Preparing Solutions - Part 3: Dilutions from stock solutions

[@mehboobyaqoob473]

thanks for restoring my confidence, i was the most confused person in lab regarding calculations. again thank you so much Mam

[@alimunir9902]

same situation.

[@sharbaridas4912]

You're not alone 🙂

[@harrisonbrand8985]

concentrations have always come so hard to me compared to other parts of chemistry, no idea why besides that i'm just less math oriented

[@shubhambhardwaj5946]

I usually forget these calculations again and again but I thank her because every time I knew where I need to learn it again when I do forget.

[@davidzalazar7036]

This is hands down the clearest explanation ever! Better than any website!!!

[@rukayatjimoh4944]

I really need to thank you for this tutorial, a total of about 6 years in school and counting. I lost confidence in myself until I came across your video today. Thank you so much.

[@mroosie7488]

This video has got me through my degree

[@bbmeesci5950]

I'm currently doing my second year in Biomed, I suffer from dyscalculia. This video has saved my grades! I've never felt so comfortable in labs and exams working out buffers etc. Thank you.

[@ahmadhayat7959]

Thank you very much.. never knew how to do it before; never will forget how to do it from now on

[@saurabhthakar]

Thankyou mam i have watched all three of your videos and my concepts are clear like never before thankyou so much v apprenticted your work now i am able to solve any type of sims

[@ShakespeareCafe]

Can you please make more videos? I could listen to your voice all day

[@bijangh93]

This triples your work. Use M1V1 = M2V2 and you'll solve these in less than 15 seconds.
Example: Stock solution of 70% ETOH. How to make 100 ml of 10% ETOH?
(70%) x (volume) = (10%) x (100 ml) --> Volume = ((10 x 100)/(70)) --> Volume = 14.3

[@theresajihadelalam5388]

Thank you so much. I've been searching for too long for how to do the dilution method and this helped me quite alot.

[@buharimuhammad5989]

A very good step-wise presentation. Please, more its kind.

[@qamarhennawi9137]

I am so glad to study in Glasgow Uni and waiting to meet you in person, I would like to know what is written in the board in the back side about Phd, this is what I am planning to do next step, Thanks a lot for your lovely explanation

[@ayeshasiddiq7023]

Very well explained mam. very helpful video.thanks for sharing

[@sara97979]

The equation made my life much easier. Thank you

[@sunnyyoda5511]

Can you please do a video for serial dilutions please?

[@dawilmercastillo5545]

Just made my life so much simpler

[@shobhasairam7397]

Your videoi is made so simple,Thank u so much ma'am,Can you please help me with serial dilutions and back calculation

[@collinsn.6674]

Please which University are you a professor at you are a good teacher keep up the good work

[@michellecarlamaier1923]

Please keep making videos! Very helpful. :)

[@rosetennant9721]

Hey, I still do not understand how can I apply this when for ex. I have to make a solution 1:1000 for 50 mikro M fiinal working solution, when I have no other information like volume.

[@lalnoumas2577]

Excellent explanation

[@l.fsader6021]

so theoretically, if I wanted to pippet a sample in a lab of 5.56microL, I would use a P20 with a 055 reading but what about the remaining .01microL, or would a "pipet W/ bulb and cylinder " be the only way to accurately draw a measurement in the hundreds place?

[@bishalbaruah4191]

Thank you so much! The concept is clear for me now.

[@floWer84PoWer]

Thank you!!! Great explanations for all videos

[@yathatisgood]

400ml to make 2%.
1 part in 5 = 200ml
Half of a part = 100ml
So to make 1.5% solution
I would need 300ml per 1000ml
I think.

[@sunnyyoda5511]

You can do C1*V1=C2*V2 in doing so you get X*2%= 1.5%*1000ml and if you solve for x you get 750ml of 2% stock soln in 250 of water.
but according to this video you would want to divide (1.5%/2%)*1000ml= 750ml of 2% stock soln in 250 of water.

[@seromane]

i should study in glasgow.. u made it so easy to understand, thanks alot !

[@dia6976]

Plz make more videos mam.don't stop

[@pianellrielly9803]

Hi ma'am, very helpful thank you. Does this kind of dilution (ie. starting from a stock) count as serial dilution? Or is serial dilution only when you keep decreasing the concentration by a set factor.
Thanks in advance.

[@MB-vd6hc]

That was super useful, thanks.

[@Its_InduB]

Please explain the calculations for enzymatic digestion of dna

[@GitikaThakur]

please help me out of this: I need to use 100ng/ml of activinA(26 kDa mol. wt ) in 40 ml media.
what concentration of activin A i need to use to make it?

[@angelineangelic4811]

Thank you very much!!! incredibly useful

[@zinabali7026]

So helpful, thanks alot

[@Deepbrowneyes]

Thank you so much for your help!

[@stompyd]

im in love. thank you sooo much for this

[@jeonghyun1664]

It was very helpful. Thank you so much :)

[@sahraahmed5821]

brilliant video thank you

[@beboweke]

thank you very much, best explanation ever
by the way you are so pretty

[@ranahaiderali4821]

Great trick

[@gardenlykaila7211]

Very helpful

[@priyanshu7821]

Mam u teach sooooo welll thank u

[@hazzmat9527]

Stock concentration of IL-1 beta = 25 ug/ml
Need to treat cells with 1ng/ml IL-beta
Each well of cells in a 96 well plate is treated with 100 ul of the IL-1beta solution
You need to make up sufficient volume to treat 6 wells, using cell medium as the diluent.
Questions
Q1: what total volume of IL-1beta solution do you need to make up
Q2: how much of the stock solution do you need?
Q3: how much of the cell medium do you need for the dilution?
CAN ANYONE HELP ME? I DO NOT KNOW HOW TO DO THIS AND HAVE BEEN GIVEN IT FOR TOMMOROW

[@laure189]

OMG, Sophie Marceau doing molecular biology!!!

[@nasrmhm]

Thanks you so much clear , and usefull

[@leticiasingh7937]

Thank you so much!

[@neetijaggi6617]

best ever..Thankyouu!!

[@muneebkhalid5125]

Solve That
0.01 M sodium phosphate buffer in 20% sucrose: dissolve 0.095 g of acid (NaH2PO4), 0.054 g of salt (Na2HPO4), and 20 g of sucrose and make volume up to 100 mL.

[@kjtrwarhead]

i get it now. Thank you

[@kundanIngale]

thanks for explaination

[@sushiboy8289]

amazing !!!

[@sushmitabora6662]

thank you so much!!

[@lateef230]

Many thanks

[@eliaali1083]

Thank you very much

[@jyotidubey4890]

I am always afraid when it comes to calculations in biology 🥲

[@dosiakumbe8105]

Thank you

[@genefreak]

Babe.

[@alainnsimpli6227]

Thank you so much...

[@dani45216]

Thanks so much

[@tajudeenabdulrazak3136]

Thanks so much