How To Find The Square Root of Large Numbers Using The Division Method
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- เผยแพร่เมื่อ 3 ก.พ. 2020
- This math video tutorial explains how to find the square root of large numbers using the division method.
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I was in dire need of this video......thank you .....I have finals form 24th wish me luck..
good luck. did you pass
Good luck, even though it’s been 2 years after the test
Good luck
Good luck brother🎉❤
i cannot thank this guy enough, math is my weakest subjet and i missed this lesson due to travelling, he explained it so briefly and was straight to the point THANK YOU
Thank you so much. You are a really great teacher. I always watch your videos and it helps me a lot. Thank you
It really helps me a lot. Thank you so much
Never understood it until now so thank you for that. 😬👍
MR. Organic Chemistry Tutor ,thank you for another short and exciting video/lecture on How to Find the Square of Large Number Using the Division Method. From watching this video, I found this topic problematic, however, I will review these concepts.
Well explained and very clear...ty😊😊😊
i thought it was hard, but after wwatching your video, it got real easy real fast
Thank you!! Helping my daughter with math and this made is so much easier to explain 🎉🎉
Very impressive indeed. Fantastic website.!
i loved this video it explained so much, honestly the highest honor i can grant you is hitting the subscribe button.
edit: i tried hitting the subscribe button but my laptop fell and now wont switch on. guess it wasnt touch screen ( writing this from my phone )
F
Bruh
I was finding square roots of large numbers in middle school with ease but haven't done so in many years I've forgotten how to. Thanks for the review.
there is a little easier method which you will never forget. All you need to remember is the number 20
In each iteration all you do is multiply your current root by 20, add your new digit, and multiply by your new digit. Done. Put it under your current remainder and subtract. Proceed with the next
thank you mate ! i saw like 30 seconds and knew what exactly what to do !
Thank u man ......love this method
This Helped A Lot
Thank you so much
You made me understand..
OMG, THANK YOU! Taking an exam and this explained it ALLLLLLLLL
Thank you 👍🏻👍🏻👍🏻
This is a very powerful method for solving for perfect squares. However, can this be used to solve for non-perfect squares. That is, squares with decimal remainders? And if so, how do we apply this technique to solve for the answer?
you need to add 2 0s where you want a decimal. in normal division we add one 0 but here we add 2
@@thetooshminator3195 So, let’s say if we had 134 as a remainder. Would we do .00134? Or are we adding 00 to the end of the remainder, (in this case 13400) then trying trying to multiply (when I say this, I mean like how we multiply in the problems) to get to it or lower?
(I assume the second one.)
Yes, you just add a decimal and two zeroes for every additional digit of precision you want. This method can find any square root to any arbitrary precision. As you add more digits of precision, the multiplication becomes more challenging so there is a practical limit.
@@RayFowler, I still don’t get it, but thank you.
@@chinmaibommana9788 🤓👍🏻
Please do one on non-perfect cubes and decimal numbers and also one using the algebraic formula. Thank you!!!
for cubes you cant use division method
I actually got it correct in under 2 minutes. Easy as it is! Thanks!
Thanks a lot
It's very important method and well suggested.
I would like to help me the program you prepared this tutorial or video in order to use and facilitate my teaching.
Thanks for your help.
Thank you so much
Thank you!!
Helpful!
Thank u it's too good
What he did not say is that you make groups of 2 digits STARTING at the decimal point, moving in both directions, then proceed until you have a remainder of zero, or reach the required number of decimal places in the result. Add as many zeros in groups of 2 after the decimal as required.
Yes, he should've. Another video by someone else explained this.
Thank your very much..
There is an easier remembered method to do this. It all just involves remembering the number 20
(You set up the problem just as you did in Long Division form. From the decimal point, both ways divide your # into groups of 2)
All you need to do in each iteration is multiply 20 times your currant root. (20a) That is your currant trial divisor. How much does that divide into the currant root? When you decide that, add that number to the 20a figure and multiply by that same number. Thus (20a +b ) x b Write that below your currant remainder, subtract and proceed with the next digit.
Thank you so very much, i spent the entire morning trying to do little by little find the square root of 487204 😢. I know better now!
There is an easier way to count in mind square roots of 2 digit numbers squared (ex 74 * 74 = 5476)
so you take the first pair (54)
find the next and lower square that would be 49 (7^2) and 64 (8^2)
we have our first number which is the lowest square root (7)
we use the higher number and lower number to find what is the closest difference
from 49 to 54 is 5, and from 54 to 64 is 10, the closest number is a *Lower number (this is important for next step)
Next you take the latest digit from our original number (5476) which is 6
Find 2 one digit numbers that squared gives a number that ends in 6 (one exception would be 5 or 0 which doesn't have a second number, always ends in 5 (2[5]) or 0).
We have 4 (4^2 = 1[6]) and 6 (6 ^2 = 3[6] )
Giving the previous analysys that we need a *Low number, we pick the lowest number which is 4.
So we have 74
He teaches this method in reverse order to what you wrote in another example. But again, it's really meant for perfect squares. Not gonna work in real life.
Please I don't understand
@@VictoriaSarfo-cg1fk Basically you take the nearest root of first 2 numbers, and observe if it's higher or lower (nearest root than first 3 numbers) then you find the root of last number (there will be 2 roots). ex: last number 6 then it can be 4 or 6 (4^2 = 1[6], 6^2 = 3[6]), so you choose the one based on previous less or greater root. As explained above. So you end up with two one digit roots that forms a two digit number and that is the answer
Thank you
Thank u soo much
That's great 👌
Thankyou very much sir.tomorrow is my exam ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Sir which board you have used for writting
This is fun.
Please sir can you do a video on quadratic functions and equations involving Alpha and Beta ❤❤
Does this also work for cube roots?
thank
Omg! You have helped me so much!!! Thank you :) 🥰
What the digital given has 5 digits, then how will u divide the digits?
My exam is in 2 hours. Thanks for the help
Can you do the same method but for non-perfect squares?
Yes, you can carry it out to as many decimal places as you want. Basically, keep going the same way, in groups of two digits (two decimal places.) This is sort of using the formula (a + b) * (a + b) = a * a + 2*a*b + b * b backwards.
its same as long division but you need to add 2 zeros. normally we add only 1 zero after the number cant be further divided but here we add 2 zeros.
@@deanlie can u please tell my y we divide into groups of 2 that also from right to left. I understand the relation between (a+b)^2 and this long division method.
@@guru_bro Hi, basically the idea is that 10^2=100, 100^2=10,000, etc -- in general, (10^n)^2 = 10^(2*n). So if a number is between 1 and 100, its square root is between 1 and 10, if a number is between 100 and 10000 its square root is between 10 and 100, etc. So dividing into groups of two digits from right to left leaves a number between 1 and 99 (inclusive) in the leftmost group which is what we need for the "a" part in (a * 10^n + b)^2 =
a^2 * 10^(2*n) + 2*a*10^n* b + b^2. Short answer, dividing into groups of 2 finds us that 10^(2*n) part.
@@deanlie So, if the remainder is 343, we add 2 0’s, it would be 34300, and then we would do the steps like we did before all over again?
Thanks
Math is my best subject but i couldn't do it at all
what about imperfect squares?
It does work!
how to find fifth root using divsion method?
im trying to calculate fifth root of the number 3
1:39
We can get the unknown number by dividing like in sample square root of 5184 the next digit from 8 should be divided by 609 to get the one number 7 jennifer basa post this
Sorry im wrong squre root of 2209
Can you please do a video on canonical SOP and POS, Boolean Venn Diagrams, and minterms/maxterms!
You: explain these things: *BIG WORDS*
Me: can you say that in English please
why in first example we took the whole 22 not just 2 like in example in 7:26
Because 13 and 16 are in group 2 is alone
But with a decimal point will be better good ✨ however thank u
Please try this 10609 using long division.
Can someone give me a link that shows the traditional method which works even on numbers that are not a perfect square, please?
13:19 😂😂
13:20 oh lol okay never doing it again
Me who watching in 9th because I forgot the method 😂
I just Don't know how to say thank you, if I was rich, I would give a trillion dollars
First
so?
@@Burrito_16 so?
Unfortunately your two videos on this topic are all with perfect squares, which isn't like real life at all. (Today I was working on one of your pre-calc distance (point from graphed line) formulas and wanted to figure out the sides of the triangle is made just for practice and was using square roots that gave me decimals. But this method still works, obviously; you would just be finding decimals at some point.
You can still find decimals. (I actully don’t rally know how it works, but here is m understanding): It’s like decision, 2 turns to 20, but you add 2 0’s. If we had 34 as a remainder, we make it 3400 then continue.
699 likes ha nice
Ugh I have 719V48,723
There is a V in maths?
Why am I watching this I am in 8th grade WTF 🤣🤣😂😂😂😂😂😂😂😂😂😂🤣🤣🤣🤣🤣
I am 55 years old and still watching. He is good.