@@Vector_Horizonah my bad i meant to find the distance d at around 1:40, the distance between F and H u use sin 30 times 1.5 but how do you know it makes a right triangle because otherwise u can’t do that no?
@thegreentrex6890 It does not form a right-angled triangle. To find the distance between points F and H, observe that the points F, H, and E form a triangle with a 30-degree angle at E. We are also given the distance between points H and E, which is 1.5 m. This means we have two sides and an angle. Let d represent the distance between points F and H. Since we have the hypotenuse (H to E) and the angle (30 degrees), we can use the sine function to find the distance d.
how do you realise that its a right angle with the triangle at 2:01
Are you asking why I use the sine component at 2:20, or are you asking something else? Can you clarify?
@@Vector_Horizonah my bad i meant to find the distance d at around 1:40, the distance between F and H u use sin 30 times 1.5 but how do you know it makes a right triangle because otherwise u can’t do that no?
@thegreentrex6890 It does not form a right-angled triangle. To find the distance between points F and H, observe that the points F, H, and E form a triangle with a 30-degree angle at E. We are also given the distance between points H and E, which is 1.5 m. This means we have two sides and an angle.
Let d represent the distance between points F and H. Since we have the hypotenuse (H to E) and the angle (30 degrees), we can use the sine function to find the distance d.
Good explanation