(L-33) Super Trick "Cross Aldol" (NCERT + JEE NEET Q&A) || IIT JEE NEET || By Arvind Arora

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[@vedantuneet]

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[@Feelings4youu]

1) *C6H5-CH=CH-CO-C6H5*
2) *C6H5-(CH3)C=CH-CO-C6H5*
*Perfectly understood sir no word 2 say Ur teaching just wonderful...👍👍👍👍 thanks a lot sir😄😄*

[@chemclasse]

Right sis ....😀

[@sumanavadagi7390]

Ur right Dr shweka

[@Feelings4youu]

@@chemclasse yes Naziya sis😊😊

[@Feelings4youu]

@@sumanavadagi7390 yaaa ryt😊

[@sumanavadagi7390]

@@Feelings4youu app kaha se hai shweka

[@studentofcollege]

Itna quality education to hame kahi par bhi nahi milta even no coaching centre will provide this . Arvind Arora sir to chemistry ke badshah he ❤️. jo sare bharat ku educate karna chahte he.thank u so much sir for your hardwork.

[@harshyadav732]

U r wrong ka bhi iit ka content dekhna coaching ka tab pta chalega sir ki videos r not sufficient for iitjee

[@AryanGupta-ws2un]

Genand mai daal le quality education

[@shankulsingh17]

1.C6H5-CO-CH=C-CH3C6H5
2.C6H5-COCH=CH-C6H5 are the answers of that last question finally thanks sir for the nice tricks to understand aldol condensation very easily.

[@kgnstarinterior2118]

YES YOU ARE RIGHT GREAT JOB ARE YOU REPEATER OR IN CLASS 12

[@adritisharma4779]

i think you are right

[@tusharsharma1992]

You are right bro

[@dineshprajapat9484]

👍👍👍👍

[@raghavsingh3766]

Can anyone tellwhat if only 1H is present then how will h20 remove??

[@atulkishore9159]

4:57 mei jo question hai woh same question iss saal ke board exam mei aaya tha.. code 56/3/1.. set 1..2019

[@rcbariarc2006]

Yaaro sach mai....World ka koi bhi teacher itna selfless nahi padha sakta...😍😍😍
Sir...you are master of explanation...💙

[@preetdhoolu9858]

P1 = C6H5-C(CH3)=CH-CO-C6H5 (self product)
P1 = C6H5-CH=CH-CO-C6H5 (cross product)
Thanks sir 😊💐

[@RaviTeja-qi8uo]

👍✌

[@ashutosh8702]

Perfect

[@yashkatiyar6678]

Sir ji itni practice apne krwa di ki 20 sec me answer nikal re hain aldol and cross aldol k .... thank u very much sir

[@sirvilive2935]

Completed...
Sir aapne jo last question diya tha vo solve ho gaya...
App Etna basic se samajte ho to.. Question solve nhi Ho.. Esa kabhi ho sakta hai..
Thankyou so much Sir..
You are great sir...

[@shivbaba499]

Sirrr....u r really an idol teacher..... thank u so much sir...for giving us such a phenomenal knowledge

[@earthyWZM]

No doubt... he is insane 💯💯

[@Shivam313]

Kya ye trick board exam me lga skte hai

[@earthyWZM]

@@Shivam313 Haan lga sakte hai
Maine mere school mein bhi lga ya tha
School k teacher ne toh kuch nhi bola

[@tanujgupta2678]

Yesss, no doubt in this
Sir, I complete this last reaction.

[@rubytiwari752]

Sir answer ho gya so happy...To solve aldol and cross aldol questions....
Truely a great teacher u are.....🙏

[@atulpanday399]

Done sir......really it was the most easy ...effective...smooth..trick i had ever came across regarding aldols...

[@priyankkumar642]

Sir really you made us understand everything very easily. So that I could manage to do question in just few seconds.😎

[@Raviprajapati-oe9rn]

Sir 10sec me ho gya last question.. Itna Accha samjhaya apne.. Thank you so much🙏🙇 sir

[@cutiekittu3096]

1)C6H5-(CH3)C=CH-CO-C6H5
2)C6H5-CH=CH-CO- C6H5
Sir this is my answer..
Finally thanku so much sir for this awesome lecture.I have seen all your lectures of Organic chemistry...
Now I have develope confidence in organic chem...
Thanku so much sir💕💕💕💕

[@itz_luminary]

C6H5-CH=CH-CO-C6H5 By self aldol
C6H5-(CH3)C=CH-CO-C6H5 By cross aldol
Thanks sir
You are great

[@bhawnasingh2883]

U r amazing sir ...u made this topic, so much interesting for me ..😃😃

[@chetnapiplani1904]

Self Aldol product (1). 3-Methyl-1,3-diphenylprop-2-en-1-one.(C6H5-(CH3)C=CH-CO-C6H5)
cross Aldol product ( 2). 1,3-Diphenylprop-2-en-1-one.(C6H5-CH=CH-CO-C6H5)
superb trick sir ji thank you💖🙏

[@karajsingh7782]

Hlo

[@karajsingh7782]

Yr book mein toh inka ek hi product written hai jisme alcohol grp bhi hai.

[@karajsingh7782]

Please clear this to me

[@karajsingh7782]

Jaise book mein ch3cho + hcho ka product ohch2ch2cho hai

[@premabisht5640]

Hlo karaj

[@vishwassriramula9750]

Self: C6H5- (CH3)C=CH-CO-C6H5
Cross aldol: C6H5-CH=CH-CO-C6H5
Thanks a lot sir

[@anujaison8283]

Sir you are the best. Everything is clear now. Thank you so much sir 🙏 ☺ ❤

[@prajwalpawar5884]

U are awesome sir ... concepts cleared in the best way ....its the most simple way

[@mr.chauhan8578]

aap ko bhgwan ji ne
hme hi pdane k liye beja h
aap to mere liye duniya k best teacher ho 😋😋😋😍😍😍😍😍😘😘😘😘😘😘😘😘😅😅😅😄😄😄😃😃😃😃🤣🤣🤣🤣🤣😍😍😍😍😍😍😍😍👍👍👍👍👍👍👍👍👍👍👍👍👍👍💜💜💜💜💞💝💝💝💝💝💝💟💟💟

[@thebiplabroy7112]

Last question ka ans ho gaya. Or mai conform hoon ki mera ans thik ha. Or iski waja aap ho sir. Apne itni achhi tarah se samjhaya. Thank u very much sir❤️💛💛❤️

[@kumarkaushik960]

Sir the answer for cross aldol product is 1,3-Diphenylprop-2-enone
And the answer for self aldol product is 1,3-Diphenylbut-2-enone

[@umanggupta5238]

Wow sir itna ache se to aaj. Tak kisi ne bhi smjhaya thank you very much sir ✨🙏👍👍

[@shivoshitajhalta8061]

Two products -
a) 1,3-Diphenylprop-2-en-1-one
b) 1,3-Diphenylbut-2-en-1-one
Amazing lecture sir ! 👏

[@srishtikulshreshtha5090]

Mechanism and short trick, dono samjh aa gayi!!!
Thank you so much Sir 🙏

[@user-xc8lv3wc6e]

(1) self product -- C6H5-CO-CH3 + C6H5-CO-CH3--------C6H5-CO-CH=C-(CH3) C6H5
(2) Cross product--C6H5-CO-CH3 +C6H5-CHO -------------C6H5-CO-CH=CH-C6H5 (LOTS OF THANKS SIR JI )

[@Triumph369]

Sir paani nikalte nikalte aab haath v paani ki tarah chlne lgee hai ...
Great teaching indeed

[@eshapathak1172]

Best Teacher Across TH-cam 💗🙏🏼 Thankyou so much sir 🙏🏼

[@ibrahimshaikh1224]

Thank u sir.
We are so much lucky that we have got a teacher like you...

[@content989]

Sir ab aldol bhaut easy way Mai product ban Rahi hai thanks sir

[@Sakshi-vq3wm]

Sir u r reaaaallllllyyyyy amazing 🙏 mujhe ye pura mechanism samajh aa gaya hai aur woh bhi without repeating . Thank you sir 🙏 for such simple videos ❤️

[@rohitpandit8690]

Thank you sir for your greatest efforts from my core of heart

[@shiprasinghrajput9744]

🌷Thank u soo much sir nd made je family for great efforts and hard working doing for us . 🌷

[@koushikhalder6022]

sir ho gya successfully..... ab mey aldol ka product bana paa raha hu vry easily....... thnks to u sir

[@Sachin_kalakoti105]

Wow sir u r amazing... Best teacher of chemistry... Sir aap hameaha healthy rahe or isi tarah padhate rahe. Thank u so much sir

[@kapildaiyer3586]

Sir I can't find work in discription box plzz guide me

[@shyamadebnath8273]

Ha yaar
Mane bi nahi paha

[@sauravchaudharyvlogstories0234]

Me too

[@akashrawat3435]

Sir Aap Smjhaye or smjh me Na Aaye Aisa ho hi nhi Skta hai
Thanks a lot ! Sir 🙏🙏

[@vanossgaming3201]

Thank you soo much SIR AND *MADE EZEE CHEMISTRY TEAM* for all your hardwork...

[@shivanshrastogi1307]

Thank you so much Sir 🙏🙏🙏🙏 Yo have really simplified Chemistry for us Sir .....
Hamaraa Last question ho Gaya Sir ✓✓✓
Ans is => 1)Self aldol Product is 1,3 Diphenyl But-2-en-1-one.
2)Cross aldol Product is 1,3 Diphenyl Prop-2-en-1-one.
*Once Again Thank You so much sir* .

[@nishakushwaha8167]

Sir apka jitna sukhriyada karu utna kam hai ap soch nai sakte ap hum jaise gareeb bache jo coaching afford nai sakta unke liye ap kitne bade efforts de rahe hai thank you so much sir

[@akanksha5261]

Sir nobody teach like you salute u GREAT SIR , even more iitian from IIT Bombay and delhi provide lectures to motivate us rather than utilise their study.🙏🙏🙏

[@ManojGupta-zq7uc]

Cross aldol product = C6H5- CH= CO-C6H5 and self aldol product C6H5-CCH3=CH-CO-C6H5. Thank you so much sir. Aa gya smjh organic king sir ji

[@meenakshiverma5117]

Ans 1 = 1,3-Diphenyl, prop-2-en-1-one (cross aldol )
And 2 = 1,3-diphenyl, but-2-en-1-one ( self aldol )
Thank you sir😄😄

[@earthyWZM]

Thank-You Sir ... These Videos 📹 are making my ORGANIC CHEMISTRY ⚗ STRONGER 💪💪💪💪💪💪💪💪💪...

[@shashikumar8709]

Self condensation product--> Ph-CO-CH=C(CH3) -ph
Cross condensation product-->
Ph-CH=CH-CO-Ph

[@aditimorankar1172]

P1= c6h5 -(ch3)c=ch-co-c6h5
P2 =c6h5 -ch=ch-co-c6h5
Sir Answer of last question...perfect understood sir.. no word to say..amazing teaching..thanks alot sir for this knowledge aapki wajah se meri organic chemistry aur jayda perfect &easy ho gyi

[@dhispiraspajsisping9744]

😍😍😍😍😍😍......sir you really amazing...hatts off to you sir.......and im sure your teaching will bring a success in our exams...

[@himanshushrivastava5656]

Last question done sir !!
Thanks a lot for all your efforts ☺

[@maliks9287]

Wonderful sir soo wonderful your teaching method is Excellent

[@sahbanansari6983]

Sir humko bhi kabhi nhi description box main hw milta hai! Plz help me sir plz! I need to do those homework &solve variety of questions

[@sharadpandey3285]

C6H5-CH=CH-CO-C6H5 , C6H5-C-CH3=CH-CO-C6H5 I had done sir it is a very simple trick thankuu

[@devang2335]

Sir mera last sawaal solve ho gya very nice explanation

[@itzpkg]

( 1,3 di phenyl 3- Methyl Prop-2-enone) :- ist Product
(1,3 di phenyl Prop-2-enone)

[@aniketpatel5405]

1 galat hai bhai methyl substitute group me Nahi hai

[@komal_potterhead7611]

It's hardly take 10 seconds for me to solve this...
😄😃😃This is really amazing

[@harsh_sethi]

Answer of last question :
1) C6H5-CH=CH-CO-C6H5
(Cross - aldol product)
2) C6H5-(CH3)C=CH-CO-C6H5 (Self - aldol product)

[@khushpreetkaur7699]

Thnqq so much ..... very very perfect and easy explanations👍👍

[@AbdulSaleem-rg2jp]

Answer of the last question are 1.C6H5-CH=CO-C6H5...
2.C6H5(CH3)C=CH-CO-C6H5..thank you so much sir it really helps me in this lock down

[@varshinisingam631]

Sir I got the answers successfully
Self aldol product is
C6H5-CO-CH=CCH3-C6H5
Cross aldol product is
C6H5-CH=CH-CO-C6H5
Done dona done sir !!!

[@jyotimeghwal877]

Your teaching is the best on TH-cam and most helpful for me👍👍👍👍👍👍👍👍👍👍

[@khatrigaming9939]

Sir kya kho ab itna deeply badiya samjhna itna hard work sir thanku so much sir love you from Haryana palwal

[@snehapathak5960]

sir ban gya question.. or bohot maza bhi aaya banane me... thanks sir ye short trick batane ke liye

[@arindombabu9844]

Ho gaya sir home work. It's very easy.
Ans are-
1- c6h5-ch=ch-c=o(c6h5)
2- c6h5-c(ch3)=ch-c=o(c6h5)

[@falgunigaba6454]

Thank you sir 😊😊. You made it so easy

[@desiplayer7916]

One of best teacher in the world

[@alishashabbir]

yupsss sir...apne jo qustn diya vo ban gya.....ap padhaye or us concept se qustn solve na ho,aisa ho nhi nh skta.....

[@luciferthedevil5247]

*WE REALLY APPRECIATE YOUR AND YOUR TEAM HARDWORK FOR US SIR ❤❤👍👍👍*

[@cuteki1269]

Sir mujhse bhai ho Gaya last question! When you teach everything seems easy 🤩

[@saiyamchhabra8381]

I mean that's really wonderful....I used to b so scared of chemistry...n now I m just loving it...thnkuh so mchh🙏🙏🙏

[@Jim_Curry]

Due to cross aldol- 1,3 di phenyl prop-2-ene,1-one
Due to self aldol- 1,3 di phenyl but-2-ene, 1-one

[@rkshort1192]

1,3 diphenyl 3methylprop-2-enone

[@ShravaniKulkarni03]

1,3-diphenyl-but-2-enone and 1,3-diphenyl-prop-2-enone

[@AdnanKhan-po9ck]

Sir you are the best chemistry teacher in the world

[@nandanidubey8677]

I really appreciating his efforts .
His work and determination toward students is adorable, great ful, Awesome. I think that he is a huge tree who want to cover everyone with his useful intelligent and knowledge 🙏😊🙏✨
God bless you sir Stay Happy Stay Safe ...
Thank You so much ..

[@VikasYadav-fj9yg]

Sir this short trick is very helpful and l have done the last question successfully

[@arnavgupta7875]

Sir you are indeed amazing. I spent 3 hours but didn't understand anything till i saw your video. Sir i have done the last question.

[@rohinpathan6379]

Good morning my favorite sir, and thanks a lot for your help 😃😃😃😃😃😃😃😃😃😃😃😃

[@anushakoppad6368]

Hello sir,aap bohot achha padhate hain sir.. thank u so much...I solved the last question sir..

[@VishalYadav-gw6je]

Sir ap bout accha padata ha akdam makkan ho geya thanks 👍

[@naveendongre6180]

SIR LAST WALA QUESTION HO GAYA...
*THANK YOU SO MUCH SIR😀😀😀😀😀😀😀😀😀😀🤗🤗🤗🤗🤗😊😊😊😊😊😀😀😀😀😀😀😀😀😀*

[@k.chandanachary694]

U gave one question to do and told that if we can't then u will tell us the answer. Bt u r totally mad sir....
apne samjhaya aur hum nahin kar payenge... ye hohi nahin sakta.... 😅😅Love u sir

[@rohitpandit8690]

Thank you madejee team for their support to coaching free india

[@mridulkrishansuroch4554]

Jag ghoomeya aap jaisa techer na koi !!😍😍

[@anshvashisht8519]

sir it took me 10 seconds thank u so much very nice trick

[@arshdivya7]

Thnkuuu sir so muchh ..ur videos are helping us in this lockdown ..really thnks a lot sir...every concept is beautifully cleared 🙏🙏🙏🙏

[@Anytimeme_]

Answer of homework is :- product 1:-
C6h5-c=o-ch=c-ch3-c6h5
Product 2:- c6h5-c=o-ch=ch-c6h5
..,... Thanks sir all understood 💜

[@shreyanshsonu9765]

Sir meraa last question solve ho gaye haii....bahut hii easily..... because of u... thanku sir...

[@AmnaKhurram-ut5hv]

Thank you sir u r very passionate teacher.ur lecture make my all concepts clear .thank u .

[@nirnkaribhajan2666]

Sir mera ho gaya
You are my best teacher on TH-cam
Sir ke fan like jarur kare👍👍👍👍👍👍👍👍

[@ArtnCraft-]

Yes ap bhut help karte h bhut bhut acche se smjh Aya h

[@kamranaar]

Self aldol product: 1,4-diphenylbut - 3 - en - 2 - one
Cross aldol product : 1,5 - diphenylprop - 3 - en - 2 - one

[@anjusingh4102]

Last question ho gya sir . Sir apne to chemistry ko mere liye maths se bhi easy bna diya h thanks a lot sir

[@tusharwaghmare4237]

Thank you sir
As I had completed the last question successfully

[@bikibharali5240]

Plz tell me the IUPAC names of the two products 🙏🏼🙏🏼

[@SeemaCK-e9d]

Ji sir bn gye products successfully bhut mja aaya sch m 😊😊

[@Happy_girl63]

No words sir such an amazing teaching...

[@KiranChoudhary-og4hf]

Thanks a lot sir !!! Best trick ever known !!!!

[@nagasasikala4498]

superb trick from super sir......................................

[@rajdeepdebnath5764]

Thank you so much sir ❤️❤️❤️❤️❤️
Sir understand everything perfectly