 as the first die. So be prepared to double cut up to 4 cards off the top.
Thanks, I will definitely play around with and try to make it suit my performance style. I might use a normal deck and have 4 blank faced cards at the end say a message like "you" "have" "chosen" "wisely". or do it Face Up and the four ending cards being Aces that have a different colour back to the rest of the deck (this method also has a build up reveal as you see each Ace one by one
4:07 It's actually only a 28% chance that they will roll all different numbers. Definitely not "very high". Given how likely it is to fail, I don't think it's worth getting them to roll them only to then ask them to choose four different random numbers 72% of the time.
This is a good point. However,I think you could just say something like, "Oops, looks like that one is the same as this one. Go ahead and roll it again." Yeah, it's still not the smoothest thing, especially since if you have just one duplicate, it's only 50:50 that a reroll will produce a fourth unique number, and it's even less clean if they rolled three of the same number where you need to ask them to reroll multiple dice. However, as someone else pointed out, I think the trick still works with duplicates if you have at least two dice that sum to 7. So you can quickly check for that
This is very good. I don't normally get fooled by maths tricks but this one got me. I didn't like the reverse counting in the hands, it might be better to just deal those piles onto the table instead.
The second trick would be worked out instantly by most observers I know. But to overcome the lack of a 3, you could increase or decrease the number of piles.
Great trick. A couple of thoughts: Rather than have the spectator roll four dice, have him roll six and pick any four that are different. Instead of using the 'spread-count' sequence, use 'count-spread', and the four cards end up as the top card of each pack rather than the bottom cards.
I was able to see the trick being done here first time watching it. I think it’s strong for people who don’t understand how cars forcing works. Neat though
I don’t think they have to be all different numbers. I practiced it many times with duplicates and it worked just fine. Priority 1: two middle dice need to add up to 7. Priority 2: first die should be a 6. That’s it. He shows exactly how to adjust if the first die is not a 6. But the middle two need to add to 7. Great simple fooler.
Having four different numbers guarantees that you have at least two dice that sum to 7 because of the way the faces are arranged on a standard d6. But it's true, if the participant rolls a duplicate, but you notice that the set still contains two that sum to 7 then you don't need them to reroll
Great trick buddy 😊 I think ile just go with the first part of the trick as my mind is not all with it at present.A lot going on Steven and as a result my mental health is really taking a pounding!!! If you don't see me for a while please don't worry ile be alright.Wishing you and your beautiful family a very happy Christmas and all the very best for 2025.Wished YT had a personal messenger like FB so I could tell you privately ❤
Significant chance that the trick won’t work (rolling duplicates will happen 7 outbid 10 times and there is also the risk of no 2 dice adding up to 7). Given Riese risks of failure, and combining with the fact that you have Tonart up the deck, I would take hundreds of other tricks above this one.
That's why all four dice must have different numbers and also the magician arranges the dice afterwards. If you have four different numbers, you are guaranteed to have at least one pair that adds to 7. Probably the easiest way to see that is notice that opposite sides of a standard d6 always sum to 7*. Pick any three different faces of the die. If two of the three faces you picked are opposite, we'll then your set already includes a sum of 7, and it doesn't matter what you pick for the fourth face. If the three faces you picked don't have two opposites, it means that they all meet at one corner of the die. Any fourth face you pick now will be opposite to one of the first three faces, thus giving you a sum of 7. * if you had a non-standard d6 where the faces were not arranged this way, then rolling four different numbers would not guarantee a pair that sums to 7
Liam Montier released the same trick called “The Defective Deck” a little while ago. Still a great trick, but is this not someone’s marketed effect, or is this in the public domain? Not trying to be negative here, just trying to understand as I like and subscribe to your channel.
HI Scott. The trick was called “Bad Bikes” and I am the creator of that effect, working in collaboration with Liam and Kaymar. It is still being sold so I am not pleased at all with the trick being TAUGHT here. Demo it all you want. But don’t teach someone else’s material WITHOUT THEIR PERMISSION. that is nothing but shameless theft.
It’s called Bad Bikes because Michael Breggar presents it as the way that Bicycle detect reject cards during manufacture. Bought a deck from him at a lecture.
Great trick! For those interested: There are 54 ways to roll four dice (ignoring the ordering of the dice). Of those 15 combos have four different numbers. Of those, 10 combos contain a 6; but only 6 combos can use the 6 as the first die - the other 4 combos need the 6 to make 7 in the middle (with a 1 die). Ultimately, 4 combos can use a 5 as the first die, 2 combos can use a 4, 2 combos can use a 3, and one combo (4321) must use a 2 as the first die. So be prepared to double cut up to 4 cards off the top.
Thanks, I will definitely play around with and try to make it suit my performance style. I might use a normal deck and have 4 blank faced cards at the end say a message like "you" "have" "chosen" "wisely". or do it Face Up and the four ending cards being Aces that have a different colour back to the rest of the deck (this method also has a build up reveal as you see each Ace one by one
4:07 It's actually only a 28% chance that they will roll all different numbers. Definitely not "very high". Given how likely it is to fail, I don't think it's worth getting them to roll them only to then ask them to choose four different random numbers 72% of the time.
This is a good point. However,I think you could just say something like, "Oops, looks like that one is the same as this one. Go ahead and roll it again."
Yeah, it's still not the smoothest thing, especially since if you have just one duplicate, it's only 50:50 that a reroll will produce a fourth unique number, and it's even less clean if they rolled three of the same number where you need to ask them to reroll multiple dice.
However, as someone else pointed out, I think the trick still works with duplicates if you have at least two dice that sum to 7. So you can quickly check for that
Your channel has grown so well because you give a nice, clear and easy to follow presentation and you seem like a likable person.
I can’t believe you only have 50,000 subscribers. By far the best tricks on the Internet.
That was sweet! Had me at the end, love the blank deck ending. Only thing I would do is add a false shuffle at the beginning.
This is very good. I don't normally get fooled by maths tricks but this one got me. I didn't like the reverse counting in the hands, it might be better to just deal those piles onto the table instead.
COOOOOOOOOOLLL GREEEEETINGS FROM QUERÉTARO, MEXICO, JUST LOVED IT, I WILL TRY THIS TRICK IN SOME PERFORMANCE
Love this tricks! This Channel is fabtastic! Congrats! Next time you are in Spain let us know so we can have you in our Magic circle. Tx!!
Another classic trick.👌 Tks for sharing
Cool.love dice tricks, you explain perfectly, two trick in one
The second trick would be worked out instantly by most observers I know. But to overcome the lack of a 3, you could increase or decrease the number of piles.
Great trick. A couple of thoughts: Rather than have the spectator roll four dice, have him roll six and pick any four that are different. Instead of using the 'spread-count' sequence, use 'count-spread', and the four cards end up as the top card of each pack rather than the bottom cards.
Very cool! Thanks! I'll be using this one soon!
Wow.. that's really smart and great idea!
Awesome as always man! Love it!
Appreciate you bro 👊
Nice trick Steven.
V need to remember the position and switch according to dice rolled in case u dont get a six. ❤❤❤❤
Hey Steve Yeah,you Sir gave definitely delivered ❤ Thanks
Very nice!
I was able to see the trick being done here first time watching it. I think it’s strong for people who don’t understand how cars forcing works. Neat though
Another great trick .👍👍
Hola amigo. Una rutina muy bella y el tutorial muy bien explicado. Quien es el autor?. Gracias un saludo y que pases un buen día.
Very cool trick. But one thing you didn't explain. What if you don't have two dice to equal a seven for the middle two?
Excellent trick 😊
Saw how you shifted the dealing of the cards in the beginning. Too easy to figure out.
I love your accent bloke!
I don’t think they have to be all different numbers. I practiced it many times with duplicates and it worked just fine.
Priority 1: two middle dice need to add up to 7.
Priority 2: first die should be a 6.
That’s it. He shows exactly how to adjust if the first die is not a 6. But the middle two need to add to 7.
Great simple fooler.
Having four different numbers guarantees that you have at least two dice that sum to 7 because of the way the faces are arranged on a standard d6. But it's true, if the participant rolls a duplicate, but you notice that the set still contains two that sum to 7 then you don't need them to reroll
Great trick buddy 😊 I think ile just go with the first part of the trick as my mind is not all with it at present.A lot going on Steven and as a result my mental health is really taking a pounding!!! If you don't see me for a while please don't worry ile be alright.Wishing you and your beautiful family a very happy Christmas and all the very best for 2025.Wished YT had a personal messenger like FB so I could tell you privately ❤
You can message me here anytime mate.Wishing you all the best over the holiday season 🫶🏼
Daddy’s bringing home the bacon with this one 😎😂. Very strong
Significant chance that the trick won’t work (rolling duplicates will happen 7 outbid 10 times and there is also the risk of no 2 dice adding up to 7). Given Riese risks of failure, and combining with the fact that you have Tonart up the deck, I would take hundreds of other tricks above this one.
What if no 7 in the middle. Or you get 444?
That's why all four dice must have different numbers and also the magician arranges the dice afterwards. If you have four different numbers, you are guaranteed to have at least one pair that adds to 7.
Probably the easiest way to see that is notice that opposite sides of a standard d6 always sum to 7*. Pick any three different faces of the die. If two of the three faces you picked are opposite, we'll then your set already includes a sum of 7, and it doesn't matter what you pick for the fourth face. If the three faces you picked don't have two opposites, it means that they all meet at one corner of the die. Any fourth face you pick now will be opposite to one of the first three faces, thus giving you a sum of 7.
* if you had a non-standard d6 where the faces were not arranged this way, then rolling four different numbers would not guarantee a pair that sums to 7
Liam Montier released the same trick called “The Defective Deck” a little while ago. Still a great trick, but is this not someone’s marketed effect, or is this in the public domain? Not trying to be negative here, just trying to understand as I like and subscribe to your channel.
HI Scott. The trick was called “Bad Bikes” and I am the creator of that effect, working in collaboration with Liam and Kaymar. It is still being sold so I am not pleased at all with the trick being TAUGHT here. Demo it all you want. But don’t teach someone else’s material WITHOUT THEIR PERMISSION. that is nothing but shameless theft.
Original trick was called 'Bad bikes' strange title...
It’s called Bad Bikes because Michael Breggar presents it as the way that Bicycle detect reject cards during manufacture. Bought a deck from him at a lecture.
😍
I don't think you are fooling magicians with this... I am one and i immediatly sah Thatcher you countdown differently...