Note- For Q.8, In first case (a), the voltage and current would have the same polarity. So, if the current is entering into the positive terminal (as per the question), then the power delivered "by the element" would be negative and Power delivered "to the element" would be positive. In case (b), at 3ms the value of voltage is negative and the value of current is positive. Now, as per the question the current is entering into the positive terminal. But since, the voltage value is negative that's why the power delivered "by the element" would be positive in this case and power delivered "to the element" will be negative. So, In Conclusion, if you just write power delivered as -V*I (Because the current is entering into positive terminal as per the question), then your polarity would be correct.
In question 8(a) it is asked to find power delivered to an element so the answer should be positive As you taught that if power is entering to the positive terminal then it is absorbing power so power absorbed by an element is +VI , power delivered by an element is -VI and power delivered to an element is +VI
Then, all we should care is "sign of voltage and whether is current entering /leaving, -ve terminal or +ve terminal "that all ? No need consider sign of current ?
Note-
For Q.8,
In first case (a), the voltage and current would have the same polarity. So, if the current is entering into the positive terminal (as per the question), then the power delivered "by the element" would be negative and Power delivered "to the element" would be positive.
In case (b), at 3ms the value of voltage is negative and the value of current is positive. Now, as per the question the current is entering into the positive terminal. But since, the voltage value is negative that's why the power delivered "by the element" would be positive in this case and power delivered "to the element" will be negative.
So, In Conclusion, if you just write power delivered as -V*I (Because the current is entering into positive terminal as per the question), then your polarity would be correct.
In question 8(a) it is asked to find power delivered to an element so the answer should be positive
As you taught that if power is entering to the positive terminal then it is absorbing power so power absorbed by an element is +VI , power delivered by an element is -VI and power delivered to an element is +VI
@@HARIOM-2427 Yup, correct
Then, all we should care is "sign of voltage and whether is current entering /leaving, -ve terminal or +ve terminal "that all ? No need consider sign of current ?
best lecture on youtube😊of network theory
GRATEFUL FOR FINDING THIS AMAZING SERIES OF LECTURES ! ANYONE SEARCHING FOR GOOD LEC SHOULD GO FOR IT , WORTH WATCHING♥
does this playlist cover entire syllabus of gate for Ece?
Very thankful for this series!✨
24:02 by that analogy, Vgs of Mosfet means V(source) - V(Gate) but, we never do that in Mosfet analyisis, why ? for easier understanding or what??
very nice explanation, ❤️👏
Any one explain calculation part of question no 3 by taking Area under curve how to solve it
Area of Rectangle+Area of Triangle
2 X Area of triangle+ area of rectangle
thankyou
really awesome
Why for voltage, we are considering that charge is at infinity.
15:13 sir can u explain how to measure area under the curve
Area of rectangle + area of Traingle
Sir Can you please explain it briefly
@@vandanachowdaryarea of triangle 1/2*breadth*height + area of rectangle breadth*height. So 1/2*1*2 + 2*2 + 1/2*1*2 = 6
In Q8) since current is entering into +ve terminal, Pdelivered should be = -VI? Right?
Hi, Please see the pinned comment.
Thanks for marking it out
❤❤❤❤❤
Bdiaa Bhai❤
sir , in 57:23 is the active and passive written wrong?
Written in the video itself
where can I find notes for these lectures?
Thanku bhaiya
Bro Kya full course available hai For getting full knowledge of this Subject
Q8 a
The is 75 mw or 53.48 ?
Cos(60
Sir But there are totally 4 burners in experiment ryt..U calculated energy of the single burner only?
I added up their time. Check out the given time for each burner
sir notes nhi mil rhe teligram me ..kaha milenge notess ye sb lectures ka??
It's there in Telegram already
@@PrepFusion_GATE ok thanks you sir .got it 🙏
Didnt understand the last question solution and concept can you please explain more ?
Sir ye btayiyr kahi khai sirg current i=q/t aur kahi current ko i=dq/dt aur sir kabhi i=∆q/∆t use karte jo plz tall me ye alag formula kb llgaya jaye
Time domain function diya ho toh dq/dt
2 point difference diya ho toh DelQ/DelT
@@PrepFusion_GATE aur I=Q/t kab use karte hai
Q5 mein to Vba 25v hai ya Vab ….?
brother Q9 me 120 minutes kasa aaya burner timing
completed
16:27 how the slope value is zero sir
Function is constant.
I recommend you to start your Preparation From Engineering Mathematics.
Sirr ji eske notes kidhr milega ..
Telegram me to nhi mila ?