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beautifully explained, keep up the good work !!
What happens when blocking and nonblocking assignments are intermixed?
In what way would mixing blocking and non-blocking assignments cause issues?
great
5:30 explication is absent...why mem{a}'s old value went to the output?? Why the old ?
Because both right hand side values were evaluated first, then assignment happened at the end of that always block.
thats literally the whole point of non blocking assignments
good explanation but this digital stuff is depressing I wish I didnt have to rake it for ee
beautifully explained, keep up the good work !!
What happens when blocking and nonblocking assignments are intermixed?
In what way would mixing blocking and non-blocking assignments cause issues?
great
5:30 explication is absent...why mem{a}'s old value went to the output?? Why the old ?
Because both right hand side values were evaluated first, then assignment happened at the end of that always block.
thats literally the whole point of non blocking assignments
good explanation but this digital stuff is depressing I wish I didnt have to rake it for ee