If CD is free from local attraction then FB of DE should also be free of local attraction.. so when you calculated it should be 230degree 10 minutes. Why did it come 230degree 5 minutes?
Sir I have a doubt can u please help me Station C and station D not effected by local attractions so back bearing of BC and Forbearing of DE donot change ??
This is another method, see the title. You are trying to solve it by previous method. Here we close the traverse first by fixing the interior angles and then find the bearings of lines using those angles and previous bearings.
If CD is free from local attraction then FB of DE should also be free of local attraction.. so when you calculated it should be 230degree 10 minutes. Why did it come 230degree 5 minutes?
True
@@anishabarman1481can you give your any contact insta I'd or something
Yes
Bro, same question....
3 saal se unanswered hai yeh question, ab koyi aasha nahi lag rahi merko ki mera doubt bhi solve hoga 😂😂
good method of compass surveying thanks sir
have you uploaded videos about engineering mechanics?? if yes then kindly share link to the playlist!!!
Very appreciated ur teaching
Hats off ❤❤❤
Sir I have a doubt can u please help me
Station C and station D not effected by local attractions so back bearing of BC and Forbearing of DE donot change ??
back bearing of BC shold be true if CD has no local attraction.
@civilmodules help
Meru chala great sir ❣️❣️
Sir thank you it is very helpful video sir
Thanks sir
From where did you pick this question??
Ssc je mains paper se
Thank you🙂
Kya aap drawing ka Bhi video Banate h
Supr sir
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Thanks sir 🙏🙏🙏
If CD is free from local attractions then value of DE should be 230*10* and not 230*5*
If this is the case, then what is the use of correcting the interior angles at the first place?
@@CivilModules just like previous question that you solved .... Or not ?
This is another method, see the title. You are trying to solve it by previous method. Here we close the traverse first by fixing the interior angles and then find the bearings of lines using those angles and previous bearings.
@@CivilModules yes sir now my doubt is clear 👍👍
60°20° ki jgh 60°25°5 ka error chal Sikta h kya error sir exam
what to do when there is an error on all angles?
Same method
Choose least error station as reference
Thanquuu sir
feeling confused???
Thnkuuu sr🙏🙏👍👍👍👍👍👍👍🙂🙂🙂🙂🙂❤❤❤❤❤
It's like I am watching him solve questions not explain to us
Mera integer angle to 540° hi aaya h