Всегда начинаешь с точки, где количество путей нечетное. Если в фигуре таких точек больше двух, ее нельзя обвести одной линией без повторения пути или прерывания его.
@@tapalagealexandru6805 ну все правильно, я лишь озвучил алгоритм решения. Контретно в этой задаче решение есть и это понятно уже потому, что точек с нечетным количеством путей 2. Не обязательно ее даже решать при этом.
Specifically, there must be either zero or two nodes with odd number of edges! If there’s zero, you can start anywhere and win; it’s usually very easy once you know this trick and you can solve it almost automatically
U start from a point with 3 lines connected to it and end at the other point with 3 lines connected( Vertex with odd degree and end with the second vertex with odd degree)
If there's two spots where an odd number of lines meet, you start at one and end at the other. If there's more than two, it's impossible. For shapes with only even-lined intersections, you have a way in and a way out (or two ways in and two out, etc.) So it doesn't matter where you start or where you end. When you have the three-line intersections, every line coming in allows for a line going back out so that deals with two of them but then for the third line, you get stuck unless you start at one of the odd nodes and that, in effect turns it into an even-numbered node. (thus leaving two more that are in and out) and end at the other. (if you already did two, that leaves a single line for the finish. This also expands out to intersections with four or six or eight and also the odd-lines extends to five or seven or nine, etc. But because odd-nodes must always have pairs removed till you're left with one, then the last line would end at that odd-node and never escape back out. Thus "start at one odd-number node" turns it in to an even node and do all other lines before ending at the other, And, curiously enough, there'll always bw an even number of odd nodes and if there;s 4, 6, etc of there, you can never reach/finish more than two of them
@@josealexanderdeleonfernand7613As long as there's no odd-numbered nodes at all, you can start at any node and you'll end at the same node. The actual path you do it in isn't that important. So if you took the simplest shape, a triangle, you can start at any corner so there's three solutions there. And you can go either clockwise or counter-clockwise so that doubles the solutions to 6. And it's obvious that you have to end at the node you started at. If you had a square and ran a single diagonal, then you'd have to start at one end of the diagonal and end at the other and I'm too lazy right now to figure out exactly how many solutions. I'm sure there's a formula for it somewhere. But if you added a second diagonal, then there's no solution because you have more than two nodes with odd # of lines, And, btw, the number of odd nodes can be limitless but it's always an even # of them. So the above shapes have 0, 2 and 4 odd nodes respectively. The number of even nodes can be any where from 3 and up (or if you allow curved lines, you could do two nodes with a shape like an American football.
Надо начинать с точки, в которой нечётное количество линий и заканчивать в этой точке или в такой же. В которой нечётное количество линий. И количество этих точек должно быть чётным.
Ada yang bilang, diatas langit ada langit, di atas orang pintar ada yang lebih pintar . Tapi bagi saya, siapa pun yang tidak bisa menjawab permainan ini dengan benar . Maka dia adalah manusia terbodoh yang pernah ada didunia ini 😅🤭
А на третьем участникн звучит смех моего маленького сынишки... Я его записывала на кассетный магнитофон для свадебного конкурса. Какой то идиот взял у меня эту кассету , и потом,через много лет, когда появился иртернет - выложил его в сеть... Никогда ни с каким его не спутаю... Помню лействия этой записи до мелочей... Сейчас сыну 45. Хакеры, вы талантлиаые люди.... Как можно убрать это смех из сети? ....
The trick to puzzles like these are to start at an intersection with an odd number of paths. If the drawing is possible, there will be up to 2 odd intersections.
I bet if I was in that video I would stop and think and see what would happen if I do this until I figure it out! then I would technically get it first try! 😂
Другой вариант решения: начинать надо с нижней точки ромба. Идём направо, очертим ромб, вернемся к исходной точке. Дальше вниз, верх, еще верх и вниз к верхнему углу ромба.
Leonhard Euler solved this... at least a variant of it. Look up Bridges of Königsberg if you're curious. This one is solvable since it has exactly two vertices with an odd number of points. How? You must start at one of them, and you will end up at the other, no matter what.
Always start where there’s an odd number of edges - unless there isn’t any such part, in which case you can start anywhere. If there’s not 0 or 2 odd-edge spots, it’s impossible and you’re being trolled
This is such a convenience, On Thursday me and some of my classmates are going to sing the song In the background And I just so happen to be scrolling on TH-cam shorts and finding this
Bonjour, commencer au sommet de la base inférieur du losange, puis suivre le périmètre du triangle bas à gauche, continuer le périmètre du losange vers la droite et remonter vers la gauche puis finir par les deux côtés du triangle du haut. Mer
And this is why you should learn some basic graph theory just in case you get asked to draw a shape in 1 line or else you'll get hit with a hammer and laughed at
Unfortunately, in Japan, this kind of advanced quiz and punishment game, air hammer hitting, is a source of complaints, so it will not be broadcast. I'm jealous of my brother
![[TH] 2024 PMSL SEA W2D1 | Summer | ถ้าไม่พร้อมลุย ได้ไปคุยกับรากมะม่วง](http://i.ytimg.com/vi/XlkKtVvBxac/mqdefault.jpg)
Solved into in just one try
😂😂😂😂Rggvfgugjhnhvkgh
❤❤❤😂😂😂🎉🎉Yfhgugh
Me too
❤❤❤
😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂2024❤
This is literally just like one of those "99% of people cannot do this" ads
Many as this should be get a report
And it wofked.. You commented
It became very simple after seeing the last person do it 😅😉
❤❤❤❤
*AYO WHAT THE FUCKKKK*
Мужчина в бардовой кофте был близок к победе😊
I figured it out after the first person did it.
Song name? 🙏
X2
小城夏天 xiao cheng xia tian
It is so much 🤣🤣😂
Всегда начинаешь с точки, где количество путей нечетное. Если в фигуре таких точек больше двух, ее нельзя обвести одной линией без повторения пути или прерывания его.
А я решил задачу
@@tapalagealexandru6805 ну все правильно, я лишь озвучил алгоритм решения. Контретно в этой задаче решение есть и это понятно уже потому, что точек с нечетным количеством путей 2. Не обязательно ее даже решать при этом.
Simple Euler advice: Always start in a node with odd number of edges.
also, if there are more than 2 nodes with odd number of edges, it can't be solved.
可以一筆畫，先畫兩個外边小三角的各2條邊线，后畫4邊菱形
Эта самая простая задача.
Graph theory
Specifically, there must be either zero or two nodes with odd number of edges! If there’s zero, you can start anywhere and win; it’s usually very easy once you know this trick and you can solve it almost automatically
O ALLAH, BLESS mouhammd and the family for mouhammd ❤
He had clearly gained more ground, looking at previous players even if it worked out it wouldn't be anything strange
I didn’t need to wait for the answer I did it right away. Most of these are fairly easy.
😢
ЛГУН 😷
Yeah, I did it straight away but not the way he did it.... There is another way too
@@easygarden777 most of these puzzles have more than one way to solve it
If you got it first try
👇. TYSM for the likes ❤️
Bisa
Should start at the first inner point from below
@@rioaben363 ?
@@imsmiley23 Or first inner point above.
@@frankt... i stand corrected 🤣🤣🤣
Seven Bridges of Königsberg!
U start from a point with 3 lines connected to it and end at the other point with 3 lines connected( Vertex with odd degree and end with the second vertex with odd degree)
If there's two spots where an odd number of lines meet, you start at one and end at the other. If there's more than two, it's impossible.
For shapes with only even-lined intersections, you have a way in and a way out (or two ways in and two out, etc.) So it doesn't matter where you start or where you end.
When you have the three-line intersections, every line coming in allows for a line going back out so that deals with two of them but then for the third line, you get stuck unless you start at one of the odd nodes and that, in effect turns it into an even-numbered node. (thus leaving two more that are in and out) and end at the other. (if you already did two, that leaves a single line for the finish. This also expands out to intersections with four or six or eight and also the odd-lines extends to five or seven or nine, etc.
But because odd-nodes must always have pairs removed till you're left with one, then the last line would end at that odd-node and never escape back out. Thus "start at one odd-number node" turns it in to an even node and do all other lines before ending at the other,
And, curiously enough, there'll always bw an even number of odd nodes and if there;s 4, 6, etc of there, you can never reach/finish more than two of them
Además de la solución mostrada encontré otra forma de hacerlo.
Ghki🎉😊
@@josealexanderdeleonfernand7613As long as there's no odd-numbered nodes at all, you can start at any node and you'll end at the same node. The actual path you do it in isn't that important. So if you took the simplest shape, a triangle, you can start at any corner so there's three solutions there. And you can go either clockwise or counter-clockwise so that doubles the solutions to 6. And it's obvious that you have to end at the node you started at.
If you had a square and ran a single diagonal, then you'd have to start at one end of the diagonal and end at the other and I'm too lazy right now to figure out exactly how many solutions. I'm sure there's a formula for it somewhere.
But if you added a second diagonal, then there's no solution because you have more than two nodes with odd # of lines,
And, btw, the number of odd nodes can be limitless but it's always an even # of them. So the above shapes have 0, 2 and 4 odd nodes respectively. The number of even nodes can be any where from 3 and up (or if you allow curved lines, you could do two nodes with a shape like an American football.
🎉🎉😮😅😢😢😅😊
ĐJjeuuhrl
Надо начинать с точки, в которой нечётное количество линий и заканчивать в этой точке или в такой же. В которой нечётное количество линий. И количество этих точек должно быть чётным.
Точно. Это фигура даже проще чем пресловутый "конверт".👍
Very simple and easy start from topup
Drawing that rectangle from center would be a easy step
❤❤❤❤❤❤
If you already know the right drawing before the end gather here 👇👇👇
I puss it to check the right drawing and I got it 💖💯💯
😂😂😂
sa ibaba ng palikpik mo umpisahan tas derecho tas balik pataas then baba
Here
Simple
Ada yang bilang, diatas langit ada langit, di atas orang pintar ada yang lebih pintar .
Tapi bagi saya, siapa pun yang tidak bisa menjawab permainan ini dengan benar .
Maka dia adalah manusia terbodoh yang pernah ada didunia ini 😅🤭
한번에 그리기는 무조건 홀수 꼭지점에서 시작해야 합니다
The trick is to start at a point where three lines connect.
ง่ายๆ
1 จุดกลางเปียกปูนล่างลากลงยอดปีกล่าง
2 จากยอดปีกล่างลากไปยอดแหลมซ้ายมือ
3 แหลมยอดซ้ายมือลากไปแหลมปีกบน
4 จากปีกบนลากลงเปียกปูนกลางบน ลากเข้าซ้ายปลายศร
5 จากปลายศรเฉียงขวาไปเปียกปูนล่าง
6 ลากเฉียงขึ้นขวา แล้วลากเฉียงซ้าย...จบ
Solved easy.
Начинаем с одного крыла , переходим на второе , все это время не задевая сам ромб , после крыльев уже идет ромб
Можно и с ромба, тоже получится
@@user-jd3og6ji9z
Да, тут много вариантов, в отличии от пресловутого "конверта".
@@user-jd3og6ji9z Ну, или так! (с)
😂😂😂😂😂😅😅😅😅😅😅
А на третьем участникн звучит смех моего маленького сынишки... Я его записывала на кассетный магнитофон для свадебного конкурса. Какой то идиот взял у меня эту кассету , и потом,через много лет, когда появился иртернет - выложил его в сеть...
Никогда ни с каким его не спутаю... Помню лействия этой записи до мелочей... Сейчас сыну 45.
Хакеры, вы талантлиаые люди.... Как можно убрать это смех из сети? ....
This is going to sound weird but I found it right on my first thought.
홀숫점에서 시작하면 됩니다
홀숫점이란 점에 연결된 선이 홀수개인 점을 말하죠
세로선 두개보이죠 저기서, 안쪽점 에서 시작해야 합니다.
Isko to ham Bhai 1 minut mein solve kar sakte hain
Ah the good old "99% of people are paid to act stupid" ads
Muy bueno,además de divertirnos aprendemos,felicitaciones al que que lo pensó👍👍👍😊😊los chinos,son unos genios!!🎉🎉🎉
Нижний треугольник ромба , затем выход на оба крыла и завершение ромба внутри
1st center one draw chesi ,next one side draw chesi second side kuda draw cheyali.🙋🙋👍👍
😂😂😂
Who just fast forward towards d end cos we knw dats wen d WINNER will emerge? Hands up!!✋😅😅
ஓம் நமசிவாய🇨🇳🌎
That dance at the end was just hilarious.🤣🤣🤣🤣
Способа решения минимум 4, пробуйте!
The trick to puzzles like these are to start at an intersection with an odd number of paths. If the drawing is possible, there will be up to 2 odd intersections.
I bet if I was in that video I would stop and think and see what would happen if I do this until I figure it out! then I would technically get it first try! 😂
Wow Awesome 👍 Amazing 👍
cringe
Solved in less than one second
진짜틀리는게 더힘들어
@@user-yv7xi3mm8j
Exactly
@@user-yv7xi3mm8j
Exactly… kid stuff
Yes there is an answer to this one
These puzzles are trivial. You have to start at a vertex connected to an odd number of lines.
Gampang banget 😊😊😊😅😅
Amazing, next more ❤😊
😅
th-cam.com/users/shortssR06T2hIKXw?si=DWDr9GhSP2RS670r
@SherazSunpal-ok3kwo ko
Okk was not in😊
Start at a junction with 3 lines and end at then other. Super simple
It's transversable if you start at an odd vertex. Network theory. Very simple.
Good, great interesting activity🎉🎉🎉🎉
La clave es empiezas ir las.lineas de adentro y luego te pasas a la de afuera o de viceversa
Другой вариант решения: начинать надо с нижней точки ромба. Идём направо, очертим ромб, вернемся к исходной точке. Дальше вниз, верх, еще верх и вниз к верхнему углу ромба.
чуть умнее самого тупого обьясняет тупым как надо))))))))))))))))))))))))))))))))))))))
Leonhard Euler solved this... at least a variant of it.
Look up Bridges of Königsberg if you're curious.
This one is solvable since it has exactly two vertices with an odd number of points. How? You must start at one of them, and you will end up at the other, no matter what.
👍👇easy
I have 3 ways to solve this puzzle
Start at the top or bottom of the diamond. Follow the perimeter, starting towards the right,
The winner had enough time to rehearse
It's easy I know another method
Me too
😂😮😂😂😂😂
Start @ top of left half of diamond; left, right, down, left, right, down, right, left; done.
Always start where there’s an odd number of edges - unless there isn’t any such part, in which case you can start anywhere. If there’s not 0 or 2 odd-edge spots, it’s impossible and you’re being trolled
😂😂😂😂😅😅😅 ❤❤❤
He be doin minecraft emotes when he won
This is such a convenience, On Thursday me and some of my classmates are going to sing the song In the background And I just so happen to be scrolling on TH-cam shorts and finding this
Excellent
From Timor-Leste 🇹🇱🇹🇱👍👍
Or, just look at where the chalk line begins-
these sound effects make my brain rot
Сначало центральный ромб обводишь и потом с верхней точки ромба закрываешь остальное😊
L❤❤❤❤❤❤❤❤
Я еще одно решение нашел
Bonjour, commencer au sommet de la base inférieur du losange, puis suivre le périmètre du triangle bas à gauche, continuer le périmètre du losange vers la droite et remonter vers la gauche puis finir par les deux côtés du triangle du haut. Mer
Simple trick ❤❤❤
very easy to solve
So much for the results 😸😸
Easy peasy, got it o first try. Great funny video, thanks!
Easy. Start at the bottom part of the little line up top. Go up left, right, down over and back around.
Simple
I solved easily
❤❤
Solved it too in one second and my answer is different than the video 😉
А ведь все было не так сложно)))
done 💯 ❤
😂😂😂😂😂😂😂🎉❤
dog
Start at a junction with an odd number of lines and do anything
There are a few ways to solve it. Pretty easily
Amazing😊
gringe u bot
U can also start with the square atan angle near to top move toward left then😉
Qoyil ijodilaga omat ❤❤
Ну, это не сложно) над этой головоломкой "голову ломать" не пришлось 😁
I solved
Nice of you
Too easy under 3 sec
it's fun do watch your video keep up
the first girl literally started 1/3 into the right anser
Wow nice great ❤❤❤❤
Bro took the hard way
i feel like all intelligence has decreased since the 1970's
Draw the main middle shape making sure you begin at either the bottom or top point then just do the ouside side shape lines. Not much of a puzzle
I did it 😊
Me who got it a different way: 👁👄👁 *re checks answer 50 times*
螢幕下方的垂直線先往下畫 然後左上右上再往下 最後順時針把菱形畫完就OK了,方法還蠻多種的
I love your video's ❤
This is ridiculously simple
There are several paths to get it done correctly
فنانين ما شاء الله ❤❤❤❤
Solved into in just one try ❤❤❤❤❤❤so hard ❤❤❤❤❤❤❤❤❤
как минимум 4 способа правильно решить эту задачку.
Super
And this is why you should learn some basic graph theory just in case you get asked to draw a shape in 1 line or else you'll get hit with a hammer and laughed at
Solved in a single first try..with different pattern..
Unfortunately, in Japan, this kind of advanced quiz and punishment game, air hammer hitting, is a source of complaints, so it will not be broadcast.
I'm jealous of my brother