Integrated Rate Law: First Order Reaction
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- เผยแพร่เมื่อ 19 ก.ย. 2024
- A first order reaction has integrated rate law
[A] = [A]0 e^(-kt)
which is the same as ln [A] = -kt + ln [A]0
Which means a graph of ln [A] vs time will give a line with slope -k and a y-intercept of ln [A]0.
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this man made feel home, taught me something and was super nice during all of it. Teachers can really learn from him
It's stupid how the chem teachers on TH-cam can teach and explain things better than my chem professor at one of Canada's top universities.
+Shaftell lol I know right, I have no idea what my university prof taught me. They care more about the quantity of material that they deliver, not the quality.
+Shaftell do you see how long this video is? 5 minutes is pretty long for something as trivial as integrating (which is btw math not chemistry) an expression. A professor at university cannot explain 1200 pages of literature in detail like this video is, in a given time of his class.
I second that
Welcome to earth
came to think about it, that is the most selfish yet efficient way for universities to teach their undergraduate students, the mediocre will fall behind and the really smart ones will rise to the surface that way it automatically decides who to keep, all this while being lazy. Actually you will eventually need to learn by yourself at higher levels and if you can't figure out this kind of stuff on your own you are probably not meant for academics. When I go to university, I think ill get most of my tuition if the professor zeroes in on one of the class materials and walk me through his or her thought process from the basics to deeper things. WIth that way of thinking in my mind. I will try to do other parts on my own.
You are literally saving me from flunking my chemistry semester examination! Thank You!
bro have you graduated now...its been 5 years
AP Chemistry test tomorrow. YOU have no idea how much you have helped me. Thank you very much!
Whoa now, you have Calculus in your AP Chem class? We don't at all and it's not on the AP test. I'm just looking this up for fun.
cursedswordsman
The Calculus is the derivation of the formula. Don't worry about the derivation, just memorize!
SirPerfectful That's my plan, I'm just wondering how this would have helped you on your AP Chem test.
cursedswordsman The fact that I now know it.
SirPerfectful Omg mine is this coming Monday. Between ChemistNate and Bozeman Science, I've learned the whole AP chem curriculum basically. Bless them both! How was your exam btw?
Well done explaining integrated rate law. Was really easy to follow, helpful, and funny!
who needs angels when you're there
your vibes are so positive about something so boring, you made it so easy to understand. Amazing video !
chemistNATE is SO underrated, his teaching is SO clear and helpful!
THIS VIDEO LITERALLY SAVED MY LIFE AND EXPLAINED THIS BETTER THAN MY CHEM PROFESSOR BLESS YOUR SOUL
content on this channel is fun to watch
I love how you got excited at the ending part
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Thank you so much sir, it really help me with my pharmacokinetic subject
Thx, I love your humor.. I can see you prosper as a teacher....
to be precise: the rate of a reaction is directly proportional to the concentration of a reactant. The k is used merely to equate the two.
Mathew Garcia yeah... Obviously
To equate two proportionals you obviously need a constant
Otherwise how can you?
impressive personality combined with good teaching skills.
Thank you. Very easy to understand. Love the connection to the linear function graph.
My teacher made 'k' the subject and gave the equation like this: k=(1/t)ln([A_°]/[A_t]). Anyways, she also taught us your last equation😊
thank you for existing man
Best video out there. Needed this for my christmas coursework, thanks :)
great video thank you for actually explaining the steps for integration instead of just listing the formula like other videos
Nate! I'm a biochemistry major and I love doing kinetics problems but I'm frustrated that I don't know how to go from a rate law to this y = mx + b form.... What do you suggest? I took calc in high school I'm just rusty as a nail. Thanks Nate!
It might be late but i will answer anyways. I recommend you to read the art of problem solving: introduction to algebra. It helped me a lot to understand the rate law in terms of y=mx + b. It doesn´t tell you the answer immediately but instead forces you to think. But don't worry if it seems hard for you, the book itself helps you by suggesting what steps you could take to solve a problem. The topic of interest (graph and lines) is the number 8 but you had better read it from topic 1 if you want to understand everything better because almost all lessons are intertwined to keep track the incoming knowledge. On the other hand, if you are struggling only with the calculus part, then only I can do is suggest to read any calculus book
@@cesaralejandrojimenezmay4104 4 years too late hahah, love the enthusiasm in your reply
I'm in the way of reading Larry Gonick's cartoon book on chemistry. This vid was helpful. Many thanks.
Ur t looks like plus + got me confused there 4 some time.
also I love the markers u use keep that high
Thanks
I have been searching long time for this integration
Very nicely done, thanks for this!
stop calling natural log lawn...
+brandon Somerville even my math professor calls it that and he's been teaching calculus since the 1980's.... it's not wrong...
it is.
+Kidchipy IN Punjabi language lawn is a very bad term.
Brandon s ln is lawn
Log is log
Also using both are correct
Take a chill pill Einstein!
HAHAHAHAHAHAHA I THOUGHT I WAS WRONG.
Super explanation..
l am from india
I've been trying to figure this calculus out. I understand kinetics and all but not this integrating thing.. I am confused as to what happened to d[A] and what does -d[A]/dt mean and where did it come from? THANKS NATE!
Ok, does the "d" represent delta or change in.. Now im just curious how you got rid of the d[A] that is on the other side of the integrated 1/[A]... I appreciate it.
I didn't get it either
Tyler Obermark d[A] means he's integrating with respect to the concentration of A.
Remember your identities:
∫1/x dx = ln(x)
I love the enthusiasm
Is " ln [A]0 = kt + ln [A] " the same as " ln [A] = -kt + ln [A]0 " ?
Its like a sight for sore eyes, I have the whole idea, but I am seeking how it would be realted to half life, though a plethoraof videos are outthere with (K=1/halflife). Since, most of the research articles employ first order rate to depict how the pollutant concentration over time, how it can be achieved when we have only final and initial concentrations, and change in time, and how to find K and half life?
Is this stop motion or something?
Could you please do a video on Pseudo-First Order reactions?
sure yes?
You made it so easy!!! Thanks a lot
my prof made it ln[a_t]/ln[b_0] = -kt but she didn't teach us that equation :/ either way I still don't get most of my professor's lecture
I like the way you explain with lot's of energy
can somebody help me to integrate rate law for 1.5 order.. my lecturer always find a way to make the thing become complicated
What about if you had a rate equation that was rate=-k[A][B]
Too much Helpful !
This is the video I'm looking for! Thanks man!
sir ur explanation is so nice tq
integration you did was extremely helpful to visualize, thanks!
great explanation :D
do you think you can briefly describe to me what the t and 0 mean on the integral notation?
t=0, ie time for initial rate of reaction and t means time after reaction is completed.
Thus According to the previous comment
It means that you are going from 0 to t
thanks bro that was really helpful!
thanks bro, you solve my problem immediately
Great stuff. Well done.
Great teaching
This an amazing video. All your videos are so helpful!
"You tell me... and you're right! Because you're smart!" I don't tell you anything and I have no idea what you did, but there is one thing I do know... I'm retaking chem II because I don't get this crap at all. My brain shuts off and all I hear is Charlie Brown's teacher.
I HATE when Leibniz derivative notation is treated as a fraction. It isn't! You can't just move about dt as you please.
4hours in class and i didn t get a shit..5:05 min and i do : Thank you soooo much ! Clear explaination Thank God! God bless you my friend!
What does ln mean? You said “lon??” What is that?
Natural log...log base e
Thanks but I had one question which still confuses me. You did the indefinite integral first, but later added showed the definite integral by having an interval. On the left side, you integrated with respect to variable [A], but your interval is in terms of t. Shouldn't it be in terms of [A]? Sry, just learned integrals in calc 1 so it's still pretty new stuff
You can take the definite integral of both sides from 0 to t. And that's what he meant to do. And it's ok if you want to write 0 to t in terms of A on the left hand side, rewriting the limits as A_initial and A_final.
What matters is the time interval. On the right side, the time interval decides what value dt is going to take, whereas on the left side, this interval decides what's going to happen to [A].
tbh, it's easier to explain when in person than when you're online. I agree that he didn't use the notations as strictly as its done in our math classes, which is what left you confused.
You can show this to your chem or math teacher and he'll explain it to you. Idk about your school but we had this part in both math (In our differential eqtns chapter) and chemistry. So yeah.
Wow . You made it easy man !
Wow
THANK YOU SIR SO MUCH !!!!
diz guys on youtube explain more dan my professor
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Convert in log10
My book has it printed wrong 🙄 thank you for your help!!!!😂
First time on this Chennal..
It is really op
amazingggg.... Its really helful in understing this all and Also interesting... thanks for uploading Sir...
beautifully explained thankyouuuuuu
Thank you so much. it was very helpful
"This Marker is CRAP"
xDDDD
TQ so much!
are you saying lawn? :o
Yes, that’s Canada !
WELL EXPLAINED!
Thank you
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nice
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kuch samjh nahi aya
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Mander
Wrong
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