Redox Reactions 03 || Balancing a chemical Equation By ion- electron Method or Half Reaction Method
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Class 11 chap 8 | Redox Reactions 01 : How to Find Oxidation Number- Methods n Tricks JEE MAINS/NEET
• Class 11 chap 8 | Redo...
Redox Reactions 02 || Oxidation and Reduction & Types of Redox Reactions IIT JEE MAINS / NEET |
• Redox Reactions 02 || ...
Redox Reactions 04 ||Balancing a Chemical Equation By Oxidation Number Method IIT JEE MAINS /NEET
• Redox Reactions 04 ||B...
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10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
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The test series follows very logical sequence of Basic to Advance questions.&
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Class 11 chap 8 | Redox Reactions 01 : How to Find Oxidation Number- Methods n Tricks JEE MAINS/NEET
th-cam.com/video/c06C1t0PnGk/w-d-xo.html
Redox Reactions 02 || Oxidation and Reduction & Types of Redox Reactions IIT JEE MAINS / NEET |
th-cam.com/video/5Bf_Qk_YSI8/w-d-xo.html
Redox Reactions 03 || Balancing a chemical Equation By ion- electron Method or Half Reaction Method
th-cam.com/video/vf6PiQVK6oU/w-d-xo.html
Redox Reactions 04 ||Balancing a Chemical Equation By Oxidation Number Method IIT JEE MAINS /NEET
th-cam.com/video/v6D5eETBQk0/w-d-xo.html
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Alakh sir u should consider this
Sir std:- 11 chapter:-9 hydrogen leacture
Please upload
Sir redox Mai titration padha do plz sir...... Titration ke sums Mai bohot problem aa raha hai
I donate rs 200000 thanks to me
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stolen comment
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Nothing can complete with Alakh sirs explanation and experience.
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I agree❤❤ the old videos are diamond💎💎 not gold
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Indeed
exactlyyy there are many from pw rn but these are the besttt and shortest tooo
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Who else watches his old lectures instead of new ones?
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Mee yaat
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O, sir
me too bro
sir ji pr bharosa hai 😍😍😍
Bhai NCERT dekhna bhi zaroori he
@A to Z Videos grow up kid dusro ki chori ki hui videos se badhna chahte ho To kabhi grow nhi hoge
Or ha agar tere dad ko ye pata chalta h ki tu aisi baate likh rha h on social media just to gain some dead subs kya bitegi unpe
Shame on you!
@@samarthh6528 🤣🤣🤣🤣
27:25 Sir i did both
(1) > 2MnO4- + 5C2 O4 2- + 16H+ ---> 2Mn+ + 10CO2 + 8H20
(2) > 3C2 O4 2- + Cr2 O7 2- + 14H+ ---> 2Cr3+ + 6CO2 + 7H2O
Yes sir,they were really interesting.
👍
Same answer
Same answer....
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@@LokeshXahlawat right
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27:21 1) Charge is balanced +4
2) Charge is balanced +6
41:00 1) equation is balanced charge=-1 LHS=RHS
2) equation is balanced charge=-1 LHS=RHS (NOTE: sir has written wrongtake only Cr on LHS instead of Cr(OH)3)
Thanks bro
I was confused regarding this
Thanks ❤
Or take CrO4^-2 on RHS
Thank bro it was giving difficulty...
No bro you are wrong on 41:00 1) equation is balanced charge=-2
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Jisne tujhe banaya"
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Tauba tauba saara mood kharab kr diya
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@@ManjuSharma-xe1tz Kya matlab? Gaali khane ka shok h Kya?
@@neetaccelerator9627 kha Ka Don h Tu gandu
Aaj mujhe sunne ko mila ye apni gf se'
Kon kon sir ki new pace series ko na Dekh kr 2 years old video Dekh rha hh because 🌏 alakh SIR ko koi bhi replace nhi kr sakta .💗💗 Those who feel like it.💥💥💥
Hmmmmm
👍
Very 👍
Thanks sir very good lacture
Isse bakwass comment maine apni jindagi me kabhi nahi padha!!🤮
Aapke ye old videos hame hi nhi hamare aane vaali 10 generation ko kaam aayegi......😂😂😂😂😂😂
Haha right 😂
Sahi bola 😅😊
Jo log Sir ko as the physics best teacher in the world mante ho like maaro
Physics and chemistry both
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Tu huttttt
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ek like vo log maaro jinhe
alkh sir ke 2x aawaj ki aadat lag gai hai
1.5x
@@medico.dhanjit1915 hn 1.5 x mein samjh ache se ata hain aur kahi kahi jagah ben 10 jaisi aawaz lag rhi thi ultimate wale ka 😂
1.5x bro😎😎🤘
Nonsense
High light kar ke kya kor loge idiot
Whiteboard And blackboard explanations are the best.
Yeah.
Noice
At 18:24 why does he not count cr2 and said it is 12
@@finite805 the -2 charge is for the whole cr2o7
And hydrogen is losing 14 electrons, so 14+(-2 electrons of cr2o7-2)=12
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Answers to 1st and 2nd Homework questions are as follows
1. 5C2O4^-2 + 16H^+. +2MNO4^- ------>. 2MN^+2 + 8H2O. + 10CO2
2. 3C204^-2 +14H^+. +. CR207^-2 ------->. 6CO2 + 2CR^+3 + 7H2O
I HOPE THAT IT WILL BE CORRECT AND WILL HELP EVERYONE 🤗
Yes bro I am also getting the same answer.
Smartness Kahi aur dikhana
Same ans....thanks
Yes same ans.
Ye BHI bta Do....kse Hoga....Cr(OH)3+IO3-=Cr3+ +I-
Sir ne ye question BHI homework m Diya tha.....yha p Cr ki OS change hi nhi hui to oxidation half rxn kse bnegi?
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Answering the question at 27:36 is
A) 2MnO4-+16H^+ +5C2O4²-=10CO2+2Mn²+ +8H2O
B) 3C2O4²-+14H+ + Cr2O7²-=2Cr³+ +7H2O+6CO2
Correct think so😁😁
Correct hai 👍
mera B) ka 28H+ aur dusre side 14H2O a rhA hai
srry wrong hai galat bnaya hu
Second wale me cr balanced nahi hai
@@monuthakur8882 same here
Soch rha hu Mere school teacher aapka vídeo dikha du
Shayad kuch padhana aajaye😂
Thanks Sir
Tum astrology ho
Like chahta h
Pull
th-cam.com/video/-y3jf653_Pc/w-d-xo.html
Very funny video 😂
What is the answer of basic medium hw 2nd question
Final Balanced equation for the last question is:
3 I2 + 6KOH ----------> KIO3 + 5 KI + 3 H2O
mera bhi same hai
Same here also
yes i got it
kaise solve kiya bhai
Solution ka pic mail kr to please koi
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51:15 Sir breaking the fourth wall 😂
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Answer of question at 58:42 is
3I2+6KOH ----> 5KI+KIO3+3H2O
Therefore, the value of x is 1
Perfectly correct I got same
Perfection
Yes it is right
Right
I did not get the answer 😥
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H.W. Q1 Ans is 16H{+} + 2MnO4{-} + 5C2O4 {2-} ----> 2Mn{2+} + 8H20 + 10CO2
Q2 Ans is 3C2O4 [2-] + Cr2O7 [2-] + 14H[+] -------> 6CO2 + 2Cr [3+] + 7H20
Hope im right
Absolutely
Basic?
@@random.499 ?
@@arunmishra5615 Basic ke Equation ko balance nhi kiya?
@@Uehehdjdjsh Nhi
41:35 me Cr3+ ki jagah CrO4^2- aayega and usse ans sahi aa raha hai 👍
Thnx bhai yhi confusion thi ki uska oxd no. Same kaise hai dono mai
Thank u
Mera bhi same hi doubt tha
@@vishnusinghchauhan3993 1st yr ke 3 aur 2nd yr ke 3
@@vishnusinghchauhan3993 ihave finished my 2nd yr and now preparing for entrances
Question at 40:45
Zn + NO³- → Zn²+ + NH³
Oxidised half -->
( Zn →Zn²+ + 2ē )×4
Reduced half -->
NO³- → NH³
NO³- → NH³ + 3H²O
9H+ + NO³- + 8ē →NH³ + 3H²O
Adding both halves :
4Zn + NO³- + 9H+ → 4Zn²+ + NH³ + 3H²O
Adding OH- to both sides...
4Zn + 6H²O + NO³- → 4Zn²+ + NH³ + 9OH-
Is it correct? :/
Yes i think so
ii part
@xpion22 dragzuhan hihihi so it's wrong thanks💚
Yes bro my ans is same
@@yatharththapliyal405 I think the electrons are not balanced. Ek baar check karna
answer of 42:05
1) 4Zn + 6H2O + NO3^- = 4Zn^+2 + NH3 + 9OH^- 2) in second sir made a mistake on product side instead of Cr^+3 Cr3O4^-2 will come and the answer for that is 2Cr(OH)3 + IO3^- + 4OH^- = 2CrO4^-2 + 5H2O + I^- I hope this will help you
Thanks
HEY SIS IT IS CrO4^2- AND NOT Cr3O4^2- BTW TQ SO MUCH
bhai Cr3O4 nahi aayega CrO4 aayega nahi to tere answer me Sirf CrO4 nahi aata 2Cr3O4 aata ek baar check karna
Correct
Thanq
5 years But Still Top Recommended !! ❤❤
Ans of HW questions 🤗🤗🤗
1) 5C204 ^(2-) + 16H^(+) + 2Mno4 ^(-) →10CO2+ 2Mn^(2+) + 8 H20
2) 3C204^(2-) + 14H^(+) + Cr207^(2-) → 6Co2+2Cr^(3+)+7H20
Plzzz correct if am wrong ☺️☺️☺️
Correct!🙌🏼
Correct
Correct 👍👍
But charge nhi balance h na 🙄🙄
Correct
Best teacher of physics and chemistry 👍👍
Yes you are right bhai
+counciller
No doubt
Yup
@@sankulkunjara7607 yes you are right
Baithe baithe kya kre 🙎♂️krna h kuch kaam 😂... Shuru kro chemistry leke physics wallah ka naam 🌹😂
Wow
Kon sa class me ho aap
Iam from Nepal. Now in 11 standard. I am getting too much help from him.❤ Love you sir❤.Love from Nepal to Alakh sir and all indians sister and brothers too.
are from ktm
@@prajwal-fj7xd8ot6f yes .
@@strugglingboy10 which college
@@prajwal-fj7xd8ot6f KMC . And you
@@strugglingboy10 prasadi
answer of the hw question are as follow :-
1) 5c2o4- + 2mno4- + 16 h+ --> 10 co2 + 8 h2o + 2 mn+2
2) 14 h+ + cr2o72- + 3c2o 2- --> 2cr3+ 7h2o + 6co2
Yes mera bhi sahi hai
yes its correct
Aa gaya
Thanks for confirming
fist wale me 5c2o4 ki power 2- he.....,.
Mera bhi aa gaya thanks bro
Sir ji last ka coefficient of x = 1 hai ..😊😊
Thank you very much sir ji 😊
Final equation is 3I² + 6KOH -----> 5KI + KIO³ + 3H2O
@@Rohitkumar76046 See if you can divide your whole equation by 2. After dividing mine x comes out to be 1
After too much struggle, my final balanced equation comes out to be - 6I2 + 12KOH ----------> 2KIO3 + 6H20 + 10KI, AFTER dividing this by 2 , coefficient of KIO3 comes out to be 1
Same 🤝
Mera ans to kuch or hi aa raha hai ....
I2 ka cofficient 5 aane ki wajah se 2 common hi nahi aa raha😴
The most amazing teacher I have ever found ❤️🌹💐🔥
Bhai tera ionic equilibrium ho gya??
@@CineClipindia nhi bhai
Ha Mera to ho gya
Right bro
@@anuragpatel9922 kya ho gya bhai 🤭🤭
THIS VIDEO IS 1 HOUR LONG BUT I TOOK ME 2 HOURS TO COMPLETE 😂😂
Yes sir done 😇
58:47 3I2+6KOH------>KIO3+3H2O+5KI
Therefore, x(coefficient of KIO3) =1
Thank you sir itna accha parane ke liye
Exactly bro🙏
Great 👍👍
@@Vatsalzaprat 2 common lelo dono equation mai fir katke 1 aa jayega
@@Vatsalzaprat koi na kabhi kabhi hota hai
@@Vatsalzaprat yes bro
Last question-
Ans_ xKIO3=KIO3 then.....
x=1
3I2+6KOH------->KIO3+5KI+3H2O IS THE BALANCED EQUATION
same here bro
Same
@@shrutisharma7356 yes correct
Yessss 😉😉
Same as👍
3I² + 6KOH --------> 5KI + KIO³ + 3H²O
So , xKIO³
here, x = 1
Same 😊
bro superscript nahi subscript me likh dete
@@OK-fo5tm accha bhai
Sir the Answer for the 1st question in HW is
(5C2O4)2- + 16 H+ + (2MnO4)- -> 8H2O + 10CO2 + 2Mn2+
@@KaranDubey-gf4im baigan bc
Sir I salute your teaching style 🇮🇳🇮🇳👍❤
Bkp 😂😂
Bro how will we know that the reaction is acidic or basic?
Bhai ion mai kaisai convert Kartai hai? Plzzzzz helpp
@@bakasta4907 likhke aayega ki acidic hai ya basic
Sir congratulations having 1.9m subscribers,😍✌️✌️✌️✌️🤘🤘🤘🤘and if u are happy from this achievement of alakh sir then like
Now 2.17
2.18
But now sir is going to cross 3 M
Now it is 2.36
Now it is 2.41 M
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Value of x is, x=1 58:56
Thank you for this amazing lecture ❤
Can u tell me how u came with 1? I am getting 2
@@Saharsh__Raj i gusse x=2 , mera bhi 2 aarha hai
@@Anamkhan-kt3vs @Saharsh_Raj are dono answer shi hai ..unhone bas usko simplify krdia hai puri equation ko by dividing it by 2... toh x ki value 2/2=1 aajayega
@@RiyaNegi121 yess both answers are correct..
But right answer 1/3 hoga.kioki h2o ka coficient 1 karna hai.
Alakh sir tussi grt ho. Actually i am a jee 2023 aspirant from lakshya jee 2023 and i am having heavy backlogs of class 11th. so today(sunday) i decided to cover this chapter from sir lectures. I started studying on arund 8 pm and now its 1 40 am and i completed 3 lectures with full notes all questions and full confidence till this part. in tomorrow morning i will complete the remaining one lecture and practice some questions and again start my 12th. Literally if i have this type of confidence in only some of the chapters in my 11th then my condition is far better than now. Now i will complete one more chapter on next sunday.
GUYS ALAKH SIR OLD LECTURES ARE LIKE A "GOLD MINE- KGF" FOR JEE AND NEET ASPIRANTS FOR THEIR PHYSICS AND CHEMISTRY.
Love u alakh sir and thank u so much
@ vlogger jee you are able to solve all jee question of this chapter
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Boka
insta do
Really bro
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41:32 there should be CrO^4 on right side and answers comes to be
4OH^-1 + 2Cr(OH)3 + IO3 ^-1 ---> 2 CrO4^2- + 5H2O + I^-1
Yeah
Thanks
Thanks bro
Pehle wala samaj nahi aaya
Bro teri balanced eq sahi hai?
Yes
Sir basic medium ke balance me chromium ka oxidation state change nahi ho raha hai isko kaise karte hai.
Anyone have same doubt pls like or ask for doubt to our respected sir by commenting
There is CrO4(-2) in place of Cr(+3)
Then it's ok bro! Keep studying 😎😎🙂
@@av9756 thanks
@@av9756 thanks bro because l was also having the same doubt.
thanks A V
the day i found you was the luckiest day of my life.......
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Mobile se nahi padh sakte bhai
Dropper ho
Ya class 11 th Ke student ho
i got 2nd in 10th vlass in my schl my director allso says me the same...i can afford coaching,,,,,but mera view h ki bhalehi 3 attempts se crack krun mgr khud ki dam par,,,i hate coachings
Jo log aisa kehte hain to unse keh do ki aap jitne time mein mujhe dekhte hai ki mai kya kar raha hoon aap utne time mein kuch aisa kijiye ki aap ka bhi koi naam ho
48:55 my answer for this h.w. question is
3Cu + 8HNO3 -----> 3Cu(NO3)2 + 2NO + 4H2O
Mera bhi same hai
I don't get the answer can u explain in ions equation form
@@l.dangthingcharanga9679still need one?
Mee too
No words to admire your lecture sir , this is excellent .
Aandhi aaye ya tufaan mai tumhe padhaunga sir ne ye baat jyada hi serious le li! Salute u sir 🫡
The Ans of the first two question is ;
1:- 16H^(+1)+5C2O4^(-2)+ 7e^(-1) + 2MnO4^(-1)--------->10 C02+ 8H2O +2Mn^(2+)
2:- 14H^(+1)+Cr2O7^(-2) +3C2O4^(-2) +6e^-1---------->2Cr^(+3)+7H20+6CO2
Galat hai bhai
Ek bar phir se check kar lo ans
@@gauravtripathi8512 kaise galat h
Because you write the electrons
Think its correct!
41:35 The second equation given by sir is not REDOX as, Chromium's Oxidation State does not change
Yes bro
There is cr2o4 minus 2 charge
Yes you're right bro
Exactly
@@dance_with_pallavi614 yaa so what shall we do?
Tomorrow is my chemistry test and thanks to sir I finished maximum preparation in short space of time
Bless me sir🙏🙏🙏
ALL THE BEST TO ALL FELLOW STUDENTS!!!👍👍👍
How did it went ?
REACTION=
CU+HNO3=CU(NO3)2+NO+H2O
BALANCED REACTION=
3CU+8HNO3=3CU(NO3)2+2NO+4H20
JISKA YEHI SAHI ANSWER HAI YO LIKE KRE👍👍
Lecture dekhne se pahle hi feel de diya😍☺...... Ye h knowledge se pahle feel😅 wo bhi basic redox rxn balancing me🤣🤣hats off sir🥳🥳
Aur lectur completed..
3I2 + 6KOH ---------> KIO3 + 5KI + 3H2O
41:31
Q1) 4Zn + NO3- + 6H2O ----> 4Zn2+ + NH3 + 9OH-
And for the second one I think that Ques is wrong but I put. CrO42- instead of Cr3+
Then I got this Ans i.e. 2Cr(OH)3 + IO3- + 4OH- -----> 2CrO42- + I- + 5H2O
Aree bhai same pahla wala
Doosre wale me cr ka oxidation no. Change hi nhi hua na 😕😕
Toh redox reaction hi nhi hua
*कहो मुकुल*
*कैसन बा लाल*
@@randomthings5432 sahi hai bhai
@@ulsh7124 ha but mujhe ek esa hi similar question mila tha jisme Cr3+ nhi tha
Wow! Sir 4M subscribers ❤💞, to up soch lo ap khub jada behetar tarika may parate ho❤, love u
X=1 / 3i2 + 6koh -> kio3 +5ki+3h20
Great lecture sir thank you 😊
👍 done bro
@@AsthaMaurya-vt3ir X=12
same ans
X=1 right?
X=1 aa rha h par
(3) - 4Zn + 6H2O + NO3- --------- 4Zn2+ NH3 + 9OH-
Absolutely Correct... 👌👏👍
Mine is same sa well
Can you give full explaination
Same here
Mera bhi yh hi h
Comment section me homework ke answers ke alawa sab miljata hai
Coefficient of KIO3 is 1
Value of x in the question at 58.35 is 1 The balanced equation is
3I2+6KOH ----->5KI+KIO3+3H2O
Correct
M
Bhai 6 I k reactant mai liye to 6 p mai bhi loo
@@nandanitiwari4955 kya bol rahe ho sahi to hai , mera bhi yhi aya.
kaise ho raha hai kar do
42:57 to find te oxidation state of Cu (products side)...
1st find the oxidation state lf N ( nitrogen)... NO-²3 ... N as 'x' and then
x + 3(-2) [oxidation state of atoms of oxygen (-2) ]
x - 6=-1
x=5
Oxidation state of N is 5
Now... From Cu(NO3) 2.....
Let oxidation state be 'x'
x + 2 atms of N * oxidation state of N(5) + 6 atoms of oxygen * oxidation state of oxygen (-2)
x + 2(5) +6(-2) = 0
x-2=0
x= 2
Cu has thus oxidation state +2
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For all dude
sir , I've never met with one of the greatest teachers like you .......as soon as i see your videos , I'm able to understand all the concepts really quick. thank you very much sir.
Very Very Very thank you sir , just because of you I can balance redox reaction ❤
there's something about his teaching that makes him better than the other teachers.. his lectures>> always
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It's best teacher in world always best teacher love you alakh sir ❤❤ I watch this video in 2024
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That's me😁
Basic started from 28:27.
Like if helpful..
basic medium answers
1) 4Zn + 6H2O + NO3- gives 4Zn2+ + NH3 + 9OH-
the second question is a mistake. actually the question is
Cr(OH)3 + IO3 - gives I - + CrO4 2- and the answer for this question is
4OH- + IO3 - + 2Cr(OH)3 gives I- + 2CrO4 2- + 5H2O
Wrong
First one 5Zn aaya gaa
@@shahid.bhat.vlogs-2399Nhi, 4Zn hi aayega
@@shahid.bhat.vlogs-2399 mera to 4Zn aaya and its actually correct
Ha 4Zn hoga
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Jaisa hi second lecture padh k khatam kiya
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Love u sir😘
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Please speak in English
@@debasishmahapatra6501 Its not like that everytime We have to speak in English We also have to speak in Hindi Bcoz Hindi is our मातृभाषा And second thing who are you 🤔telling me to speak in English I am comfortable in Hindi so I comment in Hindi😑🖕
@@crusheryt5751 😆
@@sensei680 kya hua bhai hassa kyu
@@debasishmahapatra6501 chup bengali
Sir your way of teaching is very interesting ❤ Thanks Sir ❤
59:00 answer: 3I² + 6KOH ➡️. KIO³+ 3H²O + 5KI.
So the coefficient of I in KIO³ is x=1. 😘🙏
yes, i got the samee
@@mahitrasaraf4476 pls help me I am not getting right answer
@@animeforlife3151 watch anime you'll get the right answer 🙂
@@Vintage598 I was just getting confused in 12K
@@Vintage598 also I didn't asked from u , so there was no meaning of reply from you , look like u lack basic sense and ur parents haven't taught u 🤣🤣🤣 poor child
27:20
1. MnO4- +C2O4 ^2- +8H^1+=Mn^2+ +4H2O+2CO2
2. 3C204^2- +Cr2O7^2- + 14H^1+= 2Cr^3+ +7H20+6C02
mno4- + 5c2o42- gives mn2+ + 10c02 + 4h20 @ 27.30
@@gowthamthevipre2609 2MnO4-+5C2O4-2+16H+=2Mn+2+10Co2+8H2O
@@santoshkumar0005 mera bhi yahi answer aaya.. jo apka aaya hai.
Three teacher more than enough to crack neet of at free of cost , no burden ,no hostel fee, institutions fee, no pressure,no depression if u study or follow since 11th
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i am fearing for my thumb @ft. Eklavya
this video will still be the best video of redox in 2030..
Yes for sure. ❤
just only bcoz of you sir i understand this chapter bcoz my teacher in aakash taught us this chapter in only onen day by taking two classes of 1.30 hour each .and i got only confusions from him the only thing i understand in 3 hours is how to find on .thank you sir so much
True yr
Sir Yautaa long questions laee method maa solve garnu n ....
Mere aakash ke class me toh sir 4-5 lecture me complete kiye hai