13.1 Introduction to Colligative Properties, the van't Hoff factor, and Molality
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- เผยแพร่เมื่อ 11 ก.ย. 2024
- Struggling with Colligative Properties? Chad provides an introduction to the topic and explains how to calculate molality and identify the van't Hoff factor.
00:45 - Freezing Point Depression
04:21 - Boiling Point Elevation
07:10 - van't Hoff Factor
10:28 - Molality
13:58 - Freezing Point vs Freezing Point Depression
If you want all my study guides, quizzes, and practice exams, check out my premium course at www.chadsprep....
Happy Studying!
thank you Chad. Your expression of chemistry is very charismatic: making the concepts easy to digest. Thank you for your patience and continue to strive for greatness
You're welcome!🙂
Best ever teacher on the entire youtube thanku very much for such a great job
Love the hyperbole! You're welcome and I'm so glad you found this lesson helpful! Happy Holidays!
Thank you so much for your videos! I always watch them after class and you explain things better than my lecture professor.
It's a great day for students with all that is available on the internet. But cut your professor some slack as I get the advantage of being the second source you're exposed to. If you know what your upcoming lecture is going to be about, you might try my video lecture first...you might just find out that your professor is doing a better job than you realized and that you get more out of class. Best!
Studying for my DAT thanks for these awesome explanations. You're an awesome professor!! :) wish I had you in undergrad!
You're very welcome Sarah! Glad you're finding them helpful in your studies. Have you seen my DAT practice exams that are currently available free of charge? courses.chadsprep.com/courses/chads-dat-practice-exams
savior, really simplistic teaching. helped me feel more confident in understanding these concepts.
Awesome Nicole! Be sure to work some problems too...mastery is the best source of confidence!
ultimate best video on colligative properties on youtube. you have my thanks.
You're welcome and Thank You!
this was so in depth yet so specific and totally digestible! fantastic lecture i’m sure my upcoming test grade will leave me thanking you !
Glad it was helpful, Gabi - good luck on your test!
This was the best explanation of colligative props. & van’t Hoff factor. TY!!!!
You're welcome Michalina! Glad you found it helpful!
Amazing teacher!!
Thank you Cindy! 😃 Happy Studying!
Thank you for the beautiful explanation. You just saved my Chemistry grade. {-;}
You're welcome! And love the name!
wow chad don't know how I'd prep without you!!!!
Thanks, Conor - glad you found us!
Hey Chad, you definitely need more subscribers. Not sure, why you have less than 10K subscribers. It shoulda been more than 100K. I am not exaggerating, but I know your teaching qualities, being a teacher myself.
Wow, thanks! I'm working on it. I figure take care of the students and the rest will follow. What do you teach?
@@ChadsPrep I think, you need to make videos more frequently and on the topics of high school. I teach chemistry to high school students in India and teach AP Chem to a few students in US when ever they need my help (online).
Sounds like a great idea. Sounds like something I should begin releasing in the fall to match the school year. Thanks!
One more suggestion for you...if you make videos for JEE students in India, you will have so many subscribers from India. India has more than billion people who have access to internet and anything that attracts them will change everything. Just include IIT-JEE in the title and make a few videos.
Amazingly explained😍#love from India
Thanks for the love Shikha! Know these were also made with much love!
awesome video, used it while writing my lab report and trying to understand the meaning of van't Hoff factor!! Thank you!!
You are welcome, Michelle - glad it helped!
Damn why aren't you famous damn you one of the greatest chemistry teacher....salute sir
Thank you very much.
ur too good at it ideky u havnt got much views
Thank you soo much..
You're welcome, LNT!
Excellent explaination
Thanks Reuel!
You're a wizard. Never change.
Unfortunately, change is the only constant! While I am getting older at least you can't say I have less hair than when I filmed this lesson!😜
everyone says this but your explanation is great
Thanks Sanaa and glad you found it helpful!🙂
ty
yess! thank you so much
You are very welcome!
helpful as always 🙌
Excellent!
Outstanding
Thanks Jed!
Dear Chad, I'm curious about if there is a video for Chapter 12? Is it hidden in a secret place that only the brave heroes/heroines can access? :P
Hey HC! This is just my laziness. I left out a chapter on modern materials (like semi-conductors) not covered in most General Chemistry courses. But as it is covered in some I left a spot for it for when I get around to producing a set of videos for it. :)
Describe the relationship between intermolecular forces and solubility including the use of " like dissolved like " rule.
A solute will be soluble in a solvent when they are 'alike' in terms of polarity. Hydrogen-bonding is kind of like a super strong dipole-dipole force so it often indicates a high degree of polarity. This is why if both the solute and solvent are both capable of hydrogen bonding then they are both probably pretty polar and the solute is likely to dissolve in the solvent.
On the other hand if both the solute and solvent are nonpolar (which also means they only have London dispersion forces) the solute is likely to be soluble in the solvent in this case as well.
Hope this helps!
@@ChadsPrep thank you
hey chad! Im kind of stuck with understanding something. If the salt lowers the freezing point which then also decreases the melting point, how do you get ice to actually melt then? I get that the solute prevents the lattice structure from forming so we'd prevent the liquid from freezing, but I guess I don't get how the ice would actually melt? Thanks!
Hey Devika! So the freezing point and the melting point are the same point (same temperature). At the surface of the ice there will be a small amount of liquid water in equilibrium with the ice present. The salt will first dissolve in this small layer lowering its freezing/melting point. The ice will now be in equilibrium with this new salty water layer with the lower freezing/melting point. The result is that the ice in in direct contact with this salty water layer will now melt also. This process is simply repeated causing the salt to make its way further and further to the center of the ice. Hope this helps!
@@ChadsPrep ahhh thank you! you're the GOAT
Why doesn't the size of the pieces affect the properties ?
Is this in relation to Van't Hoff factor?
An angel
Thanks, Katie!
And now I'm your 21st subscriber! Anymore dental/DAT videos in the works?
@@ChadsPrep Thanks for subscribing! I plan on making a video of all the resources I used while studying, I'll make sure to mention you :)
W O W !!!
Hoping that's a good WOW Geraldine! Best!
@@ChadsPrep It's a wow wow! Impressive 👏👏👏
Sound intellectualism + a Bible verse in the background! Where do I sign up??
👍 👍 👍
He sounds like Neil Patrick Harris
Doogie Howser?!
I thought him someone else 😂😂
Thank you sir time and time again you save my tuckus
Glad the channel is helping you!