@@SkanCityAcademy_SirJohn there's 2 cables on the ground, both have 1000 volts and 0,2 amp. Lets say that 0,2 amps makes me fell tingling and 0,4 makes fell pain, if i touch in both cables at the same time i will fell pain or tingling? Superposition theoreme is applied to humans or not?
i have one question in 15:39 you took 10//4, but in 12:00 you took 5+5. They are the same, but why is the one at 12:00 is in series and the one at 15:39 is in parallel ?
Great In 15:39, 10 and 4 are connected to the same two nodes so parallel In 12:00 5 and 5 are connected to each other end to end. Hope you will understand
@@SkanCityAcademy_SirJohn hmm, okay. How do you determine the nodes then? because the original circuit had no nodes(dots on the line). Is it because when you solve for the voltage source, the current source becomes an open circuit? and when you remove the voltage sources and solve for the current source, the voltage source becomes a short circuit? so does the open circuit doesn't create a node but the short circuit does? sorry for the disturbance. I appreciate your help🙏.
We want to find the current in 8ohms, but since 8 is in series with 10, the current in 8 will be the same as the current in 10. Since current division is applied to two resistors at a time we need to combine 8 and 10 in series which is 18, before we divide the current amongst 18 and 6.
It is so because, the current divides at the node connecting the 4 and 10 ohms after flowing through the 7.8571, at the end the current combines and again and flow through the 5 ohms
There is no particular trick. The idea is since the currents I8' and I8'' flow in the 8 ohm in two different directions, you can choose to make either of them positive or negative. But normally for me, I make current in moving to the left negative and that moving to the right positive.
You need to combine the two parallel resistors and add to the series resistor, that will be the total resistance. Then if you know the source voltage you can use voltage division to solve for the current in R1, meanwhile the approach also depends on the position of the resistor you are interested in
@@SkanCityAcademy_SirJohn i have a picture that would make it clear but cant upload it here. I want to go through this and get it right, but im unsure. I know you work out the figures for each power source first. Trouble is if i make a mistake the whole problem goes wrong
sir in minute 15.53 i think it should rather (5//4)+10. As the current is coming from resistance 10, and that current is the one that's shared between resistance 4 and 5.
No please, look at it this way. The 4 and 10 are parallel resistors since they are connected to the same two nodes. Instead of using the usual direction on the current source, take it the other way around.
Great video sir...but on the second example..is it wrong if we consider the current I4' that's acting downwards to be negative and the one acting upwards I4'' to be positive?
Also for example 1, where the current in 8 ohm is 4.5A, is it 4.5A because the current divides equally? Would the current always divide equally where it splits into two paths only?
Why didn’t you use current divider rule when 9v acts alone to find current through the 8ohms resistor because the step you used was a little unclear to me
we could not do it straightaway because current division is applied to only two resistors at a time. So the best thing is to combine the resistors in the circuit first to obtain only two resistors before you divide the current among them.
Good example ..,just a quick question when we now considering 9A current supply do we include the 3ohms resistor since the voltage source is now short cct
Okay, you need to understand that, for Parallel resistors: they share the current approaching their common node. Or they are connected to the same two nodes or junction. Series resistors: the same current flows through them
If they have different resistors different current values will flow through them, so you need to us current division. The deal is, even when the two resistors are the same or not we still use current division rule. Just that when two resistance have same value, half of the total current is what flows through them.
Why in 1st example we are converting the circuit in 2 10 ohm resistors when we can easily get it by taking ratios I guess the answer given is quite not right.
I solved it that way so that everyone can understand. And that is the correct thing. If you want to use ratios, that is good but you need to arrive at that same answer.
I solved it that way so that everyone can understand. And that is the correct thing. If you want to use ratios, that is good but you need to arrive at that same answer.
this is because in the first question, the two resistors sharing the 9A current were the same (10 ohms each), so current will be divided equally between them. But for q2, the two resistors have different values hence they cannot share the same current.... i hope you understand
so you know, we had 6A approaching the node, and we want to find the current in the 8ohm, but the current that passes through the 8ohm is the same through the 10ohm because they are in series, so we add them, then we apply current division rule at the node. Hope you will understand this
That has been clearly explained. Current approaching the node is 6A And we have (8+10) and 6 connected in parallel. Now to find current in 8 ohms, then it's basically 6/(18+6) * 6 which is 1.5A
Yes please. That is what I have explained in my first comment. That's the current division. We want to find the current in the 8 ohms. But 8 is in series with 10 which means same current will flow through them. So current in 8 Ohms is, 6/(18+6/ * 6A = 1.5 A
eveything is well understood...but why should we assume that the I8 ^1 in the 45V acting alone should be negative....shouldnt it be a standard something??why the assumption????
I get you. But it's not about it being a standard. Once the two currents are pointing in opposite directions, then one is a negative current, I just wanted the final current value to be positive hence choosing the current with less value to be negative. It can also be the other way round. It doesn't matter, provided the final current value is the same, disregarding whether it's positive or nagative
Explained something that my lecture failed to explain in 2 days, in 20 minutes.🙌
Thanks so much
@@SkanCityAcademy_SirJohncan i make a question about superposition theorem?
Yes please, you can
@@SkanCityAcademy_SirJohn there's 2 cables on the ground, both have 1000 volts and 0,2 amp. Lets say that 0,2 amps makes me fell tingling and 0,4 makes fell pain, if i touch in both cables at the same time i will fell pain or tingling? Superposition theoreme is applied to humans or not?
@@SkanCityAcademy_SirJohn look my previs comment
worth it watchig .. Well Explained Sir
Thanks so much
You deserve to be subcribed
thanks so so much
This is amazing...Finally understood this theorem🎉..Thank you..very clear and simple to the point..
You are most welcome
hi can i ask a question? at 7:58 if the two R doesn't the same value so what we have to do ?
Quick question please: At 18:20 why are you not doing 4/14 x 0,7778A? Confused on why you are using the 10ohm resistor with the current division rule?
In applying current division rule to two resistors, R1 and R2, i1 = R2/(R1+R2)*I and it switches for i2.
This was really helpful thank you sir!
thanks so much
i have one question
in 15:39 you took 10//4, but in 12:00 you took 5+5. They are the same, but why is the one at 12:00 is in series and the one at 15:39 is in parallel ?
Great
In 15:39, 10 and 4 are connected to the same two nodes so parallel
In 12:00 5 and 5 are connected to each other end to end.
Hope you will understand
@@SkanCityAcademy_SirJohn hmm, okay.
How do you determine the nodes then? because the original circuit had no nodes(dots on the line).
Is it because when you solve for the voltage source, the current source becomes an open circuit? and when you remove the voltage sources and solve for the current source, the voltage source becomes a short circuit?
so does the open circuit doesn't create a node but the short circuit does?
sorry for the disturbance.
I appreciate your help🙏.
@Ahmed-nz2vp most welcome.
The node is just the junction, the point where current divided or join.
Watching this two days to my exam
That's nice
😂😂 Iam watching 3 days before
1hr 15mins😂
Oh okay. Nice
1day
Have an exam at 14 hours here i am and damn this is helping 😢❤❤
Good luck
This is a godsend for the FE mechanical! Thanks!
Most welcome
can you do calculations I8u¹¹ = 4.5A in question 1?
Please where from the 6/6+18 in the first example when using the current divider theorem
We want to find the current in 8ohms, but since 8 is in series with 10, the current in 8 will be the same as the current in 10. Since current division is applied to two resistors at a time we need to combine 8 and 10 in series which is 18, before we divide the current amongst 18 and 6.
@@SkanCityAcademy_SirJohn All clear now thanks very much boss.🙂
You are most welcome
Why is the current in example 2, where current source is replaced, why does the resistance of 7.87... ohm have the same current for the 5 ohm
It is so because, the current divides at the node connecting the 4 and 10 ohms after flowing through the 7.8571, at the end the current combines and again and flow through the 5 ohms
At example 2nd how can the current which flows from eqvivalent of 3 resistor be flowing through 4ohm?
can you please state the time in the video so i help you out?
Thank you sir
You made it clear for me
youre welcome
In the first example why was the other current considered to be negative . Is there any trick to help me identify it.
There is no particular trick. The idea is since the currents I8' and I8'' flow in the 8 ohm in two different directions, you can choose to make either of them positive or negative. But normally for me, I make current in moving to the left negative and that moving to the right positive.
In example 1 why did u subtract 4.5A to 1.5A instead of adding them?
It's so because, the current move opposite to each other, hence we subtract
Nice one sir
thanks so much...
In example 1 how did you get the 4.5A sir?
Kirchoff law. There is two brench so the current multiplies
Or became the half it depends on how do you consider it
okayy its reallly helps me alot thanyou sir!! but please can sir make more video about Thevenin's Theorem?
@asyrielashdom217 you are most welcome. Will consider that.
@asyrielashdom217 which country do you watch me from?
how could i find the current for r1, if i have 3 resistors 2 in parallel and one series?
Is it a general question you want to ask or a question from the video, if the latter kindly state the time in the video.
@@SkanCityAcademy_SirJohn General question, that I need help with to follow
You need to combine the two parallel resistors and add to the series resistor, that will be the total resistance. Then if you know the source voltage you can use voltage division to solve for the current in R1, meanwhile the approach also depends on the position of the resistor you are interested in
@@SkanCityAcademy_SirJohn i have a picture that would make it clear but cant upload it here. I want to go through this and get it right, but im unsure. I know you work out the figures for each power source first. Trouble is if i make a mistake the whole problem goes wrong
@@SkanCityAcademy_SirJohn could do with your email really
sir in minute 15.53 i think it should rather (5//4)+10. As the current is coming from resistance 10, and that current is the one that's shared between resistance 4 and 5.
No please, look at it this way.
The 4 and 10 are parallel resistors since they are connected to the same two nodes.
Instead of using the usual direction on the current source, take it the other way around.
Why cant i get the voltage of the 8 ohm resistor using the mesh method? No matter how many times i tried im just getting wrong numbers
wow, that's interesting, for all you know you are just not doing something right, I would urge you to take your time and go over it once again
@@SkanCityAcademy_SirJohn alright thanks! All I needed to know was that it's actually possible in order to try again!
@@ΡαφαήλΣαλιάρης-ν5ω great
Great video sir...but on the second example..is it wrong if we consider the current I4' that's acting downwards to be negative and the one acting upwards I4'' to be positive?
yes, you can, just that the resultant(total) current in the circuit will be directed the opposite way
Also for example 1, where the current in 8 ohm is 4.5A, is it 4.5A because the current divides equally? Would the current always divide equally where it splits into two paths only?
Yes
Hello. Excuse me from where can I find these questions to practice on which website?
Download Fundamentals of Electric Circuit, Alexander and Sadiku
in the fisrt example is it okey to find -3A?
Yes, it is
is the current moving leftalways negative or an assumption
It's just an assumption
Why didn’t you use current divider rule when 9v acts alone to find current through the 8ohms resistor because the step you used was a little unclear to me
we could not do it straightaway because current division is applied to only two resistors at a time. So the best thing is to combine the resistors in the circuit first to obtain only two resistors before you divide the current among them.
Good example ..,just a quick question when we now considering 9A current supply do we include the 3ohms resistor since the voltage source is now short cct
Yes, the 3 ohms should be included. You just remove the voltage source and replace that with a short-circuit.
Good job
Thanks so much
thank you
Well explained
Thank you
May i ask why 3ohm and 6ohm are parallel but 8 ohm and 10 ohm are series
Okay, you need to understand that, for
Parallel resistors: they share the current approaching their common node. Or they are connected to the same two nodes or junction.
Series resistors: the same current flows through them
Thanks king🙏
What if the two resistors which the 9A is passing through have different resistance
If they have different resistors different current values will flow through them, so you need to us current division. The deal is, even when the two resistors are the same or not we still use current division rule. Just that when two resistance have same value, half of the total current is what flows through them.
Captivating
Thank you so much
Watching 1 day before exam 😅#engineer
😂😂😂😂 good luck 🙏🙏
I didn't understand the current division rule.explain the rules clearly
Check out this video : th-cam.com/video/ub9-8j92yVA/w-d-xo.html
Doing electrical principles at 2
Great
Why in 1st example we are converting the circuit in 2 10 ohm resistors when we can easily get it by taking ratios I guess the answer given is quite not right.
I solved it that way so that everyone can understand. And that is the correct thing.
If you want to use ratios, that is good but you need to arrive at that same answer.
I solved it that way so that everyone can understand. And that is the correct thing.
If you want to use ratios, that is good but you need to arrive at that same answer.
Why didn't you use half of the current in the second question the same way you did in the first question when you got 4.5A
this is because in the first question, the two resistors sharing the 9A current were the same (10 ohms each), so current will be divided equally between them. But for q2, the two resistors have different values hence they cannot share the same current.... i hope you understand
What a gainful ❤️
Thanks so so much
Great explanation, however, I can't quite understand how you found the 1.5A, I got lost there
so you know, we had 6A approaching the node, and we want to find the current in the 8ohm, but the current that passes through the 8ohm is the same through the 10ohm because they are in series, so we add them, then we apply current division rule at the node. Hope you will understand this
@@SkanCityAcademy_SirJohn yes I do, thank you very much🙏🏽
Youre most welcome
Watching this video 20 minutes to my exams
Wow interesting
Equivalent resistor is 4.5 ohms
How come u had the 1.5A
That has been clearly explained.
Current approaching the node is 6A
And we have (8+10) and 6 connected in parallel. Now to find current in 8 ohms, then it's basically 6/(18+6) * 6 which is 1.5A
I thought you mentioned the current divider rule I don't still understand how you got this
Yes please. That is what I have explained in my first comment. That's the current division.
We want to find the current in the 8 ohms.
But 8 is in series with 10 which means same current will flow through them.
So current in 8 Ohms is,
6/(18+6/ * 6A = 1.5 A
30 minutes before exam
Wow, Great, good luck
eveything is well understood...but why should we assume that the I8 ^1 in the 45V acting alone should be negative....shouldnt it be a standard something??why the assumption????
I get you. But it's not about it being a standard. Once the two currents are pointing in opposite directions, then one is a negative current, I just wanted the final current value to be positive hence choosing the current with less value to be negative. It can also be the other way round. It doesn't matter, provided the final current value is the same, disregarding whether it's positive or nagative
Knust button 😊😁
👇👇
Hehehe
2nd example answer is wrong
What's wrong with it?
Good voice is not clear. Some what
Okay, well noted.
thare is some ting wronge
what wrong and where please?
Not great
Ok