6:46 in this question can we just directly do fxd so force would be fsin30 so 5sin30, now for distance we can take 0.2, so when we multiply them both we still get the same answer ?
I would put your pen or ruler on the pivot and make a line to the line of action of the force. Or you could resolve the force into vertical and horizontal distance and take the perpendicular one.
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6:46 in this question can we just directly do fxd so force would be fsin30 so 5sin30, now for distance we can take 0.2, so when we multiply them both we still get the same answer ?
Thank you very much for this channel I am grateful
Anytime! Thanks a lot for the comment!
Great video! Do you know where I can find more of these questions?
Here is one : ) th-cam.com/video/9_uLHOYjNh0/w-d-xo.html
@@zhelyo_physics Thanks!
@@Krakon. I know im a year late but PMT is always good for Physcis questions on all topics :)
Hi! Quick question, for the example shown in 6:15 which one will be our line of action?
Sure! So the line of action of the force is along the tension, i.e. along the line T
on the first question resolving the force works aswell right? or would i lose marks?
totally works!
@@zhelyo_physics thanks man
any tips for recognising what the perpendicular distance in each scenario?
I would put your pen or ruler on the pivot and make a line to the line of action of the force.
Or you could resolve the force into vertical and horizontal distance and take the perpendicular one.
@@zhelyo_physics thankslegend
5:59