Oxford University Admission Interview Tricks | Find x=? ✍️🖋️📘💙

[@ManojkantSamal]

^= read as to the power
*=read as square root
As per question
5^(sin^24x)- 5^(cos^24x)=4
5^(sin^24x)-5^(1-sin^24x)=4
5^sin^24x - {5/(5^sin^24x)}=4
Let 5^sin^24x=R
So,
R-(5/R)=4
(R^2-5)/R=4
R^2-5=4R
R^2-4R-5=0
R^2-5R+R-5=0
R(R-5)+1(R-5)=0
(R-5)(R+1)=0
R-5=0, or R+1=0
R=5 or R=(-1)
If R=5
5^(sin^24x)=5
5^(sin^24x)=5^1
Sin^24x=1
Sin4x=*1=1
Sin4x=sin90
4x=90
X=90/4=22.5 degree