Triangles - Theorem 6.2 🌟Converse of Basic Proportionality Theorem 🌟Class 10 Maths Chapter 6 🌟NCERT🎯

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Very useful I can understand easily from your viedo,no need of tution teacher .

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Yes sir please tell why we add 1

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Yes sir

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To prove of DE||BC in a possible way.

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You can use componendo instead

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I can't understand why we add 1 in theorem

[@anchalnamdev9421]

Yes

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We have to take lcm vikas

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To prove that the both line DE and DE' overlap

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It's very useful video for 10th class students ❤🎉
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One hour

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Sir can we take another alphabet in place of second E'

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Yes you can

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Why you are adding 1 to both sides?

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to symplify and get numerator and denominator term.

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To balance both sides

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To get answer

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[@Altamash_31]

EC=E’C
This implies EandE' must coincide
Since DE'||BC
Therefore DE||BC
But you assume 2 line DE' and DE from the same point
Also DE'||BC Not DE||BC (Assume)
But at last you prove both lines are parallel to same line
And it is not possible as the two different lines passing from same point are not parallel to same another line.

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Same bhai

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How is AE +EC is equal to Ac?

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Why are we assuming DE' II BC

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Thanks sir

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Why are you not prove that DEparallel to BC

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Iska prove?

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