00:04 Disk scheduling algorithm aims to minimize seek time 00:51 A CD is a circular platter made up of multiple CDs. 01:35 Data is stored in sectors on the platter surface. 02:14 Data storage on hard drives involves tracks, surfaces, and sectors 03:03 Moving the read write head to the desired track 03:48 Seek time is an important aspect of operating systems. 04:41 Seek time is the time taken to move the read-write head to the desired track. 05:31 Disk Scheduling Algorithm and Seek Time Crafted by Merlin AI.
Thank you so much sir. This simple thing was taught to me in my college in a very much complex way. But after seeing your explanation, things are becoming very easy.
00:02 Disk architecture is important in computer organization and is often asked about in related subjects 01:31 Hard disk architecture includes platters and read write heads. 03:01 Platters in hard disks have tracks on them. 04:28 Hard disk architecture involves tracks, sectors, and data storage. 06:00 Hard disk architecture involves platters, surfaces, tracks, and sectors. 07:28 Understanding disk size calculation in sectors 08:54 Understanding disk size notation in terms of bytes and conversion to terabytes 10:16 Understanding the number of bits required to represent disk size Crafted by Merlin AI.
not actually... there was 2^40 bytes... so when we will be asked for number of required bits we need to convert bytes to bits. That is 2^40 x 8 = 2^40x 2^3 = 2^43 threfore number of bits required is 43 bits i think thats the correct way!!!
Sir u r amazing..... M watching ur videos in 2x speed for ugc net exm revision.... Tq sir .. Cnt tell u hw much u have helpd me throughout my exm prepartion.... Hope i ll clear my exm✌tq once again🙏🙏🙂
I just realized I'm watching this for so long now and you sir have helped me a lot but I still hadn't subscribed or liked your videos and I felt so bad. So now I'll go back and like all your videos and I have subscribed now. So sorry !
⛔ Could not find **Add a comment** button. Here is the entire summary: ```markdown 🎯 Key Takeaways for quick navigation: 00:00 🖥 *Disk architecture is a crucial topic in Operating Systems and computer organization, often asked in exams.* 01:34 🔄 *Platters, surfaces (upper and lower), and read-write heads with actuator arms are fundamental components of disk architecture.* 03:35 📀 *Tracks, both in upper and lower surfaces of platters, are the next element in the disk architecture sequence.* 04:33 🛤 *The movement of the read-write head is limited to forward and backward on tracks, distinguishing internal and external tracks.* 05:34 📊 *Sequence: Platters ➔ Surfaces ➔ Tracks ➔ Sectors ➔ Data. Questions often involve calculating total tracks, sectors, or disk size.* 06:56 💽 *Example calculation: Total tracks = Platters × Surfaces × Tracks, with values often given in powers of 2 for easier computation.* 07:55 📏 *Disk size calculation involves multiplying platters, surfaces, tracks, sectors, and data capacity, usually given in bytes (often in powers of 2).* 09:26 💾 *Disk size conversion: 2^40 bytes = 1 terabyte. Understanding kilo, mega, giga, tera conversions is essential for accurate answers.* 10:30 🤔 *Number of bits*
i really CANT thank you enough for this good quality helpful playlist... but here regarding the last part, "the number of bits required" I think the ans should be .... there was 2^40 bytes... so when we will be asked for number of required bits we need to convert bytes to bits. That is 2^40 x 8 = 2^40x 2^3 = 2^43 threfore number of bits required is 43 bits 😇 i think thats the correct way!!!
Sir please addressing [ chs( cylinder-head-sector) and LBA( logical BLock addressing )] ka vedio banaye please sir aapke alava dusre vedio me maja nahi aata . So sir please , me aapka subscribe bhi hu aur aapke sabhi vedio ko like bhi karta hu
Consider a hard disk with 16 recording surfaces (0-15) having 16384 cylinders (0-16383) and each cylinder contains 64 sectors (0-63). Data storage capacity in each sector is 512 bytes. Data are organized cylinder-wise and the addressing format is . A file of size 42797 KB is stored in the disk and the starting disk location of the file is . What is the cylinder number of the last sector of the file, if it is stored in a contiguous manner? Sir please give explanation of this question
Sir one query...! If number of bits are asked, doesn't we need to convert the answer from Byte to bit {i.e. 2^40 X 2^3 = 2^(40+3)}? So the answer is coming *43 bits* Isn't it the right answer?? As we had calculated the disk size in byte (i.e. 2^40 Byte = 2^43 bit)
Sir confusion h 2 ki power 40 byte h , number of bits required 40 then byte ko bit m convert krege , 43 Ans ayega please sir reply kr dena ans kya ayega or kyu
Ek confusion hai , like last me no. of bits pucha hai question me , pr abhi bhi hmne byte calculate ki hai , to last me answer 43 bit nhi aayega ? , Like 2 raise to power 3 nhi krenge ?
I have a doubt regarding the number of bits required to represent the disk size. You have taken 40 bits that represent tera but what about byte? We also have to convert byte into bits so that the final answer will be 43 bits
May be that will be irrelevant like you taught us in paging , while representing in bits we don’t convert byte into bits,because we are not required to do so. This explains the scenario. Thanks
Broo at 7:40 how can every track have same number of sectors.. INNER Tracks should have less no.of Sectors and OUTER Tracks should have more no.of Sectors. Because every SECTOR has same amount of data.
I am deaf. But I can understand your explanation because of the subtitles. Thank you so much sir....🙂your explanation wow.....
You are most welcome
😂😂 very good
❤
Bairee😂😂
The most thankful comment on this channel
00:04 Disk scheduling algorithm aims to minimize seek time
00:51 A CD is a circular platter made up of multiple CDs.
01:35 Data is stored in sectors on the platter surface.
02:14 Data storage on hard drives involves tracks, surfaces, and sectors
03:03 Moving the read write head to the desired track
03:48 Seek time is an important aspect of operating systems.
04:41 Seek time is the time taken to move the read-write head to the desired track.
05:31 Disk Scheduling Algorithm and Seek Time
Crafted by Merlin AI.
Thank you so much sir. This simple thing was taught to me in my college in a very much complex way. But after seeing your explanation, things are becoming very easy.
You have already win my 💖 ...u r So genuine person.. nicely explained 👍 May Almighty shows the rain of mercy upon you..
00:02 Disk architecture is important in computer organization and is often asked about in related subjects
01:31 Hard disk architecture includes platters and read write heads.
03:01 Platters in hard disks have tracks on them.
04:28 Hard disk architecture involves tracks, sectors, and data storage.
06:00 Hard disk architecture involves platters, surfaces, tracks, and sectors.
07:28 Understanding disk size calculation in sectors
08:54 Understanding disk size notation in terms of bytes and conversion to terabytes
10:16 Understanding the number of bits required to represent disk size
Crafted by Merlin AI.
It's been 2-3 years since watching your videos and I would say, you have a simplest way to explain such complex topics. Thank you so much sir ❤❤❤
Thanks for highlighting n like my comment, means a lot sir!!❤❤❤
I like your style of saying "HELLO DOSTO"
Ha Doremon jaise 😃
Masterclasses by the master himself...coming from ur coa series.. That's fab too.Thanks sir🙏🙌🔝
Nice explanation. I think total no of bits should be 40*8 = 320bits for 1TB
not actually... there was 2^40 bytes... so when we will be asked for number of required bits we need to convert bytes to bits. That is
2^40 x 8
= 2^40x 2^3
= 2^43
threfore number of bits required is 43 bits
i think thats the correct way!!!
@@mumtahinahmed3267 yes bro
@@mumtahinahmed3267 right bro... I had the same query
@@mumtahinahmed3267 so answer should be 43 na??????
Sir I am following your channel after memory hierarchy . I love the way that u use to comprehend any topic
Great sir
Great explanation 👌
😀😀😀👍nice video
Really a good explanation with boys calculation ✌️
Sir u r amazing..... M watching ur videos in 2x speed for ugc net exm revision.... Tq sir .. Cnt tell u hw much u have helpd me throughout my exm prepartion.... Hope i ll clear my exm✌tq once again🙏🙏🙂
I just realized I'm watching this for so long now and you sir have helped me a lot but I still hadn't subscribed or liked your videos and I felt so bad. So now I'll go back and like all your videos and I have subscribed now. So sorry !
super explanation brooo....\
Thank you so much 🙂
❤❤❤
⛔ Could not find **Add a comment** button. Here is the entire summary:
```markdown
🎯 Key Takeaways for quick navigation:
00:00 🖥 *Disk architecture is a crucial topic in Operating Systems and computer organization, often asked in exams.*
01:34 🔄 *Platters, surfaces (upper and lower), and read-write heads with actuator arms are fundamental components of disk architecture.*
03:35 📀 *Tracks, both in upper and lower surfaces of platters, are the next element in the disk architecture sequence.*
04:33 🛤 *The movement of the read-write head is limited to forward and backward on tracks, distinguishing internal and external tracks.*
05:34 📊 *Sequence: Platters ➔ Surfaces ➔ Tracks ➔ Sectors ➔ Data. Questions often involve calculating total tracks, sectors, or disk size.*
06:56 💽 *Example calculation: Total tracks = Platters × Surfaces × Tracks, with values often given in powers of 2 for easier computation.*
07:55 📏 *Disk size calculation involves multiplying platters, surfaces, tracks, sectors, and data capacity, usually given in bytes (often in powers of 2).*
09:26 💾 *Disk size conversion: 2^40 bytes = 1 terabyte. Understanding kilo, mega, giga, tera conversions is essential for accurate answers.*
10:30 🤔 *Number of bits*
On my birthday this video was uploaded
First time I got ad in your video😆
Nice
Awesome
Thankyou sir ❤❤❤
i really CANT thank you enough for this good quality helpful playlist... but here regarding the last part, "the number of bits required" I think the ans should be ....
there was 2^40 bytes... so when we will be asked for number of required bits we need to convert bytes to bits. That is
2^40 x 8
= 2^40x 2^3
= 2^43
threfore number of bits required is 43 bits 😇
i think thats the correct way!!!
@boomsi69 i forgot everything 🤣🤣🤣, i Didn't even remember i made a comment, thank you for your reply 🤣
@@mumtahinahmed3267hello 🙄
Thanks for such amazing lectures... 💥Really appreciable, helpful and so sweet of you for extremely easy and simple explanations sir 😊
I love you
👌👌👌
Thank you sir
Sir please make video on disk attachment please sir mera exam hai
Thank you so much❣
Aam je bande veere khas bante🔥😀 I suddenly Remind the song while studying with your video😂
Like kro jo samjh gya👍🤪
Thank you sir!
Sir ap bahot ache ho
thanks from NSUT
sir winchester disk format pr video bna do
Thanku very much sir
I paused at 9:11 by mistake and it reminded me of Amitab Bachchan🤣 Anyways excellent teaching sir! Thanks a lot!!
haha lol
Thnku sir😀😀😀
Legends watching in 2024
Yar tum admi barry great ho
Love from Canada Daniel
Nice sir please help to 12 standard students sir our future depend upon u please sir
Sir really u r doing great work........👍👍👍👍👍
Sir one video from introduction to computers
Sir pen drive and CD mai to koi hard disk nhi hoti h to data kis form mai aata h usme ?
Thanku sir
Sir please addressing [ chs( cylinder-head-sector) and LBA( logical BLock addressing )] ka vedio banaye please sir aapke alava dusre vedio me maja nahi aata . So sir please , me aapka subscribe bhi hu aur aapke sabhi vedio ko like bhi karta hu
Sir one video from disk cleanup disk defragmentation and data analysis data visualisation
Consider a hard disk with 16 recording surfaces (0-15) having 16384 cylinders (0-16383)
and each cylinder contains 64 sectors (0-63). Data storage capacity in each sector is 512
bytes. Data are organized cylinder-wise and the addressing format is . A file of size 42797
KB is stored in the disk and the starting disk location of the file is .
What is the cylinder number of the last sector of the file, if it is stored in a contiguous
manner? Sir please give explanation of this question
Thanks
thankyou brother
Thanks from a student of NSU, Dhaka. Without your video, I couldn't pass my engineering so smoothly.
Thanks sir
Sir todhe topic nhi h lesson 6 ke iss playlist me
Thank you sir aap bahut ache teacher hai
#admacravi
Waiting for next video
Thank you
Sir inner track aur outer track main kya sectors barabar hote hain kyonki inner sector to outer sector se small hota hai
the way you expalined .. just awesome ..
bhai teacher mein bhagwan hota hai woh aapke liye hai.
You are great sir
Ur way of teaching just awsm Sir
👍
love you mere bhai
Sir please make video on disk attachment please meri exam hai🙏🏼
Thank you sir... bhot video dekhe pr, sirf aapne thik se smjaya, thank you🙏🙏
💓💛💜perfect
You can also make a playlist on "information retrieval" as it a subject in many colleges
Sir one query...!
If number of bits are asked, doesn't we need to convert the answer from Byte to bit {i.e. 2^40 X 2^3 = 2^(40+3)}?
So the answer is coming *43 bits*
Isn't it the right answer??
As we had calculated the disk size in byte (i.e. 2^40 Byte = 2^43 bit)
Actually i was also confused about this so i searched more about it, the answer i get was we need 40 bits to represent disk size in bytes
Sir agr in 4 platter me koi b ek platter kharab ho jaye to ky baki platters ya pure disk pe koi effect dalega
Sir one video from algol language
धन्यवाद सर, आप वास्तव में बहुत अच्छे अध्यापक हो❤
Sir confusion h 2 ki power 40 byte h , number of bits required 40 then byte ko bit m convert krege , 43 Ans ayega please sir reply kr dena ans kya ayega or kyu
No, it means you need 40 bits to represent 2^40 bytes
Thank you sir....
Kon kon. Exam se ek din phele pd rha h 😂
Amazing presentation sir
Sir spindle drive motor se attach rahta hai
Ek confusion hai , like last me no. of bits pucha hai question me , pr abhi bhi hmne byte calculate ki hai , to last me answer 43 bit nhi aayega ? , Like 2 raise to power 3 nhi krenge ?
legend watching in 2022😈
Perfectly explained sir🙂👍
Superb explanation. Thank you so much sir.
Sir u r explanation is toooo good .tq soo much ,pls upload all video's of OS.🙏🙏
The best 💯💯
cover all the topics of Disk Architecture
AMAZING EXPLANATION. THANKYOU SO MUCH SIR !
Thank you sir... ❤️❤️❤️
Sir aap bhoat asha badha te ho college ke teacher se bhi badiya thanks sir
😇😇
Thank you Sir👍👍💯🙏
Sir, kya aap apne lectures jaise hi related powerpoint presentations ka link de sakte hai ?
thanks,sir
Sir plZ you also make bca CET class teaching video
I have a doubt regarding the number of bits required to represent the disk size. You have taken 40 bits that represent tera but what about byte? We also have to convert byte into bits so that the final answer will be 43 bits
May be that will be irrelevant like you taught us in paging , while representing in bits we don’t convert byte into bits,because we are not required to do so. This explains the scenario. Thanks
sir can uh plz make one video on semaphores gate question ....i am facing much difficulties in solving them plzzz
Broo at 7:40 how can every track have same number of sectors.. INNER Tracks should have less no.of Sectors and OUTER Tracks should have more no.of Sectors. Because every SECTOR has same amount of data.
Sir can u explain stroage organisation hard disk?
Because of frequently learning from your videos through subtitles now I feel like now Im understanding Hindi Language also.
thank you sir for making this playlist
NICE EXPLAIN SIR THANK YOU VERY MUCH
Sir block aur cluster ke bare me bhi batado reply me
Great !
Thanks for adding subtitles sir i don't understand single Hindi word🙂