Very clear explanation. The very beginning was super helpful with the hint that I was missing the d=rt. Moment I heard that I solved it then. Thank you.
Thanks for this, something that worked for me was to model the situation as c^2 = (150 - a)^2 + b^2. This way, you don't have to worry about negating the 35 [km/h]. I'm not sure if this is more or less complicated though :-)
At 10am a ship A is at a distance of 40 km to the east from a ship B. Ship A moves at 12km per hour towards west and ship B moves at 16 kmph towards South.when will be the distance between them be minimum and what will be the value of this minimum distance? Request to provide detailed solution
c^2 = 10^2 + 100^2 = 100 + 10000 = 10100. Now take the square root of both sides so that c = sqrt (10100). Break the sqrt (10100) into sqrt (100) * sqrt (101), which simplifies to 10sqrt(101). Does that help?
My God. Short, simple and to the point. You're better than Khan academy in my opinion.
+Shakespeare That means a lot, especially coming from Shakespeare :)
to DIfferentiate or NOT To differentiate.. THAT is the Question...
thats a sure thing ... it is really quick n easyy
Thank you. You made this problem a lot easier than it looked. :)
Thanks for saying so!
Very clear explanation. The very beginning was super helpful with the hint that I was missing the d=rt. Moment I heard that I solved it then. Thank you.
This is an incredibly good explanation of what I just went to in class.
Explained it far better and clearer than my TA.
Thank you sir! Great explanation! I understood really well!
Thank you for your guidance!
Perfect explanation. Understood clearly. Thanks!!
Thanks for this, something that worked for me was to model the situation as c^2 = (150 - a)^2 + b^2. This way, you don't have to worry about negating the 35 [km/h]. I'm not sure if this is more or less complicated though :-)
At 10am a ship A is at a distance of 40 km to the east from a ship B. Ship A moves at 12km per hour towards west and ship B moves at 16 kmph towards South.when will be the distance between them be minimum and what will be the value of this minimum distance?
Request to provide detailed solution
Thanks so much you saved my life
I still don't understand why the da/dt equals negative 35. Can you explain it clearly for me?
becuase it's technically a negative number, as it's moving east its going negative
@@chillgamer3171 im confused by this too. Wouldn't it be positive as it is going east and negative as it is going west since it is going to the left?
Thank you so much sir, great explanation
Thanks! You were very helpful!
Solved this 2x with the wrong diagram... Hate these word problems.
Thank you so much
that is really useful and simple. go ahead brother
thanks WNY tutor
Thank you
That was good one ☝️
OMG thank you saved my life!
i cant believe my professor used this question without even changing the numbers...
A boat travels 40degrees north of east for a distance of 400km. How far North and how far East of its starting point does the boat sail
i don't even know
This save me thanks!
thank you
謝謝
感謝
THANK YOU !!!
how did you get the 10 sqrt(101)?
c^2 = 10^2 + 100^2 = 100 + 10000 = 10100. Now take the square root of both sides so that c = sqrt (10100). Break the sqrt (10100) into sqrt (100) * sqrt (101), which simplifies to 10sqrt(101). Does that help?
thank you so much WNY Tutor
No problem.
i love u
ughh I did everything right except I forgot to make dx/dt negative. Ugh... .. ugh..
I love you.
correct