Class 11th - Thermodynamics Process - Work Done in Adiabatic | Thermodynamics | Tutorials Point
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- เผยแพร่เมื่อ 3 ต.ค. 2024
- Thermodynamics Process - Work Done in Adiabatic
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Lecture By: Mr. Pradeep Kshetrapal, Tutorials Point India Private Limited
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Sometimes mistakes happen but we love ur teaching sir ur really a god came from heaven to make physics far better
PV^gama may be presented as P1V1^gama=P2V2^gama and used appropriately.
@ 6:15 how sir wrote the equqtion...
Thank you so much sir
Your teaching made it very easy for me to understand sir
Great Sir. Regards
Does it have the same answer when we use first law of thermodynamics to find work?
Also P1V1^gama is not equal to RT1 and P2V2^gama is also not equalto RT2.Am I correct Professor
Nice sir
Sir,P1 gama and v1 gama is used in adiabatic expression but why not in isothermal process
In iso thermal T is constantand from PV=NRTwhen T is constant NRT is Constant this gives us PV=constant
The process of the derivation is wrong, you should correct it sir.
PV may be explained in a better way Sir.My humble opinion please.
bruh hes dead
💖💕
Ty sir❤
Hii... Where r u from???
Ehh, is the derivation even correct? like, how can we take P common when P1 and P2 are two different values? PLEASE PUT DOWN THIS VIDEO OR CORRECT IT. *DON'T MISGUIDE STUDENTS!!!*
P is not taken common... *k* has been taken out of the integration and then the value of k=PV' is substituted.
You please don't misguide student.
There is some mistake by him he forgot the fact that p1v1^r=p2v2^r=constant{K} by this the derivation will be done
his explanation is completely irrational,,,, he is just adding up the notations whenever he needs