Electromagnetic Induction and Faraday's Law
ฝัง
- เผยแพร่เมื่อ 23 ก.พ. 2013
- Electromagnetic induction is the generation of an electric field by a changing magnetic field. Electromagnetic induction is demonstrated using a coil, ammeter, and a bar magnet .
Tomorrow is my practical and tonight I watched this video, now I can do better in my practical. Thank you so much sir.
@Gavin Bryan
Is there anything for Facebook
So how did you Do in your practical
Well it was great
@@Aakashkumar-xl6vh nice
Pichke video waley bnde se bola kuni jarha tha
Love the style of the video. No fancy editing, just simple and concise explanation.
Thanks so much for this this video! The demonstration and the following explanation have made this effect very clear, especially the bit about the resistance being inversely proportional and leading to why we look at induced Emf rather than just current. Really, many thanks!
I love how you draw the concultions sir and it was very helpful
quite good.....video.... beautifully explained 👌👌
Thank you sir . I feel that now I have able to understand better Michael Faraday's law
You've saved lives, sir! I thank you!
you are welcome!
Hi Michael, what specs do you need (both wire and magnet) to make this experiment observable? Are you using a galvanometer?
I have never got this experiment to work well at all.
Yes you have to use a galvanometer. They are relatively inexpensive, www.amazon.com/United-Scientific-MGV003-Galvanometer-50-0-50µA/dp/B00ES3TQZU/ref=sr_1_1?crid=SOM9ABAC34SD&dchild=1&keywords=galvanometer&qid=1590613170&sprefix=galvanom%2Caps%2C222&sr=8-1
كنت احتاج رؤية التجربة حقا
Thanks from Egypt 🇪🇬
You are welcome!
Very simple to understand, thanks give it up.
Michael Melloch,
Thank you so much for responding to my post. Sorry that I was not clear with question 2. The question I wanted to ask is if the Amp Meter was replaced with some kind of load and one end of the magnet (any pole) was passed over the outside of the coil, (in one direction only, NOT Back-and-Forth); how would one determine (without using a Volt Meter), which end of the load would be Positive and which would be Negative?
Thanks for your response.
+Richard Vassell Let's say it was the north end of the magnet facing the coil and then you moved the magnet towards the coil, but on the outside. At first the magnet flux inside the coil would be increasing. You could determine the direction of the current flow using Lenz's Law. Then the end of the resistor in which the current was entering would be at a higher potential then the end of the resistor where the current was leaving, which would be at a lower potential. Now as the magnet passes the coil, but on the outside, you start to have the opposite situation, the magnet flux starts decreasing in the coil and the direction of current in the coil would reverse.
Your explanation is perfect and simple.
thanks
Logan D, the magnet you have should work. Did you remove the insulation from the ends of the copper wire?
Yea, my entire wire is without insulation and is connected to the meter. My experiment seems to be the exact same but the meter is not picking up any electrical readings. Maybe my magnet is not powerful enough?
If your entire wire is without insulation, then you effectively have only one turn and will generate a very low current and probably not detect it. Get some insulated wire and try it.
Thank you sir it did really helped me
Thank you so much sir my tutor taught us this but couldn't understand in which direction the magnet was moved....
But after watching this i got a pretty gd idea abt it and doubts are cleared😌
Thanks sir❤️
You are welcome!
Best demonstration and explanation I have ever seen! 💗💗💗
Thank you!
Your explanation is amazing 😍
thank you! this helped me with my plan and design experiment.
Great video!
Thank you for explaining.
Why does the current increase as you raise the number of spires? Doesn't the wire resistance raise as well?
Thank you for taking the time to produce this video. It was
very well done.
1) Would the result be the same, in terms of the induced
EMF, if the end of the magnet (North or South) was to pass, (not Spin), over the OUTSIDE of the coil instead of
INSIDE (i.e, as in the demonstration)?
2) How would I determine which end of the wire is positive & which is negative?
3) How would I determine the direction of current flow?
Thanks very much for your reply.
+Richard Vassell ) The magnetic field extends from, and spreads out from, the magnet. Wherever the magnet is if you move it there will be some change in magnetic flux inside the coil and a current produced. The magnetic could move alongside the coil as you mention, or never get near the coil. Of course the farther away the weaker the change in magnetic field inside the coil and the smaller the induced current.
2) If the wire is in a continuous loop there is no positive and negative. The electric field in the wire is not caused by charge but by the changing magnetic field. So the electric field lines have no beginning or end. They begin and terminate on themselves just like lines of magnetic flux density. Now if you had a coil that had a break in it, charge would form on the ends of the break and be an additional source of electric field.
3) The induced current is always in a way to produce a magnetic field that opposed the changing magnetic field that is inducing the current. This is referred to as Lenz's Law.
+Richard Vassell I put together a video of what happens when the magnet is moved as you ask.
th-cam.com/video/JGgHe2oiaMg/w-d-xo.html
Thank goodness! I'm glad that I found this channel 😊 Thankyou
Welcome!
@@electricandmagneticfields2314 😊
Good work, I tried many times to understand the concept of faraday's law but I couldn't but when I see this video I got it quickly... Thanks.
I'm glad the video was helpful.
Finally understood that lengthy physics chapter thanks to this!
I'm glad this helped to clarify it for you!
Greater job sir, thanks
Thank you sir, you cleared my doubts
Thx sir ....Very good explanation.
Thanks Sir it is the best explaination I found on internet 👍👍
Thank you for those kind words!
i from iraq and we have faraday`s law in our curriculum so i came here and i was shocked by this wonderful explanation so thank u and i hope to travel to europe when i get out of a school and sorry if i made any spilling mistakes because i wrote this quickly 💞💯
Thank you for your kind words about my video!
Nice explanation pls upload more this type of video😄🤗
شو جميل عاشت ايدك قابل مثل حظي عدنا بالعراق كلشي ما افتهم من المدرس لاتجترب ولاوشي بس تحفظ
تكلم عن نفسك حمبي
مدرسنا سوا التجربة قدامنة بادوات مشتريها بنفسه
Who see this video in 2020 year raise your hand and like.......🙋🙋🏻♂️
🙋♂️🙋♂️🙋♂️
THANK YOU, this help me greatly.
مرحبابك يالقحطاني
Good, discussed something about lenzs law.
Great video
hi michael melloch i have a question that how to prevent a coil (solenoid ) to get hot
If you are manually moving the magnet, you probably are not going to generate enough current to get the coil hot. If you are, you can always put a resistor in series to limit the current.
Love this so much! Real cool!
Thanks!
Straight to the point. How great is that
Thank you!
hi, this galvanometer is only for ampere or also read volt?
Hi, hope ya will answer: Where is the magnet field?? When the bar moves thru forward and backward, forward is magnet field expand depend by speed and how many turns, so the motion thru each level of current is a magnet field. When the level of current change, the magnet field change as well? And there is forward magnet field and backward magnet field which it is called collapsing magnet field to full collapse magnet field. So, opposite of collapsing is building-up. So, backward is magnet field collapse; forward is magnet field build-up. And during the process, it is with -ing. With it is positive current to the negative current that corresponds to forward to backward. There is a higher volt for forward than backward of the same motion time that interacts the load which is a forward position that is receiving the current from backward position. Which backward go forward to the load. But for a double backward position that is in position and in motion.
what the name of the item you put in the Galvanometer in
Michael, you have surely provided the answer to one of my questions; that is, determining the polarity on the load. VERY grateful for that.
This is my final question:
Let's say that your coil was wound on a solid (NO hole in its center) IRON rod, say seven inches in length. The cross section of the rod might be round or rectangular.
How, if you move a pole of the magnet along the length of the coil from left-to-right OR vice versa, stopping about an inch short of the other end, then moving the pole back in the opposite direction, towards the original starting point. Would the current flow be in one direction only and changes ONLY when the magnet is moved in the opposite direction?
Thank you.
+Richard Vassell I am not sure of the geometry you are describing. But there will be no difference whether you have a ferromagnetic material inside the coil or not. There will just be a magnetization occurring inside the ferromagnet, which will change with the changing applied magnetic field occurring from the external magnet. So if the applied magnetic field is increasing inside the ferromagnet because of the movement of the magnet you will get current in one direction, say clockwise, and then if the magnetic field is decreasing inside the ferromagnet because of the movement of the magnet you will get a current in the counter-clockwise direction.
It is really helpful.... Thanku... It helped a lot for my investivatory project...
Glad you found it useful
Hi I am indian 🇮🇳
Friends
Can we see this affect on digital multimeter? Or we need analog one?
I think digital multimeter is more effectively than analog
How to calculate emf by changing magnetic field?
Amazing man.. thanks 🙂 from India 🇮🇳
Thank you so much. It was really helpful for my investigatory project
Smriti if you are there ..i want your help..if you could do ...
My whtsapp no is 8446442067
I am doing some research need a small help..if you could by anymeans
Thank you sir.
What is the least count of the ammeter
easy to understand thank u!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Thank Brother
Hello sir, our thesis is about electromagnetic induction, we're trying to do what you did, but when we tried to measure it with galvanometer, the galvanometer did not even deflect despite it being in nano amperes, please help,
thank you sir
Good experiment
Thanks very much
Yeah u can use
Nice toast! And science facts!
Just wondering if there is a difference in the deflection of the ammeter when you inserted in the coil using the opposite pole instead. ie, if North is inserted first, it deflects to the right and if South is inserted, it will deflect to the left?
A current is generated in the coil to produce a magnetic field that opposes the change in magnetic field inside the coil caused by the moving magnet. So the deflection will change direction if you switch poles before inserting the magnet as you describe.
Can it produce current to light up a bulb
thanks
Is it more accurate to say "the magnetic induces a voltage in the coil" or "the magnet induces a current in the coil", or are they both equally valid?
The most accurate way to think of it is that the changing magnetic field induces an electric field. This electric field is there even if there is no coil. With the coil present, the electric field is inside the coil, which results in a current in the coil.
Thanks a lot sir!!
You are welcome!
Explain polarity of 4 coils when magnet moves across all 4
Hi sir, is it ok to use copper wire ?
What are the calculations for multilayered coils ?
I'm not sure what you are asking.
طلاب المتميزين
الدفعة الاولى منهج انكلش
يا رب توفيقك 🤍
(Thanks from Iraq 🇮🇶)
You are welcome!
Thanks
Can we use Magnetic wire?
Which type of insulation should wire contain .
insulation can be of PVC Or Rubber or of anyother material.
+Abhishek Gupta The insulation should not matter. In this video I was using magnet wire, which has a thin insulation.
I am attempting to conduct this experiment for my science fair project. I ordered the meter you suggested and wrapped a copper wire 100 times. The only part I have set up differently is the fact that my magnet is rectangular in shape. I have not been able to get any reading on the meter. Is my magnet the issue? If not are there any other trouble shooting tips I could try? A response would be great!!!
I know this is an old message, but I will still say a few things. The magnet could be an issue. What is important is that the magnet has the north and south poles on opposite ends and not on the large sides. If it is the large sides, then you have to turn the magnet so that one large side goes in first. The issue is then you need a much larger coil to fit this.
The other issue is this wire has to be stripped but it is not the easiest to see if it was and how well it was. The main way to do it is with sandpaper, but you have to be careful to get all the way around the wire. The way I have been testing this is with a multi-meter and checking for how much resistance there is.
In addition to what the other commentor stated there is something else. Some magners are stronger than others. Rare earth ones are way better than ceramics
How many apt where you able to get? Are you able to store this energy say in a capacitor ?
You could charge a capacitor. This is done in the Faraday Flashlight,
Faraday Flashlight
Nice video
Really very informative vedio
Thank you!
Which type of magnet you used? Is it also possible if we used normal magnet
Any magnet should suffice. The stronger the magnet the greater the change in magnetic flux. So the stronger the magnet the more current you will generate for the same number of turns.
hello sir,
could you please tell me the length as well as width of the coil having 100 rounds. Please tell me and please tell me the quality of magnet.
Thanks hoping for a positive result.
Thankk youu so muchhhh you made my life easy my brain was stuck at this topic thank you thank you!💝💝💝
You are welcome!
Thank you for posting! Through no fault of yours - I can't find a video that shows the galvanometer reaction to a magnet passing across the front of a coil !!?!?!?! Which is INSANE considering that across the front of a coil is the way nearly every motor that ever existed is made! Frustrating. Have you ever seen a motor that runs by inserting a magnet
I know you already found this other video,
th-cam.com/video/JGgHe2oiaMg/w-d-xo.html&lc=z13zu5cgknjaghe5004civgqnqeswrijxhs
but I'll post it here for others in case they are also looking to see what happens when a magnet is moved outside of the coil.
Thanks sir you are te best 🏆🏆🏆
is radius of loop matters
how to calculate emf by changing electric field
That magnet has both the North pole and the South pole, can we take poles into consideration while conducting this experiment?
If you push the north pole towards the coil and get a positive current, then flip the magnet so that you are pushing the south pole towards the magnet you would then get a negative current.
how much ampers does the apmermeter shows when the magnet is moving through 100 loups?
I was able to get about 20 mA when I was moving the magnet as fast as I could.
Can anyone please say me whether it is possible to make glow an led or a bulb with the current which is produced by the 100 loop coil. Please answer me.
How many amps were you able to generate??
The scale is too blurry to read in the video. I don't have that same galvanometer. But I just hooked another galvanometer to the same coil and at the peak was getting about 0.2 Amps.
that was really great thank u so much
You are most welcome!
You are feeling current?
good video
Thank u so much 🤩🤩🙏
You are most welcome!
can you pls give the readings
Michael what was the connectors called that allowed you to connect the copper wire to measure its current
Do you mean the alligator clips?
yes thank you
We have been lighting LEDs using this principle, which is failrly simple. Question would it be possible to produce say 3v or more in order to run a 3v motor instead of an LED?
This is the principle behind all electric generators, so yes you can produce 3 V. The faster the change in magnetic flux the great the electric field intensity generated and hence the greater the voltage.
Thank you for answering. That makes perfect sense
yes, increase the rate of change of magnetic flux and you increase the voltage produced, V = - (dpsi/dt)
What is the approximate voltage and current that is developed in the 100 turn coil ??
I redid the experiment and I was able to get about 20 mA peak current when I was moving the magnet as fast as I could. I measure 1.7 ohms for my 100 turn coil, which is about what I expect from calculations. So producing about 34 mV.
There is a movie on you tube about Micheal Faraday. Starring Micheal Kitchen. It is called Faraday's Dream.
Thanks, I look forward to watching it.
Please tell me how to do the same experiment but by changing magnetic field not by changing no.of turns and velocity
You could rotate the magnet inside the coil like this,
th-cam.com/video/O5n6ubrbK5A/w-d-xo.html
Will the observations change if the south pole was put first, instead of the north pole?
Why does the needle deflect backward when the magnet is pulled out? (current is scalar)
And, will anything that disturbs magnetic flux become conductive?
Also, thank you for the great video.
As the north pole goes towards the coil, there is an increase in magnetic flux into the coil causing a current. When you remove the magnet, there is a decrease in magnetic flux into the coil that also causes a current, but now in the other direction. So if you flip the poles, the direction of the current will flip. As you push the south pole towards the magnet the magnetic flux into the coil is decreasing because it is pointing out of the coil. The changing magnetic flux causes an electric field and why current flows in the coil, it does not turn something into a conductor. Hope that helps.
That did! Thankyou a lot!
Will a normal insulated wire work?Or do I need a thin insulated copper wire only?or specifically a thin insulated magnet wire?Also does the magnet need to be strong enough?
Any insulated wire will work. The electromotive force produced is proportional to the change in flux linkage with respect to time. Any magnet will work but the stronger the magnet the greater the change in flux linkage with respect to time and the greater the current produced.
Thanks dude,I tried out the same experiment using a rather thicker wire than yours like a normal wire but my galvanometer shows no deflection?? Can you suggest me any further suggestions....
You used a galvanometer and not an ammeter?
Michael Melloch but my galvanometer should also show a deflection right?
If you have a galvanometer it will work because a galvanometer will be responsive to a pulse of current. A regular ammeter will not.
Great stuff! But where exactly is this used in everyday life?
This is one of the most significant discoveries and it is used many place.
It is how most of the electricity is produced by utilities, with AC generators, th-cam.com/video/O5n6ubrbK5A/w-d-xo.html
It is the principle that is used in transformers, th-cam.com/video/mRQqqSxBRSs/w-d-xo.html
It is the principle used in braking and battery regeneration in electric vehicles, th-cam.com/video/MglUIiBy2lQ/w-d-xo.html
It is used in non-destructive testing.
Etc.
@@electricandmagneticfields2314 Thanks a lot!!
I wish my class teacher's teaching was like you
Atleast 10%
Thank you!
Sir why galavanometer is not used in this demo and ammeter is used any particular reason. If galvanimeter was used the deflication would be significant because galvanometer is more sensitive and use for small scale of current.