Partial Fractions - Denominator with repeated factors | SHS 1 ELECTIVE MATH

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thank you I understand what I couldn't in school and private tuition

[@SkanCityAcademy_SirJohn]

Aww, you are most welcome. God luck.

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Thank you very much sir, from Southern Africa

[@SkanCityAcademy_SirJohn]

Great

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[@SkanCityAcademy_SirJohn]

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Thanku from Ishika Tyagi

[@SkanCityAcademy_SirJohn]

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[@rusydi7440]

Finally..Thanks a lottt!!

[@SkanCityAcademy_SirJohn]

Thanks so much

[@CoillardSethKunda]

Kindly make a video on integration of partial fractions as well Sir

[@SkanCityAcademy_SirJohn]

Noted

[@ishmaeltome]

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[@SkanCityAcademy_SirJohn]

Thanks so much Ishmael.

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[@SkanCityAcademy_SirJohn]

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[@EricKabaghe]

Thank you 🙏 this clear

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Good Job sir

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[@myooneo]

@@SkanCityAcademy_SirJohn asia :)

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@myooneo thanks so much.
My greetings to all Asian students

[@myooneo]

@@SkanCityAcademy_SirJohn thank you !

[@SkanCityAcademy_SirJohn]

@myooneo ❤️

[@nimiobene5922]

9c explanation however its important u explain y u chose to put those factors into x for complete understanding of those just approaching the said topic

[@SkanCityAcademy_SirJohn]

Great contribution, thanks so much

[@mubarakquadry]

so good

[@SkanCityAcademy_SirJohn]

Thank you very much

[@mirriammwamba519]

Thank you!!!

[@SkanCityAcademy_SirJohn]

You are most welcome

[@kafrufruhon]

Why is it negative in the answer? Is it postive A/ (x-1) + B/(x+2) + C/(x+2)^2 ??

[@SkanCityAcademy_SirJohn]

Yes that is correct, but since B is - , you can pull out the negative outside, and simply write the positive value on top

[@thusoramakobya7054]

U r very key

[@SkanCityAcademy_SirJohn]

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Thank you

[@SkanCityAcademy_SirJohn]

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❤ best

[@SkanCityAcademy_SirJohn]

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Amazing

[@SkanCityAcademy_SirJohn]

Thank you

[@JyotiGhimire-hi6le]

Thank you sir

[@SkanCityAcademy_SirJohn]

You are most welcome

[@eipimath]

Thanks for sharing! I posted a video on partial fractions with repeated linear factors. Hope to get your thoughts.

[@SkanCityAcademy_SirJohn]

No problem

[@chibuchinwachukwu2342]

Sir pls how do usally not the coefficient to substitute into the solution?⁹

[@SkanCityAcademy_SirJohn]

You basically substitute a value which makes two variables become zero, so you can find the other variable

[@User-ff2gf]

I have one doubt sir suppose 4 term are present in the sum a,b,c,d how to take the values sir

[@SkanCityAcademy_SirJohn]

Okay, do you have a similar question, so that we try our hands on.

[@User-ff2gf]

I can solve this problem sir I already find b,c and d vale but I can't find A value I don't know how to find A value you may help for me find A value

[@User-ff2gf]

You just tell how to find A value its very help Full for me sir 🙏

[@SkanCityAcademy_SirJohn]

@@User-ff2gf kindly follow my steps in the video

[@User-ff2gf]

@@SkanCityAcademy_SirJohn yes sir I followed your steps sir I find b,c,d value sir but a value is just difficult beacause I apply z=0 all values are zero I have apply z=1/2 all value is zero I applied z=1/8 all value is zero ,I have confused what value is applied z=? Whose find A value

[@team_Alpha-307]

🤣🤣 University Discrete Maths, we need this in Generating functions not only shs1 E-Maths

[@SkanCityAcademy_SirJohn]

😂😂 okay, noted with thanks

[@calebntekim3293]

What is the reason for using 0? Why not 5 or 12 or 112?

[@SkanCityAcademy_SirJohn]

Just to reduce the complexity of the equation

[@calebntekim3293]

@@SkanCityAcademy_SirJohn ok

[@syahmimisnan1734]

Hi I have question, why we need to put x=0?

[@Japnaam17]

👍🏻

[@stephennjuguna6251]

Uko chonjo👍🏽

[@DanishKtk-j1p]

You speak English

[@SkanCityAcademy_SirJohn]

Yes please

[@MartinZulu-xj1oe]

The answer is wrong.

[@SkanCityAcademy_SirJohn]

Check the solution well, the right thing is what you see there.

[@vramanap8290]

Instead, you can compare the coefficients of x-square terms, x-terms and constants and you will get three simultaneous equations in terms of A, B & C - which can be solved easily.

[@SkanCityAcademy_SirJohn]

Thanks so much for your contribution

[@RashmiLawanga]

Thank you😊

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Thank you sir

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thank you!

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Thank you

[@SkanCityAcademy_SirJohn]

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