Understanding Thrust: A Continuous Explosion | Physics Explained

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  • เผยแพร่เมื่อ 25 ธ.ค. 2024

ความคิดเห็น • 16

  • @AFatWhiteShark
    @AFatWhiteShark ปีที่แล้ว +1

    As someone that just recently discovered it's own passion for physics...Thank you for this!!!
    Honestly, a great channel and amazing detailed content; your channel deserves more atention and recognition!

  • @flwi
    @flwi 11 หลายเดือนก่อน +6

    Landed here via a Hohmann transfer from Kerbal Space Program :-) Great content and excellent explanation!

  • @CecilramsfieldBaffour
    @CecilramsfieldBaffour ปีที่แล้ว +5

    How does this channel not have a million subs?

  • @kareemsalessi
    @kareemsalessi 5 หลายเดือนก่อน +1

    11:00 How about a vertical-launch example??? Thanks.

  • @thom7440
    @thom7440 2 ปีที่แล้ว +5

    I just found your channel. This is a really excellent, insightful, explanation of thrust. My only issue with it is using the word "impulse". That is a jargon-y word that has meaning to initiates of physics and rocket science, but not to someone new to this. So, best to leave that word out, until you explain it in its own video, as it's not clear what you mean by saying "impulse" from this video, on its own ... imo ... Other than that, this is by far the best, and most clear, explanation of thrust that Ive seen. Very nice job

    • @INTEGRALPHYSICS
      @INTEGRALPHYSICS  2 ปีที่แล้ว

      Thank you. You make a very good point about where to start.

  • @TheDinguin
    @TheDinguin ปีที่แล้ว +1

    Hey! Really great explanation and illustrations. I am curious on one point though: at 8:40 you use "mv" for impulse. Is it permissible to define it this way? I've learned impulse as the change in momentum, so I expected a [delta]p there, or even "mv_f - mv_i".
    Thanks!

    • @INTEGRALPHYSICS
      @INTEGRALPHYSICS  ปีที่แล้ว +1

      provided vi is 0 then it works.

    • @TheDinguin
      @TheDinguin ปีที่แล้ว +1

      @@INTEGRALPHYSICS understood, thank you

  • @taktition_
    @taktition_ ปีที่แล้ว +2

    Good explanation, but I'm confused, I thought J = kg m^2 s^-2, not kg m s^-1...

    • @INTEGRALPHYSICS
      @INTEGRALPHYSICS  ปีที่แล้ว +1

      'J' is impulse not Joules.... physics dropped the ball on that one.

  • @anyaqian
    @anyaqian ปีที่แล้ว +1

    Thank you!

  • @ishtaqrather9077
    @ishtaqrather9077 10 หลายเดือนก่อน

    In which direction does the thrust of rocket occur