For those of you that find this problem easy just wait for the very difficult ones to do in your head then you'll see so many variables, that will make your head spin. It's nice to learn a methodical way to solve challenging problems and of course the satisfaction of knowing the methods. Thanx John
I subscribed to your TH-cam channel for the fun of the personal challenge. I'm in my 70s, and enjoy exercising my math skills. High school algebra is as far as I got. Thanks for being here .
really - 33 divided by 3 =11 therefore 11-1 is the first digit, 11 is the 2nd digit and 11+1 is the 3rd digit. 10+11+12=33. Took no time to figure out.
Our professor ask, “does anyone have any questions about the test tomorrow?” My friend asks, “will there be any word problems on the test?” The professor said, “there won’t be any word problems on the test…but there might be a few story problems.”
That’s too funny, but the question “will there be word problems on the test?” is one which has been around since time in memoriam. And good news is science and engineering courses are filled with more of them so enjoy!
Just want to make sure I understand correctly because my math skills aren't strong: 16:10-16:14 you can somehow combine like terms even if there are brackets separating some of the terms?
@@victorsoto2188 Thanks Victor, it's hard for me because it has been soo long since I have been in high school and now I returning. Not all the basics are fresh in my head and to add it to the course is condensed into 8 weeks so it's quite fast paced. But I am trying. If I had someone to help guide me in the right direction even if it's 15 minutes a week I think it could help. I'm going to do best and hope that's enough to get into university
If the 3 integers are consecutive, then the middle one must be one third of the total -- in this case, 11. Thus, the numbers are 10,11,12. Why bother with anything more involved than that?
I was in second grade when my school got a landline. As a freshman in college calculators were desktop and cost a months take home pay. We had to be able to use slide rules.
SO EASY! n+n+1+n+2 = 33 3n+3=33 3n+3-3 = 33-3 3n =30 3n/3 = 30/3 n = 10 Therefore, the first integers is 10, second is 11, and third is 12. CHECK: 10+11+12 = 33
Let x = the first integer. Then let x+1 = the second integer. Then let x+2 = the third integer. Add the first, second, and third integers X+ (x+1) + (x+2) =33 Combine like terms 3x + (1+2) = 33 3x + 3 = 33 Solve this first degree equation. 3x + 3 = 33 -3 -3 3x = 30 3x/3 = 30/3 X = 10 10 + 1 = 11 10 + 2 = 12 The three consecutive integers are: 10, 11, and 12. 10 + 11+ 12 = 33
Since the sum of any 3 consecutive integers must be divisible by 3, divide the sum by 3 and you will get the middle number of the series. In this case, 33/3 = 11 So, the series is 10, 11, and 12. This problem should take less than 10 seconds to solve.
I'm 67 years old and figured this one out in my head. My gosh, you make it so difficult! 3 consecutive numbers add up to 33. 33 divided by 3 equals 11. That's the middle number. One above and one below , 10 and 12 equals 22. (22 divided by 2 equals 11). 11 plus 11 plus 11 equals 33. Don't need x and y and all that stuff. Why complicate things. It's quite evident you have no common sense.
His objective was to demonstrate how to work it mathematically. He's not interested in simply delivering the answer regardless of procedure. Sometimes, the simple problems are used to teach algebra so that you may use them as models to work more complicated problems. Why do people get so angry at math teachers, to the point of insulting them? There is no need for that. I could throw some problems at you in which the answer may be determined without picking up your pencil. But you'd probably never know that and would need to see it worked out conventionally, step by step. Should I then turn around and accuse you of having no common sense?
Doc, I think you went on a little too long expecting this simple problem, which turned out to be a little confusing, in my opinion. The word THREE in the question means you divide 33/3 = the sum of 11+11+11 which is = 33. Then to solve for CONSECUTIVE: with (11,11,11) subtract 1 from the first integer and add it to the last integer in the sequence of 11's, will be = 10,11,12 = 33. done!
Tabletclassmath, by any chance, do you know anything about asvab arithmetic reasoning? Because I need help knowing this so I can join the US army. If you don't, then I understand. If you do, can you show me?
Integers are the whole numbers and their opposites. If you have ever constructed a number line and labeled it with zero in the center, then 1, 2, 3, 4, ...along the right side and -1, -2, -3, ... along the left side, then every number displayed (that you labeled) would be an integer.
@@robertwatson818 The opposite sign. For example, 1 is and integer as well as its opposite -1. The set of integers may be represented like this: {....-3. -2, -1, 0, 1, 2, 3,...} Of course the dots indicate that integers go on and on indefinitely in both directions. An example that is NOT an integer is 1/2 because it is not a whole number. I hope that helps. By the way, you may be interested in some short-term summer math classes that a friend of mine will be teaching. The classes are taught through Zoom and are open to adults who want to refresh their math skills.
@@cbesthelper404 Thanks! I thought this to be the case. I had words many times with math "teachers" who called numbers "integers". I did not graduate from high school due to my not being able to do the higher forms of math. My parents pushed me into college despite my telling them the math only gets more difficult and Iw would not be able to pass it. I was right. Today this is still the case.
@@robertwatson818 You are here learning, so that is a start toward mastering the subject. Sometimes, you just have to find your own way of looking at math to make sense of it. Keep at it. There will be breakthroughs for you, and you will reach a point when you will wonder how it all seems so easy now. I've seen it happen many times with many students. Getting back to your original question, there are different Number Sets. The set of integers is just one such set. There is also the set of rational numbers that includes things that we refer to as fractions. There are counting numbers as well, which is probably the easiest to remember because it consists of the numbers that we recite whenever we are counting, such as 1, 2, 3, 4, 5, 6, ....... Your teachers were using the term "Integer" to distinguish the kind of numbers that they were using at the exclusion of others. I love teaching math. It's my passion. If you have any other math questions, post them here. I am confident that you can conquer math.
For those of you that find this problem easy just wait for the very difficult ones to do in your head then you'll see so many variables, that will make your head spin. It's nice to learn a methodical way to solve challenging problems and of course the satisfaction of knowing the methods. Thanx John
No, no matter how hard a word problem is, I will be able to solve it.
I subscribed to your TH-cam channel for the fun of the personal challenge. I'm in my 70s, and enjoy exercising my math skills. High school algebra is as far as I got. Thanks for being here .
I am 65 and finding it very difficult to do maths. Watching your videos has really help me a lot. Finally I got this. Thank you.
I'm 68 and I solved this one in my head.One of the first word algebra problems.
69 and I did the same, we were taught the 3 Rs not the crap they teach now!
I will be 69. 10+11+12=33. Took few seconds mentally . I like watching Math videos
really - 33 divided by 3 =11 therefore 11-1 is the first digit, 11 is the 2nd digit and 11+1 is the 3rd digit. 10+11+12=33. Took no time to figure out.
this realy helped eith algebra
Our professor ask, “does anyone have any questions about the test tomorrow?” My friend asks, “will there be any word problems on the test?” The professor said, “there won’t be any word problems on the test…but there might be a few story problems.”
That’s too funny, but the question “will there be word problems on the test?” is one which has been around since time in memoriam. And good news is science and engineering courses are filled with more of them so enjoy!
@@brucesmith9144 I prefer word prawwwms myself!
MR. TabletClass, thank you once again for another exceptional video/lecture on Algebra Number Word Problem.
if you do
3 number add up to 60
does not work
n-1+n+n+1=33
3n=33
n=11
Nos are 10,11,12
Prof mukundsir
Great stuff, especially for the homeschooled!!💎
Just want to make sure I understand correctly because my math skills aren't strong: 16:10-16:14 you can somehow combine like terms even if there are brackets separating some of the terms?
yes, the brackets are for grouping purposes only but can be combined with like terms. good luck on your progress.
@@victorsoto2188 Thanks Victor, it's hard for me because it has been soo long since I have been in high school and now I returning. Not all the basics are fresh in my head and to add it to the course is condensed into 8 weeks so it's quite fast paced. But I am trying. If I had someone to help guide me in the right direction even if it's 15 minutes a week I think it could help. I'm going to do best and hope that's enough to get into university
If the 3 integers are consecutive, then the middle one must be one third of the total -- in this case, 11. Thus, the numbers are 10,11,12. Why bother with anything more involved than that?
I was in second grade when my school got a landline. As a freshman in college calculators were desktop and cost a months take home pay. We had to be able to use slide rules.
Everyone seems to be missing the point of the lesson.
Solved in my head within 3 seconds.
Actually, He should have said, "re-read"! Written is 5X; later is " X=". Let's NOT confuse students. One might think X=5.
I did this in my head in five seconds.
SO EASY!
n+n+1+n+2 = 33
3n+3=33
3n+3-3 = 33-3
3n =30
3n/3 = 30/3
n = 10
Therefore, the first integers is 10, second is 11, and third is 12.
CHECK:
10+11+12 = 33
Was It sum of or product of
Let x = the first integer.
Then let x+1 = the second integer.
Then let x+2 = the third integer.
Add the first, second, and third integers
X+ (x+1) + (x+2) =33
Combine like terms
3x + (1+2) = 33
3x + 3 = 33
Solve this first degree equation.
3x + 3 = 33
-3 -3
3x = 30
3x/3 = 30/3
X = 10
10 + 1 = 11
10 + 2 = 12
The three consecutive integers are: 10, 11, and 12.
10 + 11+ 12 = 33
10, 11, 12. I didn't even need to use Algebra.
Or, you could just divide 33 by 3. That's 11. Subtract one from 11 and that's 10. Add one to 11 and that's 12. 10, 11, 12.
x + x +1 + x + 2 = 33
3x + 3 = 33
3x = 30
x = 10
Therefore 10, 11, 12
Trivial word prawwwm.... mmmmmmok ?
33 / 3 = 11
then i subtract 1 and add 1. so the three integers are 10, 11, 12.
Since the sum of any 3 consecutive integers must be divisible by 3, divide the sum by 3 and you will get the middle number of the series. In this case, 33/3 = 11 So, the series is 10, 11, and 12. This problem should take less than 10 seconds to solve.
Thank God, I saw the equation in seconds.
10, 11, 12 how tough can that be. Divide 33 by 3 add 1 subtract 1.
I'm 67 years old and figured this one out in my head. My gosh, you make it so difficult! 3 consecutive numbers add up to 33. 33 divided by 3 equals 11. That's the middle number. One above and one below , 10 and 12 equals 22. (22 divided by 2 equals 11). 11 plus 11 plus 11 equals 33. Don't need x and y and all that stuff. Why complicate things. It's quite evident you have no common sense.
His objective was to demonstrate how to work it mathematically. He's not interested in simply delivering the answer regardless of procedure. Sometimes, the simple problems are used to teach algebra so that you may use them as models to work more complicated problems.
Why do people get so angry at math teachers, to the point of insulting them? There is no need for that.
I could throw some problems at you in which the answer may be determined without picking up your pencil. But you'd probably never know that and would need to see it worked out conventionally, step by step. Should I then turn around and accuse you of having no common sense?
Doc, I think you went on a little too long expecting this simple problem, which turned out to be a little confusing, in my opinion. The word THREE in the question means you divide 33/3 = the sum of 11+11+11 which is = 33. Then to solve for CONSECUTIVE: with (11,11,11) subtract 1 from the first integer and add it to the last integer in the sequence of 11's, will be = 10,11,12 = 33. done!
69 and solved it in my head instantly but for "show your work enthusiasts"
x + (x+1) + (x+2) = 33
3x + 3 - 3 = 33 - 3
3x =30
×=10
10,11,12
3 consecutive numbers = 33
Therefore the middle number is 33/3 = 11
making the other two numbers 10 and 12
Tabletclassmath, by any chance, do you know anything about asvab arithmetic reasoning? Because I need help knowing this so I can join the US army. If you don't, then I understand. If you do, can you show me?
33 / 3 = 11 with 11 as middle number so 10 + 11 + 12 = 33
That took about 3 seconds
It took me about 2 seconds to get the answer.
10 11 12 easy but if you want me to show my work…. 33/3=11 11-1=10 11+1=12.
The point is, in an algebra class that work would not suffice.
33/3=11, so 10,11,12
What is this "integer" business? You mean number?
Integers are the whole numbers and their opposites. If you have ever constructed a number line and labeled it with zero in the center, then 1, 2, 3, 4, ...along the right side and -1, -2, -3, ... along the left side, then every number displayed (that you labeled) would be an integer.
@@cbesthelper404 What would be their "opposite" ??
@@robertwatson818 The opposite sign. For example, 1 is and integer as well as its opposite -1. The set of integers may be represented like this:
{....-3. -2, -1, 0, 1, 2, 3,...}
Of course the dots indicate that integers go on and on indefinitely in both directions. An example that is NOT an integer is 1/2 because it is not a whole number.
I hope that helps. By the way, you may be interested in some short-term summer math classes that a friend of mine will be teaching. The classes are taught through Zoom and are open to adults who want to refresh their math skills.
@@cbesthelper404 Thanks! I thought this to be the case. I had words many times with math "teachers" who called numbers "integers". I did not graduate from high school due to my not being able to do the higher forms of math. My parents pushed me into college despite my telling them the math only gets more difficult and Iw would not be able to pass it. I was right. Today this is still the case.
@@robertwatson818 You are here learning, so that is a start toward mastering the subject. Sometimes, you just have to find your own way of looking at math to make sense of it. Keep at it. There will be breakthroughs for you, and you will reach a point when you will wonder how it all seems so easy now. I've seen it happen many times with many students.
Getting back to your original question, there are different Number Sets. The set of integers is just one such set. There is also the set of rational numbers that includes things that we refer to as fractions. There are counting numbers as well, which is probably the easiest to remember because it consists of the numbers that we recite whenever we are counting, such as 1, 2, 3, 4, 5, 6, .......
Your teachers were using the term "Integer" to distinguish the kind of numbers that they were using at the exclusion of others.
I love teaching math. It's my passion. If you have any other math questions, post them here. I am confident that you can conquer math.
10, 1, 12
10, 11, 12
@@margaretanncobb-redhead5442 Thank U 4 the correction/ I've done it 2.
@@margaretanncobb-redhead5442 10 ,1, & 12 add up to 23 and are not consecutive.
No marks for you. Draw a sad face and go to the back of the class!
@@PreservationEnthusiast I know, I made the correction below.
Look for the correction below
10, 11, 12......
10, 11, 12
10,11,12